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MathRevolution
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sobby
MathRevolution
In the x-y plane, If line k does not pass through the origin, is the slope of the line K negative?

1) The y-intercept of the line K is 4 times the x-intercept of the line K
2) The product of the y-intercept and the x-intercept of the line K is positive


1.
Y intercept is 4 times the x ..
X intercept=(M,0)
Y-Intercept=(0,4M)

Slope = M-0/0-4M= -m/4m=-1/4.Suff.

B.
Two cases we can assume ..
1.X intercept and Y intercept will be -ve---Slope will be negative.
2.both positive-again slope is negative
we can plot in graph to check.
So D..
MathRevolution -- is my understanding correct

The way you calculated the slope in St 1 is incorrect.
It must be other way round i.e Slope = (0-4M) / (M-0) = -4 (since slope is defined as rise over run)
:)
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sobby
MathRevolution
In the x-y plane, If line k does not pass through the origin, is the slope of the line K negative?

1) The y-intercept of the line K is 4 times the x-intercept of the line K
2) The product of the y-intercept and the x-intercept of the line K is positive


1.
Y intercept is 4 times the x ..
X intercept=(M,0)
Y-Intercept=(0,4M)

Slope = M-0/0-4M= -m/4m=-1/4.Suff.

B.
Two cases we can assume ..
1.X intercept and Y intercept will be -ve---Slope will be negative.
2.both positive-again slope is negative
we can plot in graph to check.
So D..
MathRevolution -- is my understanding correct

The way you calculated the slope in St 1 is incorrect.
It must be other way round i.e Slope = (0-4M) / (M-0) = -4 (since slope is defined as rise over run)
:)

Yes, missed in haste...did other way around... :P
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==> In the original condition, there are 2 variables(there are 2 variables for a line -> slope and y-intercept). In order to match with the number of equations, you need 2 equations. For 1) 1 equation and for 2) 1 equation, which is likely to make C the answer. Through 1) & 2), 1)=2) is derived and it is yes for each condition.

Hence, it is sufficient and the answer is D.
Answer: D
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