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# In a school election, there were two candidates for class president.

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Math Expert
Joined: 02 Sep 2009
Posts: 59709
In a school election, there were two candidates for class president.  [#permalink]

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20 Nov 2019, 01:41
00:00

Difficulty:

25% (medium)

Question Stats:

89% (01:52) correct 11% (02:24) wrong based on 18 sessions

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In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000

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In a school election, there were two candidates for class president.  [#permalink]

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Updated on: 21 Nov 2019, 02:01
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000

.4x= .6x-16000
x=80,000

Originally posted by Archit3110 on 20 Nov 2019, 01:58.
Last edited by Archit3110 on 21 Nov 2019, 02:01, edited 1 time in total.
Intern
Joined: 26 Jun 2017
Posts: 18
Re: In a school election, there were two candidates for class president.  [#permalink]

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20 Nov 2019, 05:51
1
I have done this in a different way. But got a wrong answer

Candidate who won got 60% of the votes and the candidate who lost got 40% of the votes.
The difference in the percentage is 20% and the 2nd candidate lost by 16000 votes.

let us assume the total numbers of votes polled as x

so,

20 % of x = 16000

x =$$\frac{16000 * 100}{20}$$

x = 80,000

Can you please tell where i went wrong
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GMAT 1: 620 Q47 V28
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Re: In a school election, there were two candidates for class president.  [#permalink]

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20 Nov 2019, 08:04
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000

Let the total number of votes = x
Assuming voter participation = 100%, Let the two students be A & B, and A gets 40% votes

Now, it is given B's votes are 16000 higher than A's vote count

i.e., 60%(x) = 16000 + 40%(x)
=> 0.6x = 0.4x + 16000

=> 0.2x = 16000 or 2x = 160,000 ==> x = 80,000

I'm not sure where my calculations are incorrect.
Intern
Joined: 12 Jan 2019
Posts: 1
Re: In a school election, there were two candidates for class president.  [#permalink]

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20 Nov 2019, 09:55
I have exactly the same doubt as fellows above.

16000 is the difference between 2 candidates and one got 40% of the vote the other got 60%, so 20% is 16000 votes so 100% is 80000 votes.

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Intern
Joined: 28 Apr 2019
Posts: 39
Re: In a school election, there were two candidates for class president.  [#permalink]

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21 Nov 2019, 01:47
Total x
Difference between winner and loser
0.6x-0.4x = 16000

x = 80000

Can't find the answer in the options. Am I missing something?

Posted from my mobile device
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Joined: 16 Feb 2015
Posts: 170
Location: United States
Concentration: Finance, Operations
Re: In a school election, there were two candidates for class president.  [#permalink]

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21 Nov 2019, 01:55
1
Shorub IHS navaneethmmb RajKomanapalli Archit3110

I have raised this already with Bunuel with a personnel message at the time he just posted this question. Till now he has not replied.

See the attached file.

hope he will edit this question soon

Please give kudos, if you find my explanation good enough
Attachments

File comment: See this

bunuel.PNG [ 53.2 KiB | Viewed 71 times ]

Math Expert
Joined: 02 Sep 2009
Posts: 59709
Re: In a school election, there were two candidates for class president.  [#permalink]

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21 Nov 2019, 02:09
Archit3110 wrote:
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000

.4x= .6x-16000
x=80,000

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Re: In a school election, there were two candidates for class president.   [#permalink] 21 Nov 2019, 02:09
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