GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 21 Jan 2019, 10:03

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• ### GMAT Club Tests are Free & Open for Martin Luther King Jr.'s Birthday!

January 21, 2019

January 21, 2019

10:00 PM PST

11:00 PM PST

Mark your calendars - All GMAT Club Tests are free and open January 21st for celebrate Martin Luther King Jr.'s Birthday.
• ### The winners of the GMAT game show

January 22, 2019

January 22, 2019

10:00 PM PST

11:00 PM PST

In case you didn’t notice, we recently held the 1st ever GMAT game show and it was awesome! See who won a full GMAT course, and register to the next one.

# In the below addition A, B, C, D, E, F, and G represent the

Author Message
TAGS:

### Hide Tags

Intern
Status: Yes, I can and I will. 700+FTW
Joined: 30 Sep 2013
Posts: 20
Location: India
Concentration: Finance, Strategy
GMAT Date: 02-05-2014
GPA: 3.7
WE: Other (Retail)
In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

Updated on: 29 Dec 2013, 03:21
1
14
00:00

Difficulty:

35% (medium)

Question Stats:

77% (02:37) correct 23% (02:48) wrong based on 509 sessions

### HideShow timer Statistics

In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals
Attachment:

findginsum_figure.png [ 833 Bytes | Viewed 24777 times ]

A. 2
B. 3
C. 4
D. 5
E. 6

How to tackle such questions? Do we have more question like this?

_________________

It takes time before all the things work together.

Originally posted by ROckHIsT on 29 Dec 2013, 03:09.
Last edited by Bunuel on 29 Dec 2013, 03:21, edited 1 time in total.
Renamed the topic and edited the question.
SVP
Joined: 06 Sep 2013
Posts: 1705
Concentration: Finance
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

Updated on: 15 May 2014, 12:36
6
1
OK, this is what I did

First we know that E must be 1.
Then we know that 0 is to be in either F and G, since they are all different numbers. Since it does not appear in one of the answer choices then F must be zero. Now, for F to be zero the sum of the two digits A and C must add to 10. Therefore we have 6 and 4. Then B and D will be 3 and 2 , or 2 and 3 giving a sum of G=5

Therefore B is equal to 5

Cheers!
J

Originally posted by jlgdr on 22 Mar 2014, 12:26.
Last edited by jlgdr on 15 May 2014, 12:36, edited 1 time in total.
##### General Discussion
Math Expert
Joined: 02 Sep 2009
Posts: 52343
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

29 Dec 2013, 03:25
rgyanani wrote:
In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals
Attachment:
findginsum_figure.png

A. 2
B. 3
C. 4
D. 5
E. 6

How to tackle such questions? Do we have more question like this?

Similar questions to practice:
tough-tricky-set-of-problems-85211.html#p638336

Hope it helps
_________________
Intern
Joined: 23 Mar 2014
Posts: 1
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

26 Mar 2014, 05:29
I started with F has to be 0 because if not it would result in a scenario where two of the numbers are the same. So A+C must be greater than or equal to 10. The only combination of this is 4+6. This means that A+C=10. Now you have A=4, C=6, and F=0. If A and C are 4 and 6 then E must be 1. You're left with 2,3, and 5. G is the sum of B and D, therefore it must be 5.
Director
Joined: 25 Apr 2012
Posts: 683
Location: India
GPA: 3.21
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

27 Mar 2014, 00:33
ROckHIsT wrote:
In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals
Attachment:
findginsum_figure.png

A. 2
B. 3
C. 4
D. 5
E. 6

How to tackle such questions? Do we have more question like this?

Sol: Here we are adding 2 nos and get a 3 digit number
When you look at the given nos we see that E has to be 1 only

Now let's do back calculation and see where end up

Consider G= 2

then we can have possible values of B&D (1,1 or0,2 or 2,0) But then each digit can have only 1 value So ignore G
Consider G= 3 then we have B&D (1,2 or 2,1 or 3,0) Now 1,2 and 2,1 can be ruled out cause we said E has to be 1 then we have a case 3,0 but then A=3 and B=0 then G=3 which is not possible

Consider G=4 then we have B&D (2,2 or 1,3 or 3,1 or 4,0) Consider 4,0 again if A=4 then B=0 and G=4 which is not possible as each Alphabet represent only single digit

Consider G=5 then we have possible values of B&D (2,3 or 5,0 or 4,1 or1,4) Only case is 2,3 Keep G=5 and the only possible nos
62+43= 105
We can stop here but just to check
Consider G=6 then we have (3,3 or 4,2 or 1,5 or 6,0) Now 1,5 and 6,0 can be ruled out. Consider 4,2

X4+Y2= 1A6 Which is impossible because we will need bigger nos let's say 7 8 and 9 as possible values of X and Y but these values are restricted from Q stem.

So ans has to be D
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Intern
Joined: 24 Mar 2014
Posts: 4
Location: India
Concentration: General Management, Technology
GMAT Date: 07-18-2014
GPA: 3.53
WE: Information Technology (Computer Software)
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

10 May 2014, 12:44
2
If we start analyzing from E & F it will far more easier to get to the answer. My 3 step approach is below,-

Step-1

First E cannot be 0 thus A+C = 10/11 only then E will have 1 and F will have 0 or 1.
Therefore A & C needs to be either 6 + 4 or 5 + 6.

Step-2

If A & C is 5 & 6 then E=1 & F=1 but given that each variable has a different value, thus A & C will be 6 & 4.
A=6 B
+ C=4 D
----------------------------
1 0 G

Step-3

Now we have left with B, D & G and have 2, 3 & 5 in hand.
If we put B = 2 & D = 5 then G = 7 but 7 is not in our list. Thus this combination is invalid.
If we put B = 3 & D = 5 then G = 8 but 8 is not in our list. Thus this combination is invalid.

Therefore B will be 3 & D will be 2 and G will be 5.

A=6 B=3
+ C=4 D=2
----------------------------
E=1 F=0 G=5
Manager
Joined: 08 Nov 2014
Posts: 83
Location: India
GPA: 3
WE: Engineering (Manufacturing)
In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

22 Dec 2014, 10:07
1
1
What I did was actually I dont know what it is called , please tell me if any shorter approach is available

A+C can be 10(6+4) or 11(6+5), but if A+C=11 then one number will be left unassigned due to repetition of 1
So, A+C=10 (6+4)
Now , numbers left are 3,5,2 (0,1,4,6 already used)
3+2=5
_________________

"Arise, Awake and Stop not till the goal is reached"

Manager
Joined: 14 Oct 2014
Posts: 66
Location: United States
GMAT 1: 500 Q36 V23
In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

22 Dec 2014, 18:13
1
EFG is a three-digit number, hence E will be equal to 1 having in mind that it cannot be any other number because addition of two two-digit numbers never yield more than 100. So, A+C must be equal 10 (note that numbers cannot be used more than once, thus 11 would not work).

In order to get get G, for B+D we must use numbers that are left: 2,3, and 5. The only possibility is 2+3=5. So 62+43=105.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8803
Location: Pune, India
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

22 Dec 2014, 20:55
1
1
ROckHIsT wrote:
In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals
Attachment:
findginsum_figure.png

A. 2
B. 3
C. 4
D. 5
E. 6

How to tackle such questions? Do we have more question like this?

A little bit of hit and trial, a little bit of logic...

E can only be 1: No two 2 digit numbers can give us a sum of 200 or more. The sum must be in the 100 - 199 range only.
The largest digits are 5 and 6 which add to give 11. With a carryover, the sum can be 12 to give a maximum value of 2 to F. But no two of the rest of the numbers (0, 2, 3, 4) can be added to give us a carryover. So F cannot be 2 and it cannot be 1 because E is 1. So F must be 0.
A and C can be 6 and 4 to give a sum of 10 leaving us with 2, 3, and 5 - perfect. B and D must be 2 and 3 and G must be 5.

_________________

Karishma
Veritas Prep GMAT Instructor

Director
Joined: 23 Jan 2013
Posts: 560
Schools: Cambridge'16
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

22 Dec 2014, 23:13
1
we have

----AB
----CD
--EFG

1) A+C=10 to get E, it cannot be 11 because we get E=F or 12 because A=C. So, E=1, F=0

2) To get F=0 we have only one pair 4+6, so A=4, C=6

3) So, we have 0,1,4,6. Only 2,3,5 rest, so only possible G is 5

D
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1823
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

22 Dec 2014, 23:37
2
Refer diagram below:

Attachment:

findginsum_figure.png [ 4.64 KiB | Viewed 22784 times ]

With the given set of numbers & $$E \neq{0}$$, the value of E can be maximum "1"

For E = 1, A & C should add up to give "0" and "carry 1"

With all the above numbers "occupied", 2 & 3 remain to give 5

These are the 4 combinations possible

_________________

Kindly press "+1 Kudos" to appreciate

Manager
Joined: 27 Jul 2017
Posts: 50
Re: In the below addition A, B, C, D, E, F, and G represent the  [#permalink]

### Show Tags

19 Mar 2018, 08:03
ROckHIsT wrote:
In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals
Attachment:
findginsum_figure.png

A. 2
B. 3
C. 4
D. 5
E. 6

How to tackle such questions? Do we have more question like this?

I approached as follows:
- From the fact presented in the question, E has to be 1 as no 2-digit # sums to 200 or more.
- Next, let's make G to have the maximum value, G cannot be 6 because no remaining digits sums to give a value of 6. So G should be 5 accordingly B and D can be 3 and 2
- Next, I have numbers remaining 0, 4 and 6. I know A+C should give me a 2-digit number then only E will have the value 1. Therefore the only way to have it is F=0 and A and C can have a value of 4 and 6.

This gives the value of G=5. The answer is (D).
_________________

Ujjwal
Sharing is Gaining!

Re: In the below addition A, B, C, D, E, F, and G represent the &nbs [#permalink] 19 Mar 2018, 08:03
Display posts from previous: Sort by