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In a school election, there were two candidates for class president.

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In a school election, there were two candidates for class president.  [#permalink]

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New post 20 Nov 2019, 01:41
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Difficulty:

  25% (medium)

Question Stats:

89% (01:52) correct 11% (02:24) wrong based on 18 sessions

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In a school election, there were two candidates for class president.  [#permalink]

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New post Updated on: 21 Nov 2019, 02:01
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000


total votes = x
.4x= .6x-16000
x=80,000
Bunuel please review answer choices..

Originally posted by Archit3110 on 20 Nov 2019, 01:58.
Last edited by Archit3110 on 21 Nov 2019, 02:01, edited 1 time in total.
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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 20 Nov 2019, 05:51
1
I have done this in a different way. But got a wrong answer

Candidate who won got 60% of the votes and the candidate who lost got 40% of the votes.
The difference in the percentage is 20% and the 2nd candidate lost by 16000 votes.

let us assume the total numbers of votes polled as x

so,

20 % of x = 16000

x =\( \frac{16000 * 100}{20}\)

x = 80,000

Can you please tell where i went wrong
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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 20 Nov 2019, 08:04
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000



Let the total number of votes = x
Assuming voter participation = 100%, Let the two students be A & B, and A gets 40% votes

Now, it is given B's votes are 16000 higher than A's vote count

i.e., 60%(x) = 16000 + 40%(x)
=> 0.6x = 0.4x + 16000

=> 0.2x = 16000 or 2x = 160,000 ==> x = 80,000

I'm not sure where my calculations are incorrect.
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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 20 Nov 2019, 09:55
I have exactly the same doubt as fellows above.

16000 is the difference between 2 candidates and one got 40% of the vote the other got 60%, so 20% is 16000 votes so 100% is 80000 votes.

Please please explain what part of the questions are we missing.

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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 21 Nov 2019, 01:47
Total x
Difference between winner and loser
0.6x-0.4x = 16000

x = 80000

Can't find the answer in the options. Am I missing something?

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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 21 Nov 2019, 01:55
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Shorub IHS navaneethmmb RajKomanapalli Archit3110

I have raised this already with Bunuel with a personnel message at the time he just posted this question. Till now he has not replied.

See the attached file.

hope he will edit this question soon

:please Please give kudos, if you find my explanation good enough :please
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Re: In a school election, there were two candidates for class president.  [#permalink]

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New post 21 Nov 2019, 02:09
Archit3110 wrote:
Bunuel wrote:
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.

A 24000
B 28000
C 30000
D 35000
E 40000


total votes = x
.4x= .6x-16000
x=80,000
Bunuel please review answer choices..


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Re: In a school election, there were two candidates for class president.   [#permalink] 21 Nov 2019, 02:09
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