chetan2u
Bunuel
GMAT Club's Fresh Challenge Problem.
In a certain class of 5 students, the average (arithmetic mean) weight of
any two students in the group is less than 70 kg. How many students in the class weigh 70 kg or more?
(1) One of the students weighs more than 70 kg.
(2) The median weight of all 5 students is 68 kg.
Half the problem is solved by the main statement..
Quote:
the average (arithmetic mean) weight of any two students in the group is less than 70 kg
If there are two numbers equal to or above 70, their average will surely be MORE than or equal to 70..
so MAX number above 70 can be ONLY one ..
second possibility is NONE ..Our statement should be able to give us some info to eliminate any one of the two..
lets see the statements..
(1) One of the students weighs more than 70 kg.
so it gives us ONE as answersuff
(2) The median weight of all 5 students is 68 kg.
nothing much..
all 68 ... ans 0
66,66,68,70,70.... ans 2
insuff
A
Hi,
Sorry to bring up a post from a year ago, but I am working through this New Year set and couldn't help but notice something that seems out of place.
Chetan, you gave as an example for Statement 2:
66, 66, 68, 70, 70 --> this would not fit with the restrictions of the problem. If we take ANY TWO students, their average weight should be LESS THAN 70, not less or equal to. If we take the last 2 students, (70 + 70) / 2 = 70 which is not less than 70. Hence, the second to last student should be less than 70 (either 69 or 68).
Statement 2 is insufficient because of the following 2 cases:
1) 68, 68, 68, 68, 68 whereby the answer to the target question is 0 (0 students over 70kg).
2) 66, 66, 68, 68, 71 whereby the answer is 1 student is over 70kg.