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ynaikavde
In the figure below, the rectangular at the corner measures 10cm x 20cm. The corner A of the rectangle is also a point on the circumference of the circle. What is the radius of the circle in cm?


A) 10
B) 40
C) 30
D) 50
E) None of the above

Attachment:
delete.png

we can easily eliminate A.
since the sides of the rectangular figure are 10x20, and since 2r = side of the big square, it must be true that 10 can't be the radius... otherwise, one side would be exactly half of the side of the big square...
method given by bunuel is a good approach...
r^2 = (r-10)^2 + (r-20)^2
r^2 = r^2 -20r +100 + r^2 -40r + 400
r^2 - 60r +500 = 0
(r-10)(r-50)=0
r=50
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Bunuel
ynaikavde
In the figure below, the rectangular at the corner measures 10cm x 20cm. The corner A of the rectangle is also a point on the circumference of the circle. What is the radius of the circle in cm?


A) 10
B) 40
C) 30
D) 50
E) None of the above

Attachment:
delete.png

Consider the diagram below:



(r - 10)^2 + (r - 20)^2 = r^2;
r = 10 or r = 50.
r cannot be 10, so it's 50.

Answer: D.

Need help.! Can we apply PA*PB=PT^2 if PB is the diameter of circle?
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Bunuel : Can you please explain me where I went wrong in my approach ?

I somehow ended up imagining the figure on a coordinate plane and used equation of circle and distance formula. However, I got stuck after that.

I understood your solution posted above. However, I wish to know where I went wrong in my approach so as to avoid mistakes in future.

Appreciate help.

Thankyou in advance.

Regards,
Saakhi
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