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x/y > 2 then x,y must be both positive or both negative

if x,y are both negative, the inequation is always correct

so if x,y are both positive and the inequation is incorrect so the statement is insuff

x/y > 2 <=> x > 2y <=> 2y - x < 0 & x,y > 0

(1) x - y < 2 (I) 2y - x < 0 (II) (I) & (II) <=> y < 2 (III) (I) & (III) <=> x < 4

so 3x+2y< 12 + 4 = 16 < 18

sufficient

(2) we have x/y > 2 <=> x > 2y > y <=> y -x < 0 y - x < 2 (no new information)

so (2) insuff, we can check by giving it example

x = 32, y = 15 => 3x+2y > 18

So my answer is A

On of the toughest types of qustions in quant is inequalities !!you have realy given a very good tip to solve such !!! Even I got A but with some confusion !!thanks for sharing the approach !! +1 for u
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