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In the table above, what is the least number of table entries that are

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In the table above, what is the least number of table entries that are  [#permalink]

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New post 24 Jan 2014, 03:51
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A
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In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36

Problem Solving
Question: 56
Category: Arithmetic Interpretation of tables
Page: 69
Difficulty: 600


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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 20 Jul 2014, 02:59
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For A horizontal: 5 entries (eliminate A to A)
For B horizontal: 4 entries (A to B = B to A / eliminate B to B )
For C horizontal: 3 entries (we had already A to C & B to C previously/ eliminate C to C)
For D horizontal: 2 entries (we had already A to D & B to D & C to D previously/ eliminate D to D)
For E horizontal: 1 entry (we had already A to E & B to E & C to E & D to E previously/ eliminate E to E)
For F horizontal: 0 entries (we had already A to F & B to F & C to F & D to F & E to F previously/ eliminate F to F)

Hope it helps !
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 24 Jan 2014, 03:52
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In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36

The least number of table entries will be if we use only one entry for each pair of the cities. How many entries would the table then have? Or how many different pairs can be selected out of 6 cities?

\(C^2_{6}=15\)

Answer: A.

Similar question to practice: each-dot-in-the-mileage-table-above-represents-an-entry-95162.html
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 01 Aug 2014, 00:26
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Just count the colored boxes below the diagonal

= 5 + 4 + 3 + 2 + 1

= 15

Answer = A
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 01 Apr 2015, 03:09
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

Attachment:
The attachment Untitled.png is no longer available
In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36

Problem Solving
Question: 56
Category: Arithmetic Interpretation of tables
Page: 69
Difficulty: 600


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Answer 15 A
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 12 Oct 2015, 08:39
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Total possible pairs =6*6=36
Pairs with same letters=6
Pairs with same combinations (AB=BA etc) \(\frac{36-6}{2}\)=15
Answer=36-6-15=15
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 12 Oct 2015, 10:50
5+4+3+2+1=15
AB,AC,AD,AE,AF
BC,BD,BE,BF
CD,CE,CF
DE.DF
EF
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 04 Apr 2017, 16:20
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Bunuel wrote:

Attachment:
Untitled.png
In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15
(B) 21
(C) 25
(D) 30
(E) 36


This problem can be best solved using combinations.

This problem is similar to one in which 6 sports teams are playing in a tournament in which every team plays with each other team exactly once. No team plays itself, obviously, and the order of each pairing doesn't matter. [For example, if Team A plays Team B, the pairing of (Team A vs. Team B) is identical to (Team B vs. Team A)]. We would calculate 6C2, or the number of combinations of 6 items taken 2 at a time:

6C2 =6!/2! (6 - 2)! = (6 x 5)/2! = 15

Answer A
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Re: In the table above, what is the least number of table entries that are  [#permalink]

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New post 29 Sep 2018, 05:59
eybrj2 wrote:
Attachment:
Table.png
In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

A. 15
B. 21
C. 25
D. 30
E. 36


One entry must come between each pair of two cities

Two cities out of six cities (ABCDEF) can be chosen in 6C2 = 15 ways

Answer: Option C
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Re: In the table above, what is the least number of table entries that are &nbs [#permalink] 29 Sep 2018, 05:59
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