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09 Apr 2020, 03:58
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C
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Difficulty:
35%
(medium)
Question Stats:
73% (02:27) correct
27%
(02:41)
wrong
based on 288
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In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. What is the largest possible value of the fourth digit?
A. 5
B. 6
C. 7
D. 8
E. 9
Are You Up For the Challenge: 700 Level Questions
A. 5
B. 6
C. 7
D. 8
E. 9
Are You Up For the Challenge: 700 Level Questions
Let the six digit number is abcdef
f =a+b+c
e =a+b
a = c
b =2a
d=e+f
Now
f =2a+b
So
f =2a+ 2a =4a
e= a + 2a =3a
Now
d = 4a +3a =7a
As d is a single digit number so only value of a possible is 1 and value of d is 7
Option C is the answer
Posted from my mobile device
f =a+b+c
e =a+b
a = c
b =2a
d=e+f
Now
f =2a+b
So
f =2a+ 2a =4a
e= a + 2a =3a
Now
d = 4a +3a =7a
As d is a single digit number so only value of a possible is 1 and value of d is 7
Option C is the answer
Posted from my mobile device
General Discussion
Archit3110
Major Poster
09 Apr 2020, 04:56
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given digits in order of 1st to 6th = abcdef
we know
f=a+b+c
e=a+b
c=a
b=2a
we can re write
e=3a and f=4a
d= 7a
max possible digit value of d ie 4th digit is 7
OPTION C
we know
f=a+b+c
e=a+b
c=a
b=2a
we can re write
e=3a and f=4a
d= 7a
max possible digit value of d ie 4th digit is 7
OPTION C
Bunuel
