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14 Feb 2022, 09:45
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Difficulty:
5%
(low)
Question Stats:
89% (02:17) correct
11%
(02:21)
wrong
based on 93
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In a certain state, schools pay 2% tax on food and 8% on stationary. A school placed a combined order of $500 on food and stationary, and paid $19 on tax on the order. How much of that money was spent on food?
(A) $200
(B) $250
(C) $300
(D) $350
(E) $400
(A) $200
(B) $250
(C) $300
(D) $350
(E) $400
Jagmeister
Joined: 24 Feb 2021
Last visit: 19 Aug 2023
Posts: 169
Given Kudos: 137
Location: India
Concentration: Technology, Entrepreneurship
Schools: Fuqua '25 (WA$$) HBS '25 (D) Stanford '25 (D) Sloan '25 (D) Haas '25 (WL) Darden '25 (A) Ross '25 (WL) Marshall '25 (WA$$$) McCombs '25 (D) Tuck '25 (WL)
GMAT 1: 720 Q50 V37 (Online)
GMAT 2: 750 Q50 V42 (Online)
GPA: 4
Schools: Fuqua '25 (WA$$) HBS '25 (D) Stanford '25 (D) Sloan '25 (D) Haas '25 (WL) Darden '25 (A) Ross '25 (WL) Marshall '25 (WA$$$) McCombs '25 (D) Tuck '25 (WL)
GMAT 2: 750 Q50 V42 (Online)
Posts: 169
14 Feb 2022, 11:29
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My Answer: (D) $350
My Approach:
Total amount spent: $500
let amount spent on Food be = x
Then amount spent on stationary = 500 -x
Total tax = tax on food + tax on stationary = 19
2% of x + 8% of (500-x) = 19
\(\\
\frac{2x}{100} +\frac{8(500-x)}{100} = 19\\
2x + 4000 - 8x = 1900\\
6x = 2100\\
x = 350\)
Ans (D) $350
My Approach:
Total amount spent: $500
let amount spent on Food be = x
Then amount spent on stationary = 500 -x
Total tax = tax on food + tax on stationary = 19
2% of x + 8% of (500-x) = 19
\(\\
\frac{2x}{100} +\frac{8(500-x)}{100} = 19\\
2x + 4000 - 8x = 1900\\
6x = 2100\\
x = 350\)
Ans (D) $350
kungfury42
Joined: 07 Jan 2022
Last visit: 31 May 2023
Posts: 580
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Given Kudos: 725
Schools: NUS '25 (A)
GMAT 1: 740 Q51 V38
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14 Feb 2022, 14:04
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Bunuel
In a certain state, schools pay 2% tax on food and 8% on stationary. A school placed a combined order of $500 on food and stationary, and paid $19 on tax on the order. How much of that money was spent on food?
(A) $200
(B) $250
(C) $300
(D) $350
(E) $400
(A) $200
(B) $250
(C) $300
(D) $350
(E) $400
Let \(a\) be placed on Food and \(b\) be placed on Stationary
Therefore, we have \(a+b=500\) (1)
Tax on Food = \(0.02a\)
Tax on Stationary = \(0.08b\)
Therefore, we also have \(0.02a+0.08b=19\) (2)
Solving (1) and (2)
\(a=350\) and \(b=150\)
Hence, $350 was spent on Food, our answer is option D.
