Is quadrilateral ABCD a rhombus?

Question

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

Bunuel · Accepted Answer

Thought about this again: D it is.

Well:
(1) True for square or for rhombus but every square is a rhombus, so sufficient
(2) Again true for square or for rhombus but every square is a rhombus, so sufficient

D

KarishmaB · Answer

Statement 1 says the diagonals are perpendicular bisectors of each other which means that they intersect each other at mid points and form 90 degree angles. It is not possible that they are in the shape of an asymmetric kite. Figure 1 is not possible. Only figure 2 is possible. In figure 2, all sides will be equal. Ques4.jpg

Bunuel · Answer

Answer D.

(1) Line segments AC and BD are perpendicular bisectors of each other. --> rhombus

(2) AB = BC = CD = AD --> rhombus

Or am I missing something, seems pretty obvious...

mk87 · Answer

Hi guys
I'm a little confused as to whether we should consider the properties of a kite when dealing with quadrilaterals. For example:

Is quadrilateral ABCD a Rhombus? 
(1) Line segments AC and BD are perpendicular bisectors of each other
(2) AB = BC = CD = AD

The official answer is as follows:
Statement 1 - SUFFICIENT: The diagonals of a rhombus are perpendicular bisectors of one another. This is in fact enough information to prove that a quadrilateral is a rhombus
Statement 2 - A quadrilateral with four equal sides is by definition a rhombus

What I don't get is that the question mentions it is a quadrilateral, not a parallelogram. In this case, how can we eliminate the possibility that it could be a kite as well in Statement 1?

mbaiseasy · Answer

A rhombus is a quadrilateral with all its sides equal to each other.

1. 
Imagine that the point where the bisectors meet is called X. 
Then, BX = DX and AX = CX.

Using the Pythagorean Theorem you could imagine getting the hypotenuse of sides BX and CX. 
Since AX = CX, then the hypotenuse of BX and AX is also as long as the previous. 
As you could imagine, all the hypotenuse formed are equal, thus forming equal 4 sides. Hence, a rhombus.

SUFFICIENT.

2.

All sides are equal.

SUFFICIENT.

Answer: D

jlgdr · Answer

Hi Bunuel When they perpendicular bisectors they mean that all angles and all sides are equal, therefore it is a square. And a square is just a type of rhombus? And for statement 2, when they say that all sides are equal, you can assume that it is a square therefore it is also a rhombus? Is that the correct line of reasoning? Thanks so much in advance Cheers J

Bunuel · Answer

For (1): a perpendicular bisector is a line which cuts a line segment into  two equal parts  at 90°.

Thus, "line segments AC and BD are perpendicular bisectors  of each other " means that AC cuts BD into  two equal parts  at 90° and BD cuts AC into  two equal parts  at 90°.

For (2): AB = BC = CD = AD, means that ABCD is either a rhombus or square (so still a rhombus).

Hope it helps.

honchos · Answer

But Bunuel this would be true even for rectangle:
Line segments AC and BD are perpendicular bisectors of each other.

I need Your though, am confused. Diagonals of rectangles also bisect each other.

Bunuel · Answer

For (1): a perpendicular bisector is a line which cuts a line segment into  two equal parts  at 90°.

Thus, "line segments AC and BD are perpendicular bisectors  of each other " means that AC cuts BD into  two equal parts  at 90° and BD cuts AC into  two equal parts  at 90°.

Now, the diagonals of a rectangle, though cut each other into two equal parts, do NOT necessarily cut each other at 90°. This happens only if a rectangle is a square but if ABCD is a square then it's also a rhombus.

Hope it's clear.

TARGET730 · Answer

Bunuel,

For (1), can you consider the case of a kite?

Bunuel · Answer

Yes. In the special case where all 4 sides are the same length, the kite satisfies the definition of a rhombus.

TooLong150 · Answer

This question is poor, because (1) could be right kite, which is not necessarily a rhombus or a rhombus, but (2) will always satisfy a rhombus.

KarishmaB · Answer

Actually, the question is fine.

A rhombus is a quadrilateral all of whose sides are of the same length - that's all. You could have a rhombus which also has all angles 90 which makes it a square or a rhombus in the shape of a kite. But nevertheless, if it is a quadrilateral and has all sides equal, it IS A RHOMBUS.

(1) Line segments AC and BD are perpendicular bisectors of each other.

Make 2 lines - a vertical and a horizontal - which are perpendicular bisectors of each other. Make them in any way of any length - just that they should be perpendicular bisectors of each other. When you join the end points, you will get all sides equal. Think of it this way - each side you get will be a hypotenuse of a right triangle. The legs of the right triangle will have the same pair of lengths in all 4 cases. So AB = BC = CD = AD. So ABCD must be a rhombus.

(2) AB = BC = CD = AD

This statement directly tells you that all sides are equal so ABCD must be a rhombus.

Answer (D)

KrishnakumarKA1 · Answer

Superset
The answer to the question will be either yes or no.

Translation
In order to find the answer, we need:
1# measure of length of sides
2# angle between the diagonals
3# other properties to justify that the quadrilateral is a triangle

Statement analysis
St 1: diagonals are bisectors happens in parallelogram. Diagonals are perpendicular happens in kite. A figure common to both is a rhombus. ANSWER.

St 2: if all sides are equal. The figure will be a rhombus. ANSWER

Option D

cgarmestani · Answer

Aren't the diagonals of any parallelogram perpendicular bisectors?

Bunuel · Answer

No.

The diagonals of a parallelogram always bisect (cut in half) each other but they are perpendicular to each other only if a parallelogram is a square.

thinkpad18 · Answer

Hi Bunuel,

Thanks for all your help. I have a question. Why is statement 1 a rhombus and not a kite or square? I am guessing it has to do with intersecting at 90 degrees vs. perpendicular bisectors. What is the difference between the two terminologies?

Bunuel · Answer

A perpendicular bisector is a line which cuts a line segment into two equal parts at 90° . A line segment bisector is a line which cuts a line segment into two equal parts. As for your other doubt, I think it is answered on the previous two pages: https://gmatclub.com/forum/is-quadrilat ... ml#p999739 https://gmatclub.com/forum/is-quadrilat ... l#p1277833 https://gmatclub.com/forum/is-quadrilat ... l#p1438436 https://gmatclub.com/forum/is-quadrilat ... l#p1497287 Hope it helps.

manishk30 · Answer

Just one question if you could help me.
Are not diagonals of rectangle perpendicular bisectors of each other. I know that they are not equal but they are at 90 degrees to each other and divide the diagonals in equal halves.

Is quadrilateral ABCD a rhombus?

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