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03 Mar 2021, 06:45
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E
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Difficulty:
55%
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Question Stats:
53% (01:14) correct
47%
(02:14)
wrong
based on 89
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In how many ways can 4 people be accommodated in 4 rooms if each room can accommodate from 0 to 4 people inclusive?
A. 24
B. 48
C. 96
D. 192
E. 256
A. 24
B. 48
C. 96
D. 192
E. 256
03 Mar 2021, 07:31
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The first person can be accommodated in any of the 4 rooms, so total possible ways for 1st person =4
Similarly , for 2nd,3rd and 4th person - 4 ways each.
So total number of ways = 4*4*4*4=256 ways
IMO E
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Similarly , for 2nd,3rd and 4th person - 4 ways each.
So total number of ways = 4*4*4*4=256 ways
IMO E
Posted from my mobile device
20 Mar 2021, 14:51
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Bunuel
In how many ways can 4 people be accommodated in 4 rooms if each room can accommodate from 0 to 4 people inclusive?
A. 24
B. 48
C. 96
D. 192
E. 256
Solution:A. 24
B. 48
C. 96
D. 192
E. 256
The first person has 4 choices for a room. The same thing is true for the second, third, and fourth person. Thus, the number of ways to accommodate the 4 people is 4 x 4 x 4 x 4 = 256.
Answer: E
