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Math Expert V
Joined: 02 Sep 2009
Posts: 58371
Is integer k a multiple of 14?  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 51% (01:06) correct 49% (00:47) wrong based on 105 sessions

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Is integer k a multiple of 14?

(1) k > 13!
(2) k = m!, where m is an integer greater than 6.

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Intern  B
Joined: 02 Oct 2016
Posts: 35
Schools: HEC Dec '17
Is integer k a multiple of 14?  [#permalink]

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1
1) Minimum value of k = 14 and also 14! contains a 2 and 7 as its factors. YES. Sufficient.
2) Min value of k = 7 and 7! contains a 2 and 7 as its factors. YES. Sufficient.

D.
SVP  V
Joined: 26 Mar 2013
Posts: 2345
Re: Is integer k a multiple of 14?  [#permalink]

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Is k a multiple of 14?

Rephrase the question to be : K/14 = Integer

(1) k > 13!

K is any number that is GREATER than 13! so it does not mean to be integer.

K =14!.......Answer to question is Yes

K= 13!+ 0.5. it means that we have Number xyz.5.........So answer to question is NO

Insufficient

(2) k = m!, where m is an integer greater than 6.

As m is integer, k will always be integer.

m>6...i.e. 7, 8, 9

So we have always at least 2*7..............Answer to question is always Yes

Sufficient

Math Expert V
Joined: 02 Aug 2009
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Re: Is integer k a multiple of 14?  [#permalink]

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2
Bunuel wrote:
Is integer k a multiple of 14?

(1) k > 13!
(2) k = m!, where m is an integer greater than 6.

Hi,

Let's see the statements..
1) k >13!..
Don't take it to be 14!...
13! + 1 will not be div by 2 or 7, as 13! Is div by 2 and 7..
14! Will be div by 2 and 7..
Insufficient

2) k=m!, m>6 and an integer..
Next would be 7, and 7! Will contain both 2 and 7..
Anything above in the given condition will be div by 14..
Suff

B
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Re: Is integer k a multiple of 14?  [#permalink]

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answer is D. as both option include 2*7
Retired Moderator V
Joined: 22 Jun 2014
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Re: Is integer k a multiple of 14?  [#permalink]

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Answer should be B.

a number > 13! is not certainly divisible by 14. so stmt-1 is insuff.

a number factorial of greater than 6 will have both 7 and 2. hence divisible by 14. suff.
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Current Student V
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GMAT 1: 730 Q49 V41 Re: Is integer k a multiple of 14?  [#permalink]

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(1) would be sufficient if K were an integer. But it is not mentioned.

In (2) M is an integer and M>6. So the smallest possible value of M! = K is 7! which includes (2*7). Sufficient.
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GMAT 1: 780 Q51 V46 Re: Is integer k a multiple of 14?  [#permalink]

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It's important to note that we DO, in fact, know that k is an integer. The question stem, "Is integer k a multiple of 14?" tells us it is.

(if the question stem were "is k a multiple of 14?" or "is k an integer that is divisible by 14?" we would not know. But with the wording the way it is, we do know.)

Nonetheless, statement one is till insufficient. All we are told is that (integer) k is greater than some large number. But only every fourteenth integer will be on the "14 times table". In other words some of the integers greater than 13! will be a multiple of 14 and some of them won't. 14!, for example will be a multiple of 14, but the next integer up, 14! + 1, will not. Sometimes Yes, sometimes No; Statement 1 is insufficient.

As others have pointed out, the best way to see why statement two is sufficient is to consider prime factorization. If k/14 is going to be an integer, then k/(2*7) will be an integer. And if k/(2*7) is to be an integer, then the denominator must cancel out completely. In other words, k must include a 2 and a 7 in its prime factorization. Statement 2 tells us k could be 7! or 8! or 9! (and so on). No matter what, k will have at least one 2 and at least one 7 in its PF. Sufficient.

B.
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GMAT 1: 670 Q48 V34 Re: Is integer k a multiple of 14?  [#permalink]

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Given : k is an integer.

1. k>13!

13! is divisible by 14.(13x12x11x10x9x8x7x....)
But k is greater than 13!
So, possibilities :

k = 13! + 1(Not divisible by 14)
or
k = 13! + 14( Divisible by 14)

So by contradiction, INSUFFICIENT

2. k = m!, where m is an integer greater than 6.

k has a definite value that is equal to m!
And m > 6(m=7, 8,9,10)
Possibilities:

m = 7:

k = 7! or 8! or 9! (Divisible by 14, as 7! = 7x6....).

SUFFICIENT Re: Is integer k a multiple of 14?   [#permalink] 18 Mar 2018, 00:44
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