The table displays the results of a repeated sampling of the Gallus ga

Question

IR Butler Competition 2021 - Participate and Win! Question # 29, Date : 14-Jan-2021 This question is a part of IR Butler competition 2021 . Click here for Details Genetic Sequence Percent of Samples Category Number of Amino Acids in Sequence Gene Encodes Protein Alpha-1-antiproteinase 2 29 A 425 No Alpha-1-antitrypsin 32 A 437 No Angiotensinogen 24 A 476 No Heparin cofactor 2 23 D 488 No Neuroserpin precursor 35 I 410 Yes Ovalbumin precursor 64 B 386 Yes Ovalbumin-related protein Y 99 B 397 No Plasma protease C1 inhibitor-like 27 G 503 No Protein Z-dependent protease inhibitor 31 A 439 No Serpin B6 44 B 379 Yes Serpin H1 precursor 33 H 405 Yes The table displays the results of a repeated sampling of the Gallus gallus (chicken) genome in which 11 genetic sequences were found. The percent of samples in which various sequences were found, as well as the category, number of amino acids, and ability to encode protein for each sequence, is provided. For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False. 2.jpg

Sajjad1994 · Accepted Answer

Official Explanation

Statement 1:  False.   Sort the table by Gene Encodes Protein; there are seven “No” sequences. Scan the Percent of Sample column for these seven sequences. Six of them are less than 50%, but Ovalbumin-related protein Y is 99%.

Statement 2:  False.   Sort the table by Category. The four sequences in category A each have over 400 amino acids. The three sequences in category B each have between 300 and 400 amino acids. Therefore the average number of amino acids is actually higher for the sequences in category A.

Statement 3:  True.   Sort the table by Number of Amino Acids in Sequence. Of the 11 sequences, 5 have fewer than 415 amino acids; therefore, 6 of the 11 have 415 or more. When choosing one of the 11 sequences at random, there is a 6/11 chance to choose one with more than 415 amino acids. This probability is greater than 1/2.

False, False and True

yashikaaggarwal · Answer

1) The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
 => FALSE  
Ovalbumin related protein Y can't encode a protein but has 99% of samples taken.

2) Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
 => FALSE 
Amino acid average of Category A has an average in the 400 range, whereas the amino acid range of Category B has an average of 300 range.

3) When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.
 => True 
6 of the sequences have a greater amino acid count than 415
so the probability is 6/11, which is greater than 1/2

TarunKumar1234 · Answer

Given,

The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken .-> we can't say it is true of false. Because, there are 4 cases where gene encode protein, in 3 cases samples taken are below 50% (35%, 44% and 33%), but in one case gene encode protein is 64% (greater than 50%). So, we can't say anything for sure here.

Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B. -  False

Reason: 
Average of A = (425+437+476+439)/4= 444.25
Average of B = (386+397+379)/3= 387.3

So, Average of A is not less than Average of B.

When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2. -  True

Reason: 
Event= there are 6 sequences where amino acids is greater than 415 (425, 437,476,488,503 and 439)

P(Event)= 6/11 >1/2

Estate · Answer

F F T

Deepakjhamb · Answer

For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False.

True False 
The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.

solution :

1)The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken :

by observation we see that sequences that cannot encode protein , one of them has been found in 99% SAMPLES ( Ovalbumin realted protein Y) , So clearly this is False

so answer for 1) is FALSE

2)Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B:

By observation we see that Category A sequences are 4 in number and are in 400's while B category sequences are 3 in number and are in 300's , so we do not even need to calculate and can infer that average of A would be greater than B for amino acids , so answer for q2 is also FALSE

3)When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.:

We see that 6 sequences have amino acids > 415 
so Prob (Desired ) = 6/11 which will be 1/(1.some decimal) so definitely this will be greater than 1/2

so answer for q3 is True

gauravmanu · Answer

1) False
2) False
3) True

Sumi1010 · Answer

For each of the following statements,  select True if the statement can be verified as true  based on the information in the table.

The sequences listed that cannot encode protein were  each  found in fewer than 50% of the samples taken.
  -- The sequence Ovalbumin-related Protein Y cannot encode protein, but is found in  99%  of the samples taken. 
FALSE. 
Sequences in category A have a  lower  average (arithmetic mean) number of amino acids than those sequences in category B.
 --This statement is clearly FALSE as each of the sequences in category A have 400+ amino acids while each of the sequences in category B have <400 amino acids.
 To be precise - 
Total number of amino acids in Sequences in category A = 425 + 437 + 476 + 439 = 1777
Thus, The average number of amino acids in Sequences in category A = 1777/4 =  444.25

Total number of amino acids in Sequences in category B = 386 + 397 + 379 = 1162
Thus, The average number of amino acids in Sequences in category B = 1162/3 =  387.33

FALSE
 
When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.
 The number of sequences having more than 415 amino acids = 6
That is 6 out of 11 ( > 50%) sequences have more than 415 amino acids .

TRUE

Thus, answers are : 
 FALSE, FALSE, TRUE

rocky620 · Answer

For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False.

The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.   False  .  Ovalbumin-related protein Y cannot be encoded and it was found in 99% of the samples.

Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.  False    
Sequences in Category A = 425, 437, 476, 439, Mean = 444.25
Sequences in Category B = 386, 397, 379, Mean = 387.33
We do not even have to calculate as the Sequences in category A are all above 420, and those in category B are all below 400. We can infer that the mean of Category A will be greater than that of Category B.

When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.  True   
Sequences which have more than 415 amino acids = 425, 437, 476, 488, 503, 439, Total count = 6
Probability =  \frac{6}{11} , which is greater than  \frac{6}{12}  or  \frac{1}{2}

Sajjad1994 · Answer

This is an Easy question, OA Is False, False and True. Everyone did well here. Official explanation will be posted soon.

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The table displays the results of a repeated sampling of the Gallus ga

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Genetic Sequence	Percent of Samples	Category	Number of Amino Acids in Sequence	Gene Encodes Protein
Alpha-1-antiproteinase 2	29	A	425	No
Alpha-1-antitrypsin	32	A	437	No
Angiotensinogen	24	A	476	No
Heparin cofactor 2	23	D	488	No
Neuroserpin precursor	35	I	410	Yes
Ovalbumin precursor	64	B	386	Yes
Ovalbumin-related protein Y	99	B	397	No
Plasma protease C1 inhibitor-like	27	G	503	No
Protein Z-dependent protease inhibitor	31	A	439	No
Serpin B6	44	B	379	Yes
Serpin H1 precursor	33	H	405	Yes

True	False
		The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
		Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
		When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.

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The table displays the results of a repeated sampling of the Gallus ga

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