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gmatophobia
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The answer for this question is clearly wrong because if the new weight is 50 then final avg remains 50 and new weight wont divert the SD.
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If every student weighs 50 kg, then adding another student at 50 kg wouldn't change the standard deviation, therefore the standard deviation would not decrease. If all student weights are not equal, then adding a new student who's weight is equal to the mean would decrease the standard deviation. Hence insufficient.

ahddhah
The answer for this question is clearly wrong because if the new weight is 50 then final avg remains 50 and new weight wont divert the SD.
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let me correct myself, I forgot that the std deviation would have an n in formula so even if the numerator remains the same -which it will remain same even if the numbers are different -the number divided by would become n+1 and this would decrease the std deviation however i would like to highlight sum of square of (mean- individual number) would remain the same.Also when all the weights are equal then the standard deviation becomes 0 so its not effected. I hope I was able to explain but I did not see very clear answers to this question before.
UVA2024
If every student weighs 50 kg, then adding another student at 50 kg wouldn't change the standard deviation, therefore the standard deviation would not decrease. If all student weights are not equal, then adding a new student who's weight is equal to the mean would decrease the standard deviation. Hence insufficient.

ahddhah
The answer for this question is clearly wrong because if the new weight is 50 then final avg remains 50 and new weight wont divert the SD.
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