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Exp SExp NSTotal
Act S= 1-n -0.4+0.4n = 0.6(1-n)0.8n0.68
Act NS0.4(1-n)=1-0.8n = 0.2n=1-0.68 = 0.32
Total1-nn1

0.6(1-n) + 0.8n = 0.68
0.6 - 0.6n + 0.8n = 0.68
0.2n = 0.08
20n = 8
n = .4

Of the days when it did not snow, what percent of the days it was supposed to snow?
= 0.4(1-0.4)/0.32
=4*6/32
= 75%

Bunuel
In City X, it snowed on 68 percent of the days. However, 80 percent of the days when it was not supposed to snow, it snowed and 40 percent of the days when it was supposed to snow, it did not snow. Of the days when it did not snow, what percent of the days it was supposed to snow?

(A) 22%
(B) 32%
(C) 60%
(D) 75%
(E) 80%


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It snowed on 68 days, and did not snow on 32 days. The grid is wrong.
GMATinsight
Let's solve this step by step using a grid.


- Let the total number of days be 100 for simplicity.
- Given:
- It was supposed to snow on 68 days.
- It was not supposed to snow on 32 days.
- 40% of the days when it was supposed to snow, it did not snow.
- 80% of the days when it was not supposed to snow, it snowed.

Step 2: Construct a Probability Grid
Weather ConditionSupposed to SnowNot Supposed to SnowTotal
Snowed68 × 0.6 = 40.832 × 0.8 = 25.6 66.4
Did Not Snow68 × 0.4 = 27.2 32 × 0.2 = 6.4 33.6
Total6832100

(27.2 / 33.6) × 100 = 80%

Answer: Option E
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lets consider total no of days supposed to snow and not snow be (N+S) =100
which means, actual snowed days =68
which means actual no snow = 32

now we have actual snow day = 80% of days not suppose to snow(N) + 60% of days expected to snow(S)

which means 68=0.8*N+0.6*S
or 68= 0.8*(100-s)+0.6S
this implies s=60( no of days expected to snow)

which means D is correct answer
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lets make a matrix for this first-
supposed to snow (ss), not supposed to snow (nss), snow (s), did not snow (ns).
SS NSS. T
S. 0.6X. 0.8Y 68
NS 0.4X. 0.2Y. 32
T. X. Y. 100
we will make equations-
1 0.6x + 0.8Y = 68= 3x+4y=340
2 0.4x + 0.2y= 32= 2x + y= 160

solve for x we get, x=60
so, ans will be 0.4*60= 24 = 24/32= 75%
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