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Imo Answer will be :E

Correct mei id im woring

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Answer is C, I think.

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Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.



Only two cases:

1. None of the students is over 70. In that case the average of ANY two students would be assured to be below 70.
2. ONLY ONE of the students is over 70. For example, the average of 71 and 35 is clearly below 70, BUT the average of 71 and 71 is 71 what is not allowed.



S1.


Case 2. Only 1.


SUFF.



S2.

Two students on the right of 68 can be equal to 68 or greater. It can be either case.


INSUFF.




AC: A



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Statement 1 is sufficient.
Even if one of the student is more than 70, all the other students must weight lesser than 70. (as the average weight of any two students is 70)
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Question says mean of any 2 students less than 70. So sum of weights of any 2 students is less than 70. Statement 1 says 1 student is 70 and more. So if we compare other students with this student their weight should be less than 70. So sufficient. Statement 2 says median is 68. So if arrange is ascending order there will be 2 students before and 2 students after 68. Of 2 students who has weight beyond 68 both of them cannot be greater than 70. But we cannot say that either is one is more than 70 or both is between 68 and 70. So not sufficient. So answer is A

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Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.

Half the problem is solved by the main statement..

Quote:
the average (arithmetic mean) weight of any two students in the group is less than 70 kg
If there are two numbers equal to or above 70, their average will surely be MORE than or equal to 70..
so MAX number above 70 can be ONLY one ..
second possibility is NONE ..


Our statement should be able to give us some info to eliminate any one of the two..

lets see the statements..
(1) One of the students weighs more than 70 kg.
so it gives us ONE as answer
suff
(2) The median weight of all 5 students is 68 kg.
nothing much..
all 68 ... ans 0
66,66,68,70,70.... ans 2
insuff

A
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Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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chetan2u
Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.

Half the problem is solved by the main statement..

Quote:
the average (arithmetic mean) weight of any two students in the group is less than 70 kg
If there are two numbers equal to or above 70, their average will surely be MORE than or equal to 70..
so MAX number above 70 can be ONLY one ..
second possibility is NONE ..


Our statement should be able to give us some info to eliminate any one of the two..

lets see the statements..
(1) One of the students weighs more than 70 kg.
so it gives us ONE as answer
suff
(2) The median weight of all 5 students is 68 kg.
nothing much..
all 68 ... ans 0
66,66,68,70,70.... ans 2
insuff

A


Hi,

Sorry to bring up a post from a year ago, but I am working through this New Year set and couldn't help but notice something that seems out of place.

Chetan, you gave as an example for Statement 2:

66, 66, 68, 70, 70 --> this would not fit with the restrictions of the problem. If we take ANY TWO students, their average weight should be LESS THAN 70, not less or equal to. If we take the last 2 students, (70 + 70) / 2 = 70 which is not less than 70. Hence, the second to last student should be less than 70 (either 69 or 68).

Statement 2 is insufficient because of the following 2 cases:
1) 68, 68, 68, 68, 68 whereby the answer to the target question is 0 (0 students over 70kg).
2) 66, 66, 68, 68, 71 whereby the answer is 1 student is over 70kg.
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Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.

St 1 : Even in the following case

<70, <70, <70, 70, >70

The average of the highest two is greater than 70, which violates the condition given

So , the only arrangement possible is

<70, <70, <70, <70, >70

Only one student weighs 70 or more

Sufficient

St 2 : The arrangement could be

68,68,68,68,68 or 68,68,68,68,70

Zero students or one student

Not Sufficient

Choice A
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Bunuel

GMAT Club's Fresh Challenge Problem.



In a certain class of 5 students, the average (arithmetic mean) weight of any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?

(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.

There are only 2 possibilities for students weighing more than 70 kgs = 1 or 0 since for 2 or greater average of 2 students will be greater than 70 kgs.

(1) One of the students weighs more than 70 kg.
This gives us the answer = 1
SUFFICIENT

(2) The median weight of all 5 students is 68 kg.
There may be students equal to 1 or 0 having weight greater than 70 kgs
NOT SUFFICIENT

IMO A
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