Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1410:00 AM PDT
-11:59 PM PDT
GMAT Preparation Online - A limited time sale use code: EXPERTSGLOBAL10- Jul 15
08:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations! 
Jul 1609:30 AM EDT
-11:30 AM EDT
Is INSEAD your dream b-school and you're looking for solid prep and application strategies to get there? Check out Barkavi’s end-to-end journey to know how she did! Get insights into the INSEAD admissions process, know what Adcoms look at, and more!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Jul 1911:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
19 Feb 2021, 07:45
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
46% (02:54) correct
54%
(02:21)
wrong
based on 68
sessions
History
Date
Time
Result
Not Attempted Yet
In a league of 8 teams, each team played every other team 10 times. The number of wins of the 8 teams formed an arithmetic sequence. What is the least possible number of games won by the champion?
A. 41
B. 42
C. 43
D. 44
E. 45
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
A. 41
B. 42
C. 43
D. 44
E. 45
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
19 Feb 2021, 08:08
Kudos
Bookmarks
Bunuel
In a league of 8 teams, each team played every other team 10 times. The number of wins of the 8 teams formed an arithmetic sequence. What is the least possible number of games won by the champion?
A. 41
B. 42
C. 43
D. 44
E. 45
A. 41
B. 42
C. 43
D. 44
E. 45
If every team plays exactly 1 match with every other team exactly once then Total Matches \(= \frac{8*7}{2} = 28\)
i.e Total matches if every team plays 10 matches with every other team = 28*10 = 280
Total Wins = 280
For them to be in arithmetic progression of 8 terms, Mean = median \(= 280/8 = 35\)
For mean/median of 8 terms in Arithmetic progression to be 35, the terms can NOT be consecutive so they must for an Arithmetic progression of even terms with median 35
i.e. Numbers of wins will be {28, 30, 32, 34, 36, 38, 40, 42}
Answer: Option B
General Discussion
08 Jan 2025, 14:54
Kudos
Bookmarks
Bunuel
In a league of 8 teams, each team played every other team 10 times. The number of wins of the 8 teams formed an arithmetic sequence. What is the least possible number of games won by the champion?
A. 41
B. 42
C. 43
D. 44
E. 45
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
Total matches if every team plays other team once = 8C2 = 8*7/2 = 28A. 41
B. 42
C. 43
D. 44
E. 45
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
So if every team plays other team 10 times, then no of matches = 280
Now, no. of wins needs to be in arithmetic sequence and we need to find least possible largest number in this sequence, which means given a sum, we need to maximize the smallest number in the sequence.
\(S = \frac{n}{2}*(2a + (n-1)*d)\)
\(280 = \frac{8}{2}*(2a + 7d)\)
\(70 = 2a + 7d\)
\(a = \frac{70 - 7d}{2}\)
We need to maximize a, so we need to minimize d, so we will start with d = 1 and see when we get an integer value of a.
d = 1, a = 63/2 (Not possible)
d = 2, a = 28
So last term will be => a + 7d => 28 + 14 => 42
IMO: B
