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# In the table above, what is the least number of table entries that are

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In the table above, what is the least number of table entries that are  [#permalink]

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Updated on: 13 Jun 2017, 08:45
4
00:00

Difficulty:

25% (medium)

Question Stats:

69% (00:56) correct 31% (01:08) wrong based on 147 sessions

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In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36

OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/in-the-table ... 66572.html

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table.docx [10.7 KiB]

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Originally posted by Baten80 on 15 Feb 2011, 11:20.
Last edited by Bunuel on 13 Jun 2017, 08:45, edited 1 time in total.
Renamed the topic and edited the question.
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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15 Feb 2011, 11:24
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Look at this question as a Combination question

If you want to show the mileage between two cities, you have to select 2 out of the 6 cities given.
the total number of selections would be 6C2 = 15

Total number of Entries = 15
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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15 Feb 2011, 20:32
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Other than using combinations, you could see the chart has 6*6 = 36 entries. Diagonal is the distance from A to A, B to B etc so we can remove 6, leaving 30. Each has a duplicate so divide by 2 = 15
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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19 Apr 2011, 18:50
I did this one by counting rows in starting from each column, and decreasin succesively by 1. So A has 5 entries, B has 4 and so on..

The answer is = 15

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Re: In the table above, what is the least number of table entries that are  [#permalink]

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19 Apr 2011, 19:16
Easy way to go about this problem is we have 6*6 = 36 enteries in table the least number of enteries would be (36 - 6) /2 since 6 enteries represent the distances between same points .

Alternatively this can be solved as combination problem.

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Re: In the table above, what is the least number of table entries that are  [#permalink]

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13 Jun 2017, 08:46
Baten80 wrote:

In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36

The least number of table entries will be if we use only one entry for each pair of the cities. How many entries would the table then have? Or how many different pairs can be selected out of 6 cities?

$$C^2_{6}=15$$

Similar question to practice: http://gmatclub.com/forum/each-dot-in-t ... 95162.html

OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/in-the-table ... 66572.html
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Re: In the table above, what is the least number of table entries that are   [#permalink] 13 Jun 2017, 08:46
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# In the table above, what is the least number of table entries that are

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