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In the coordinate plane, region J is defined by all the points (x,y)
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06 Jun 2017, 10:46
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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06 Jun 2017, 11:00
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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06 Jun 2017, 12:17
Bunuel wrote: In the coordinate plane, region J is defined by all the points (x,y) for which 4y−6x<32. Is point (a,b) located within region J?
(1) b/2 = a + 2 (2) 12b=18a+60 My answer =B Please refer to the attachment for the explanation
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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09 Jun 2017, 00:04
Leo8 If you extend the line b=2a+4, it will cross the line 4y6x=32. Thus Option A is not sufficient.



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In the coordinate plane, region J is defined by all the points (x,y)
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09 Jun 2017, 02:43
(1) b/2 = a + 2 Since the point (a,b) can take sufficient values as per this equation. Lets test 2 points and see if it satisfies the inequality 4y−6x<32? If b=6,a=1, and we substitute these values in the expression, it will return a TRUE value. But, if b=20,a=8, substituting these values will return a FALSE value for the expression(4x6y<32) Hence, insufficient. (2) 12b=18a+60 This expression can be simplified as 2b = 3a + 10 Multiplied by 2 and taking the a to the left hand side, we will get 4b  6a = 20 This is of the form 4y  6x < 32 We know that 20 is always lesser than 32. Hence, sufficient(Option B) Oops, modified the solution. Thanks for pointing out the error!
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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09 Jun 2017, 02:50
pushpitkc wrote: (1) b/2 = a + 2 Since the point (a,b) can take sufficient values as per this equation. Lets test 2 points and see if it satisfies the inequality 4y−6x<32? If b=6,a=1, and we substitute these values in the expression, it will return a TRUE value. But, if b=20,a=8, substituting these values will return a FALSE value for the expression(4x6y<32) Hence, insufficient.
(2) 12b=18a+60 This expression can be simplified as 2b = 3a + 5 Multiplied by 2 and taking the a to the left hand side, we will get 4b  6a = 10 This is of the form 4y  6x < 32 We know that 10 is always lesser than 32. Hence, sufficient(Option B) It should be 2b=3a+10 .... neverthless the answer should be B.
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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09 Jun 2017, 05:09
i opt for B In the same line of reasoning



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Re: In the coordinate plane, region J is defined by all the points (x,y)
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09 Jun 2017, 11:07
Imo B Statement can have values that can be outside of the region But statement 2 is limited and will have values within the region as it equals 10 which less than 16 Sent from my ONE E1003 using GMAT Club Forum mobile app
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Re: In the coordinate plane, region J is defined by all the points (x,y)
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17 Jun 2017, 09:04
Bunuel wrote: In the coordinate plane, region J is defined by all the points (x,y) for which 4y−6x<32. Is point (a,b) located within region J?
(1) b/2 = a + 2 (2) 12b=18a+60 We don't necessarily have to diagram this problem so much as apply algebra Statement 1 b/2 = a +2 b= 2a +4 44 = 2(20) + 4; 44(2)  20(3) = 28 > 16 yet   2 = 2(1) + 4; 2(2)  (1)(3) = 7 < 16 Insuff Statement 2 Can be algebraically simplified to 2b3a = 10 Suff Thus "B"



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Re: In the coordinate plane, region J is defined by all the points (x,y)
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14 Aug 2018, 10:48
Bunuel wrote: In the coordinate plane, region J is defined by all the points (x,y) for which 4y−6x<32. Is point (a,b) located within region J?
(1) b/2 = a + 2 (2) 12b=18a+60 Here is my approach. Line f: 4y  6x = 32 Statment 1: b/2 = a+2 > 4b = 8a + 16 > 4b  8a = 16 > Point (a,b) lies on line g: 4y  8x = 16 From the equations of Line f and Line g, we can conclude that these 2 lines intersect. > Point (a,b) can be inside or outside region J > Insufficient. Statement 2: 12b=18a+60 > 4b = 6a + 20 > 4b  6a = 20 > Point (a,b) lies on line h: 4y  6x = 20 From the equations of Line f and Line h, we can conclude that these 2 lines are parallel, and line h is located within Region J (because 20 < 32) > Sufficient. Answer B.
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