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20 Nov 2019, 01:41
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Difficulty:
35%
(medium)
Question Stats:
89% (01:52) correct
11%
(02:24)
wrong
based on 18
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In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.
A 24000
B 28000
C 30000
D 35000
E 40000
A 24000
B 28000
C 30000
D 35000
E 40000
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Updated on: 21 Nov 2019, 02:01
Originally posted by Archit3110 on 20 Nov 2019, 01:58.
Last edited by Archit3110 on 21 Nov 2019, 02:01, edited 1 time in total.
Last edited by Archit3110 on 21 Nov 2019, 02:01, edited 1 time in total.
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Bunuel
In a school election, there were two candidates for class president. The candidate who got 40% of the votes polled was defeated by 16000 votes. Calculate the total number of votes.
A 24000
B 28000
C 30000
D 35000
E 40000
A 24000
B 28000
C 30000
D 35000
E 40000
total votes = x
.4x= .6x-16000
x=80,000
Bunuel please review answer choices..
20 Nov 2019, 05:51
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I have done this in a different way. But got a wrong answer
Candidate who won got 60% of the votes and the candidate who lost got 40% of the votes.
The difference in the percentage is 20% and the 2nd candidate lost by 16000 votes.
let us assume the total numbers of votes polled as x
so,
20 % of x = 16000
x =\( \frac{16000 * 100}{20}\)
x = 80,000
Can you please tell where i went wrong
Candidate who won got 60% of the votes and the candidate who lost got 40% of the votes.
The difference in the percentage is 20% and the 2nd candidate lost by 16000 votes.
let us assume the total numbers of votes polled as x
so,
20 % of x = 16000
x =\( \frac{16000 * 100}{20}\)
x = 80,000
Can you please tell where i went wrong
Please give kudos, if you find my explanation good enough 
