Bunuel wrote:

In a city council election, Candidate X received 1/3 more votes than Candidate Y, and Candidate Y received 1/4 fewer votes than Candidate Z. If the average (arithmetic mean) of votes per candidate was 22,000, how many votes did Candidate X receive?

A. 18,000

B. 20,000

C. 21,000

D. 22,000

E. 24,000

Y = \(\frac{3}{4}\)Z => Z = \(\frac{4}{3}\)Y

X = \(\frac{4}{3}\)Y

X = Z = \(\frac{4}{3}\)Y

\(\frac{X + Y + Z}{3}\) = 22,000

X + Y + Z = 66,000

\(\frac{4}{3}\)Y + Y + \(\frac{4}{3}\)Y = 66,000

\(\frac{11}{3}\)Y = 66,000

Y = 66,000 * \(\frac{3}{11}\) = 18,000

X = \(\frac{4}{3}\) * 18,000 = 24,000

Answer E

_________________

In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"