Last visit was: 13 Dec 2024, 09:50 It is currently 13 Dec 2024, 09:50
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 13 Dec 2024
Posts: 97,873
Own Kudos:
685,569
 []
Given Kudos: 88,268
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,873
Kudos: 685,569
 []
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
BrentGMATPrepNow
User avatar
GMAT Club Legend
Joined: 12 Sep 2015
Last visit: 13 May 2024
Posts: 6,786
Own Kudos:
32,197
 []
Given Kudos: 799
Location: Canada
Expert reply
Posts: 6,786
Kudos: 32,197
 []
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,341
Own Kudos:
3,705
 []
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,341
Kudos: 3,705
 []
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
GMATinsight
User avatar
GMAT Club Legend
Joined: 08 Jul 2010
Last visit: 13 Dec 2024
Posts: 6,074
Own Kudos:
14,603
 []
Given Kudos: 125
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,074
Kudos: 14,603
 []
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, ABCD is a rectangle inscribed in a circle. If the length of AB is three times the length of AD, then what is the ratio of the area of the rectangle to the area of the circle? (Figure not drawn to scale.)

A. 1:2
B. 3:2π
C. 2:5
D. 4:3π
E. 6:5π

Kudos for a correct solution.

Attachment:
rectangle-circle.gif

Let, AB = 3
and AD = 1
i.e. BD = \(\sqrt{3^2 + 1^2}\) = \(\sqrt{10}\) = Diameter of Circle

Area of Rectangle = AB x BD = 3 x 1 = 3

Area of Circle = (π/4)*Diameter^2 = (π/4)*10 = 5π/2

Area of Rectangle / Area of Circle = 3 / (5π/2) = 6/5π

Answer: Option E
User avatar
ashokk138
Joined: 20 Jul 2011
Last visit: 22 Jun 2021
Posts: 72
Own Kudos:
41
 []
Given Kudos: 18
GMAT 1: 660 Q49 V31
GMAT 1: 660 Q49 V31
Posts: 72
Kudos: 41
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, ABCD is a rectangle inscribed in a circle. If the length of AB is three times the length of AD, then what is the ratio of the area of the rectangle to the area of the circle? (Figure not drawn to scale.)

A. 1:2
B. 3:2π
C. 2:5
D. 4:3π
E. 6:5π

Kudos for a correct solution.

Attachment:
rectangle-circle.gif

Given: AB = 3 * AD

Let AD = x => AB = 3x. Let the diameter be d

d^2 = x^2 + 9x^2

d = ( x * \(\sqrt{10}\) )/2

radius = d/2 = (x * \(\sqrt{10}\) )/4

Area of rectangle : area of circle

x * 3x : π * (x/4\(\sqrt{10}\)) ^ 2

3x^2 : π * x^2 * (10/4)

12: 10 π => 6 : 5π

Option E
User avatar
aimtoteach
Joined: 17 Jul 2014
Last visit: 02 Feb 2016
Posts: 73
Own Kudos:
111
 []
Given Kudos: 62
Status:GMAT Date: 10/08/15
Location: United States (MA)
Concentration: Human Resources, Strategy
GMAT 1: 640 Q48 V35
GPA: 3.5
WE:Human Resources (Consumer Packaged Goods)
GMAT 1: 640 Q48 V35
Posts: 73
Kudos: 111
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Lets assume AD = 2 so AB = 6 (3 times AD)

By applying Pyth. Theory we know that AC ( which is the diameter of the circle) is -

6^2 +2^2 = AC^2

AC = 2√10

Ratio = 2*6 / pi (2√10)^2

= 6/5pi is the answer --> option E
User avatar
GMATinsight
User avatar
GMAT Club Legend
Joined: 08 Jul 2010
Last visit: 13 Dec 2024
Posts: 6,074
Own Kudos:
14,603
 []
Given Kudos: 125
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,074
Kudos: 14,603
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ashokk138
Bunuel

In the figure above, ABCD is a rectangle inscribed in a circle. If the length of AB is three times the length of AD, then what is the ratio of the area of the rectangle to the area of the circle? (Figure not drawn to scale.)

A. 1:2
B. 3:2π
C. 2:5
D. 4:3π
E. 6:5π

Kudos for a correct solution.

Attachment:
rectangle-circle.gif

Given: AB = 3 * AD

Let AD = x => AB = 3x. Let the diameter be d

d^2 = x^2 + 9x^2

d = ( x * \(\sqrt{10}\) )/2

radius = d/2 = (x * \(\sqrt{10}\) )/4

Area of rectangle : area of circle

x * 3x : π * (x/4\(\sqrt{10}\)) ^ 2

3x^2 : π * x^2 * (10/4)

12: 10 π => 6 : 5π

Option E

The highlighted part is a mistake which has led to several mistakes in the three steps in between.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 13 Dec 2024
Posts: 97,873
Own Kudos:
Given Kudos: 88,268
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,873
Kudos: 685,569
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, ABCD is a rectangle inscribed in a circle. If the length of AB is three times the length of AD, then what is the ratio of the area of the rectangle to the area of the circle? (Figure not drawn to scale.)

A. 1:2
B. 3:2π
C. 2:5
D. 4:3π
E. 6:5π

Kudos for a correct solution.

Attachment:
rectangle-circle.gif

800score Official Solution:

Let AD = x. AB = 3x. Area of the rectangle is (AD) × (AB) = x × (3x) = 3x².

Using the Pythagorean theorem, take AB and AD to get the diameter AC of the circle.
x² + (3x)² = AC²
x² + 9x² = AC²
10x² = AC²
AC = x√10 and the radius is [x√10] / 2.

The area of a circle is πr², so the area is π [(x√10) / 2]² = (10πx²)/4 = (5πx²)/2.

The ratio is:
3x² : (5πx²)/2 = 3 : 5π/2 = 6 : 5π

The correct answer is E.
User avatar
gota900
Joined: 15 Aug 2018
Last visit: 27 Aug 2021
Posts: 38
Own Kudos:
Given Kudos: 49
GMAT 1: 740 Q47 V45
GPA: 3.5
GMAT 1: 740 Q47 V45
Posts: 38
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For my understanding:

Is the statement "figure not drawn to scale" the obvious indicator that we can not assume the properties of a 90-60-30 triangle? That was what I tried to do.

So the trick here is to recognize that? I thought that:

Since the diagonal of the rectangle passes the midpoint, I could conclude that it functions as hypothenuse which yields us the information that we will definitely have 90 degrees in the rectangle. Furthermore, I based my following assumptions (90-60-30) triangle on the fact that the line that passes the midpoint would work as some sort of bisector to the 90 degree angles of the rectangle. (Is this where it all went wrong?)

Is the only thing I can trust in this prompt the fact that we have a rectangle inscribed in a circle? All the previously mentioned conclusions can't be drawn with certainty, is that correct? I'm a little confused here...
User avatar
GMATinsight
User avatar
GMAT Club Legend
Joined: 08 Jul 2010
Last visit: 13 Dec 2024
Posts: 6,074
Own Kudos:
Given Kudos: 125
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,074
Kudos: 14,603
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, ABCD is a rectangle inscribed in a circle. If the length of AB is three times the length of AD, then what is the ratio of the area of the rectangle to the area of the circle? (Figure not drawn to scale.)

A. 1:2
B. 3:2π
C. 2:5
D. 4:3π
E. 6:5π

Kudos for a correct solution.

Attachment:
rectangle-circle.gif

Adding video solution to the list

User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 35,813
Own Kudos:
Posts: 35,813
Kudos: 929
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderator:
Math Expert
97872 posts