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In the addition shown above, A, B, C, and D represent [#permalink]
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15 Oct 2013, 08:17
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ABC + BCB CDD In the addition shown above, A, B, C, and D represent the nonzero digits of three 3digit numbers. What is the largest possible value of the product of A and B ? A. 8 B. 10 C. 12 D. 14 E. 18
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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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saintforlife wrote: ABC +BCB CDD
In the addition shown above, A, B, C, and D represent the nonzero digits of three 3digit numbers. What is the largest possible value of the product of A and B ?
A. 8 B. 10 C. 12 D. 14 E. 18 I'm happy to help with this. First, look at the one's column. C + B produces a one's unit of D, and we don't know whether anything carries to the ten's place. But now, look at the ten's place  B + C again produces a digit of D  that tells us definitively that nothing carried, and that B + C = D. B & C have a single digit number as a sum. Now, C = A + B, because again, in the hundreds column, nothing carries here. Notice that, since C = A + B and D = B + C, B must be smaller than both B and C. We want to make the product of A & B large, so we want to make those individual digits large. Well, if we make B large, then that makes C large, and then B + C would quickly become more than a onedigit sum, which is not allowed. Think about it this way. Let's just assume D = 9, the maximum value. D = 9 = B + C = B + (A + B) = A + 2B We want to pick A & B such that A + 2B = 9 and A*B is a maximum. It makes sense that B would be smaller. Try A = 7, B = 1. Then A + 2B = 9 and A*B = 7 Try A = 5, B = 2. Then A + 2B = 9 and A*B = 10 Try A = 3, B = 3. Then A + 2B = 9 and A*B = 9 Try A = 1, B = 4. Then A + 2B = 9 and A*B = 4 Indeed, as B gets bigger, the product gets less. This seems to imply that the biggest possible product is 10. This corresponds to A = 5, B = 2, C = 7, and D = 9, and the original addition problem becomes 527 +272 799 Thus, the maximum product is 10, and answer = (B). Does all this make sense? Mike
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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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23 Oct 2013, 16:44
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How do we do all that in less than 2 mins, is my only question Posted from my mobile device



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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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23 Oct 2013, 16:54
saintforlife wrote: How do we do all that in less than 2 mins, is my only question Dear Saint For Life, Problems such as this are quite outofthebox. To some extent, the GMAT intends us to handle many of the other questions in 90 secs or less, so that we have a bit of a timecushion when we run into one of these oddball questions. Having said that, the more familiar you are with number properties, the faster it will go. In this problem, it took me quite some time to write out everything in verbal form, but I saw things relatively quickly. As you practice seeing patterns, you will see them more quickly, even if they are hard to explain to someone else. You may find this post helpful: http://magoosh.com/gmat/2013/howtodo ... thfaster/Mike
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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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Re: In the addition shown above, A, B, C, and D represent the [#permalink]
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... got E as an answer. However, it took me 6 minutes, since I plugged in the answer options. Is there any faster way, or am I just too slow in backsolving? TirthankarP wrote: In the addition shown above, A, B, C, and D represent the nonzero digits of three 3digit numbers. What is the largest possible value of the product of A and B ? A) 8 B) 10 C) 12 D) 14 E) 18
My explanation: According to the question stem C+B=D and D<10, since the second addition (2nd column) is C+B=D again (if there were a carry, the second column's result would not be D again), and A+B=C Now I break up the answer options: A) A*B=8, so A and B > 2 and 4 or 1 and 8. A+B=2+4=6=C, C+B=6+2=8=D, which is smaller than 10, thus the answer is not "out", but there could be a larger possible value of A*B B) A*B=10, so A and B > 2 and 5. A+B=2+5=7=C, C+B=7+2=9=D, which is smaller than 10, thus the is also possible. Let's look for the next options. For CE: C) A*B=12, so A and B > 6 and or 4 and 3. D) A*B=14, so A and > 7 and 2. E) A*B=18, so A and B > 9 and 2 or 3 and 6. Do the same process with those numbers and you will find that all will yield a sum of C+B>10, thus the constraint of D<10 is not satisfied. The answer options are not possible. Because 10>8 answer option B) is the largest possible.



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Re: In the addition shown above, A, B, C, and D represent the [#permalink]
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27 Oct 2013, 01:04
Chiranjeevee wrote: TirthankarP wrote: Attachment: Addition.png In the addition shown above, A, B, C, and D represent the nonzero digits of three 3digit numbers. What is the largest possible value of the product of A and B ? A) 8 B) 10 C) 12 D) 14 E) 18 This topic has already been discussed. Please search before posting. Here is the link: intheadditionshownaboveabcanddrepresent161656.htmlI do a thorough search before posting any new question. But this time I couldn't find this link Thanks for sharing the link Forum moderator may delete this thread
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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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saintforlife wrote: How do we do all that in less than 2 mins, is my only question :)
Posted from my mobile device This problem can be solved much faster if you start with the options. As Mike has wonderfully explained, none of the digits will have a carry over. Option E is \(18 = 9 * 2\)(no other case is possible). Now\(9+2>=10\). Therefore, it will have a carry over digit 1. So reject this option.Option D is \(14 = 7 * 2\)(no other case is possible). Since \(C=A+B\), therefore \(C= 9\). Since \(C=9\) and \(B\) is a non zero digit, \(C+B>=10\). Therefore, it will have a carry over digit 1. So reject this option.Option C is 12. This will have 2 cases \(Case 1> 12 = 4 * 3\) Here \(C= 4+3=7\). Now \(7+4>=10\) and [\(7+3>=10\). Therefore, both cases will have a carry over digit 1. So reject this option.(OR) \(Case 2> 6 * 2\). Here \(C= 6+2=8\). Now \(8+2>=10\) and \(8+6>=10\). Therefore, both cases will have a carry over digit 1. So reject this option.Option B is \(10 = 5 * 2\). If you follow the same set of steps you'll notice that there will not be any carry over digit for the case \(C=7, A=5, B=2\). So right answer! Hope it was helpful.



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In the addition shown above, A, B, C, and D represent [#permalink]
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01 Jul 2015, 08:02
HKHR wrote: saintforlife wrote: How do we do all that in less than 2 mins, is my only question :)
Posted from my mobile device This problem can be solved much faster if you start with the options. As Mike has wonderfully explained, none of the digits will have a carry over. Option E is \(18 = 9 * 2\)(no other case is possible). Now\(9+2>=10\). Therefore, it will have a carry over digit 1. So reject this option.Option D is \(14 = 7 * 2\)(no other case is possible). Since \(C=A+B\), therefore \(C= 9\). Since \(C=9\) and \(B\) is a non zero digit, \(C+B>=10\). Therefore, it will have a carry over digit 1. So reject this option.Option C is 12. This will have 2 cases \(Case 1> 12 = 4 * 3\) Here \(C= 4+3=7\). Now \(7+4>=10\) and [\(7+3>=10\). Therefore, both cases will have a carry over digit 1. So reject this option.(OR) \(Case 2> 6 * 2\). Here \(C= 6+2=8\). Now \(8+2>=10\) and \(8+6>=10\). Therefore, both cases will have a carry over digit 1. So reject this option.Option B is \(10 = 5 * 2\). If you follow the same set of steps you'll notice that there will not be any carry over digit for the case \(C=7, A=5, B=2\). So right answer! Hope it was helpful. Wonderful explanation. Just thought to add some more from my side. As we see only B satisfies all the necessary requirement(not to carry over any digits). In option A, taking A=4 and B=2 also satisfies the condition as it is something like 426 +262  688 But since we need maximum value well go for option B
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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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30 Nov 2017, 19:03
Dear Mike, I was wondering why are we maximising D since it no where mentioned to do so. We have to maximise A*B right so if we choose C=1 and B=5 and A=4 i think we staisfy all conditions and our product of A*B (5*4) comes to be 20. Dont know where i am going wrong. Kindly help



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Re: In the addition shown above, A, B, C, and D represent [#permalink]
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01 Dec 2017, 14:54
Sarthak.bhatt wrote: Dear Mike, I was wondering why are we maximising D since it no where mentioned to do so. We have to maximise A*B right so if we choose C=1 and B=5 and A=4 i think we staisfy all conditions and our product of A*B (5*4) comes to be 20. Dont know where i am going wrong. Kindly help Dear Sarthak.bhatt, I'm happy to respond. With all due respect, my friend, you are not interpreting the question correctly. There is absolutely no multiplication happening in this question. Here's the prompt again: ABC +BCB CDD
In the addition shown above, A, B, C, and D represent the nonzero digits of three 3digit numbers. What is the largest possible value of the product of A and B ?Thus, for example if C = 1, B = 5, and A = 4, then ABC would not be the product of those three numbers but instead the single threedigit number 451. With those numbers, the problem would be 451 +515966 These choices satisfy the equation. The problem is completely different from the way you were conceptualizing it, so the strategy is completely different from what it would be in the problem you had in mind. Does this make sense? Mike
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