Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jan 2110:00 AM PST
-11:59 PM PST
For a limited time, get 20% off our GMAT courses, including private tutoring! Work with an expert who will help you ace the GMAT and achieve your dreams. Use code 20NEW.
Jan 2410:00 AM EST
-12:00 PM EST
The Target Test Prep team is proud to introduce GMAT OnDemand, a video course created by Scott Woodbury-Stewart, founder and CEO, designed to provide you with everything you need to master the GMAT and achieve your score goals.
Jan 2511:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Jan 26
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Updated on: 28 Apr 2013, 03:05
Originally posted by fireinbelly on 27 Apr 2013, 12:06.
Last edited by Bunuel on 28 Apr 2013, 03:05, edited 2 times in total.
Last edited by Bunuel on 28 Apr 2013, 03:05, edited 2 times in total.
Renamed the topic and edited the question.
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
52% (00:58) correct
48%
(00:53)
wrong
based on 174
sessions
History
Date
Time
Result
Not Attempted Yet
27 Apr 2013, 12:15
Kudos
Bookmarks
Is \(m^3 > m^2\)?
\(m^3-m^2>0\) or \(m(m^2-m)>0\)
I)The first part (m)is +ve if m>0
II)The second part (m^2-m) is +ve if \(m^2-m>0\) or if \(m>1\) or \(m<0\)
Put together the intervals I and II and you'll find that the equation is +ve(>0) if \(m>1\)
The question asks: is \(m>1\)?
1. m > 0
Not Sufficient
2. m < 1
Sufficient
B, to answer your question: the answer is C if the question were \(m^3 \geq{} m^2\)
In this case the value m=0 would be a problem, and m<1 would not be sufficient.
For any m<1 but \(\neq{}0\) the equation is negative (so no \(\geq{0}\)), but for m=0 equals 0: \(0\geq{0}\)
Only combining 1 and 2 we would be able to answer in this case
\(m^3-m^2>0\) or \(m(m^2-m)>0\)
I)The first part (m)is +ve if m>0
II)The second part (m^2-m) is +ve if \(m^2-m>0\) or if \(m>1\) or \(m<0\)
Put together the intervals I and II and you'll find that the equation is +ve(>0) if \(m>1\)
The question asks: is \(m>1\)?
1. m > 0
Not Sufficient
2. m < 1
Sufficient
B, to answer your question: the answer is C if the question were \(m^3 \geq{} m^2\)
In this case the value m=0 would be a problem, and m<1 would not be sufficient.
For any m<1 but \(\neq{}0\) the equation is negative (so no \(\geq{0}\)), but for m=0 equals 0: \(0\geq{0}\)
Only combining 1 and 2 we would be able to answer in this case
27 Apr 2013, 12:27
Kudos
Bookmarks
tirbah
Is m^3 > m^2?
1. m > 0
2. m < 1
1. m > 0
2. m < 1
Simplify the question first: \(m^3-m^2>0\) or \(m^2(m-1)>0\). Since \(m^2>=0\) for every \(m\),
\(m-1>0\) or \(m>1\).
So, the question is just: \(m>1?\)
(1) insufficient. For \(m=1/2\) the answer is No, and for \(m=2\) the answer is Yes.
(2) sufficient to give the answer No.
The correct answer is B.
Hope this helps.
