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Intern  Joined: 18 Sep 2014
Posts: 6
In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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12 00:00

Difficulty:   5% (low)

Question Stats: 81% (01:07) correct 19% (01:08) wrong based on 158 sessions

### HideShow timer Statistics  In the figure below, a square is inscribed in a circle. If the area of the square region is 16, what is the area of the circular region?

(A) 2π
(B) 4π
(C) 8π
(D) 12π
(E) 16π

Attachment: square-in-circle.png [ 19.04 KiB | Viewed 10081 times ]

Area of a square = (Diagonal)^2 /2

16 = (Diagonal)^2 /2

32 = (Diagonal)^2
Diagonal = 4 (2)^(1/2)
Diagonal = Diameter in the given figure
Area of a circle = πr^2
= π [2(2)^(1/2)]^2
= 8π

Originally posted by bumblebee14 on 01 Mar 2015, 08:31.
Last edited by Bunuel on 14 Jul 2019, 21:26, edited 2 times in total.
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GMAT 1: 800 Q51 V49 GRE 1: Q170 V170 Re: In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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Hi bumblebee14,

It's great that you posted this question. However, by posting your explanation (and the correct answer) immediately under it, it's difficult for any of the other users to avoid looking at your answer. I'd suggest that you post all of that as a 'spoiler', so that others can attempt this question without any part of the explanation staring them right in the face.

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# Rich Cohen

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Special Offer: Save $75 + GMAT Club Tests Free Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/ Manager  B Joined: 20 Apr 2013 Posts: 124 Re: In the figure below, a square is inscribed in a circle. If the area of [#permalink] ### Show Tags Also, the question says: "In the figure above"; can you please post the figure, so that readers have clarity on this. EMPOWERgmat Instructor V Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 14554 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: Q170 V170 Re: In the figure below, a square is inscribed in a circle. If the area of [#permalink] ### Show Tags Hi All, In these types of multi-shape questions, it's usually a must to focus on the radius of the circle. Do you know it's value? Can you figure it out? How does the radius "interact" with the other shape(s)? Here, we know that the area of the square is 16, so each side of the square = 4. The diagonal of the square = the diameter of the circle. So…. 4(root2) = diameter 2(root2) = radius Next, plug the radius into the formula for area of a circle: pi(radius)^2 pi(2root2)^2 = 8pi Final Answer: GMAT assassins aren't born, they're made, Rich _________________ 760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com *****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***** # Rich Cohen Co-Founder & GMAT Assassin Follow Special Offer: Save$75 + GMAT Club Tests Free
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Re: In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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I still dont understand the explanation : ((
Would someone be able to help pls?
Intern  Joined: 25 Dec 2018
Posts: 1
Re: In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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1
hsn81960 wrote:
I still dont understand the explanation : ((
Would someone be able to help pls?

Isosceles is 1:1:root2

so diagonal(and diameter) is 4(root2)

R = 1/2 diameter means diameter is 2root2
Plug into pi r^2

First find r^2 = 2^2(root2)^2 = 2*4
2*4Pi = 8pi
Intern  Joined: 06 Jul 2019
Posts: 2
Re: In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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Can someone please explain why you Pythagoras theorem wouldn't work here?

4^2 + 4^2 = 32
root(32) = diameter

pi[root(16)]^2 = Pi16.

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Re: In the figure below, a square is inscribed in a circle. If the area of  [#permalink]

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bumblebee14 wrote:
In the figure below, a square is inscribed in a circle. If the area of the square region is 16, what is the area of the circular region?

(A) 2π
(B) 4π
(C) 8π
(D) 12π
(E) 16π

Let side of Square be $$= a$$

Radius of Circle $$= r$$

Area of square $$= a^2= 16$$

Side of square $$= a = 4$$

Diagonal of square $$= 4\sqrt{2}$$

Diagonal of square $$=$$ Diameter of circle

$$4\sqrt{2} = 2r$$

$$r = \frac{4\sqrt{2}}{2} = 2\sqrt{2}$$

Area of circle $$= \pi r^2 = \pi (2\sqrt{2})^2 = 8\pi$$ Re: In the figure below, a square is inscribed in a circle. If the area of   [#permalink] 07 Jul 2019, 08:59
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# In the figure below, a square is inscribed in a circle. If the area of  