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Math Expert V
Joined: 02 Sep 2009
Posts: 56300
In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 74% (01:04) correct 26% (01:26) wrong based on 68 sessions

### HideShow timer Statistics  In the figure above, x, y and z are the dimensions of the rectangular solid, and each of these dimensions is an integer greater than 1. Each of the following could be the volume of the rectangular solid except

(A) 8
(B) 12
(C) 24
(D) 27
(E) 69

Attachment: 2017-12-08_1440.png [ 11.78 KiB | Viewed 914 times ]

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Current Student P
Joined: 18 Aug 2016
Posts: 617
Concentration: Strategy, Technology
GMAT 1: 630 Q47 V29 GMAT 2: 740 Q51 V38 Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Bunuel wrote: In the figure above, x, y and z are the dimensions of the rectangular solid, and each of these dimensions is an integer greater than 1. Each of the following could be the volume of the rectangular solid except

(A) 8
(B) 12
(C) 24
(D) 27
(E) 69

Attachment:
2017-12-08_1440.png

(A) 8 = 2*2*2
(B) 12 =2*2*3
(C) 24 = 2*4*3
(D) 27 = 3*3*3
(E) 69 = 3* 13 * 1..not possible

E
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Luckisnoexcuse
Manager  S
Joined: 13 Apr 2010
Posts: 89
Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Bunuel wrote: In the figure above, x, y and z are the dimensions of the rectangular solid, and each of these dimensions is an integer greater than 1. Each of the following could be the volume of the rectangular solid except

(A) 8
(B) 12
(C) 24
(D) 27
(E) 69

Attachment:
2017-12-08_1440.png

Among the choices only "69" can't be factored into three integers , each factor greater than One to fit the volume of rectangular solid (V = h * w * d)
Intern  B
Joined: 11 Jan 2018
Posts: 19
Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Sorry if this is a silly question, isn't a cube different from a rectangular solid?
Math Expert V
Joined: 02 Sep 2009
Posts: 56300
Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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minatminat wrote:
Sorry if this is a silly question, isn't a cube different from a rectangular solid?

All cubes are rectangular solids but not vise-versa.
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Intern  B
Joined: 20 Dec 2017
Posts: 36
Location: Singapore
In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Split the answer options using the prime factorization method, but stop once you can split into 3 smaller factors to save time. The answer choice that is unable to give you 3 number of factors (excluding 1 & itself) is the answer.

A) 8 = 4*2 = 2*2*2 (ok)
B) 12 = 2*6 = 2*2*3 (ok)
C) 24 = 2*12 = 2*2*6 (ok)
D) 27 = 3*9 = 3*3*3 (ok)
E) 69 = 3*23

As 23 is a prime number and cannot be further split other than 1 and itself, E is the answer.
Intern  B
Joined: 11 Jan 2018
Posts: 19
Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Bunuel wrote:
minatminat wrote:
Sorry if this is a silly question, isn't a cube different from a rectangular solid?

All cubes are rectangular solids but not vise-versa.

Thanks so much for replying me!!
ISB School Moderator G
Joined: 08 Dec 2013
Posts: 529
Location: India
Concentration: Nonprofit, Sustainability
GMAT 1: 630 Q47 V30 WE: Operations (Non-Profit and Government)
Re: In the figure above, x, y and z are the dimensions of the rectangular  [#permalink]

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Bunuel wrote: In the figure above, x, y and z are the dimensions of the rectangular solid, and each of these dimensions is an integer greater than 1. Each of the following could be the volume of the rectangular solid except

(A) 8
(B) 12
(C) 24
(D) 27
(E) 69

Attachment:
2017-12-08_1440.png

Volume= a*b*c, where a,b,c > 0 and a,b,c are INTEGERS

For 69 can be broken into= 3*23*1, not possible.
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I never gave up what I wanted- Re: In the figure above, x, y and z are the dimensions of the rectangular   [#permalink] 13 May 2019, 22:31
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