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Math Expert V
Joined: 02 Sep 2009
Posts: 64174
Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 58% (01:26) correct 42% (01:26) wrong based on 79 sessions

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Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$

(2) $$|x| < 1$$

Project DS Butler Data Sufficiency (DS3)

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Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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1
Bunuel wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$

(2) $$|x| < 1$$

Project DS Butler Data Sufficiency (DS3)

Are You Up For the Challenge: 700 Level Questions

Question: Is x < 0?

Statement (1) $$x^2 - x > 0$$

i.e. x(x-1) > 0

i.e. either x > 1 (No) or x < 0 (Yes)

NOT SUFFICIENT

Statement (2) $$|x| < 1$$

i.e. -1 < x < 1

NOT SUFFICIENT

Combining the two statetemetns

-1 < x < 0 (YES)

SUFFICIENT

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Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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1
2
Bunuel wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$
(2) $$|x| < 1$$

(1) $$x^2 - x > 0$$
--> $$x(x - 1) > 0$$
Note: For a < b, If (x - a)(x - b) > 0. Solution is x < a or x > b
--> Solution is $$x < 0$$ or $$x > 1$$ --> Insufficient

(2) $$|x| < 1$$
--> $$-1 < x < 1$$
--> '$$x$$' can be $$>0$$ or $$<0$$ --> Insufficient

Combining (1) & (2),
--> Common solution is $$-1 < x < 0$$
--> $$x < 0$$ Definitely --> Sufficient

Option C
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Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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1
Bunuel wrote:
Is x<0? ?

(1) x^2 - x > 0
(2) |x| < 1

This is yes/no question. (Is x a negative number)

Analysis of Statement (1):
x^2 - x > 0
=> x^2 > x
[img]blob:https://www.symbolab.com/e21e63c7-dcff-4a20-91eb-bb3b7a044e54[/img]
As presented in the above number line, what we can get from statement-1 is that either x> 1 or x< 0 & that x can neither be 0 nor be a positive proper fraction. Hence, statement-1 is clearly insufficient.

Analysis of Statement (2):
|x| < 1
=> -1<x<1
[img]blob:https://www.symbolab.com/6695dbd9-9e62-4376-ae99-7a6b382aa35d[/img]
As presented in the above number line, what we can get from this statement-2 is that x can be either 0 or any positive proper fraction or any negative number greater than -1. We do not get the definite answer to the question stem. Hence, statement-2 is clearly insufficient.

Statement-1 & Statement-2 combined rule out the possibility that x can either be positive or be 0. Statement-1 & Statement-2 combined tell us the definite answer that x is negative (x<0).
Math Revolution GMAT Instructor V
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GPA: 3.82
Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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1
Bunuel wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$

(2) $$|x| < 1$$

Project DS Butler Data Sufficiency (DS3)

Are You Up For the Challenge: 700 Level Questions

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have 1 variable (x) and 0 equations, D is most likely to be the answer. So, we should consider each condition on its own first.

Condition 1)

$$x^2 - x > 0$$
$$⇔ x(x-1) > 9$$
$$⇔ x < 0$$ or $$x > 1$$

Since condition 1) does not yield a unique solution, it is not sufficient.

Condition 2)
$$|x| < 1$$
$$⇔ -1 < x < 1$$

Since condition 2) does not yield a unique solution, it is not sufficient.

Conditions 1) & 2)
The intersection of two solutions from conditions 1) and 2) is $$-1 < x < 0$$.
Then x is less than 0 all times and the answer is 'yes'.
Since both conditions together yield a unique solution, they are sufficient.

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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Posts: 493
Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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2
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$ -->insuff: x(x-1)>0 => x <0 & x>1

(2) $$|x| < 1$$ --> insuff: -1<x<+1

Combining (1) & (2) => -1<x<0, so sufficient
Intern  B
Joined: 15 Nov 2017
Posts: 16
Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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hiranmay wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$ -->insuff: x(x-1)>0 => x <0 & x>1

(2) $$|x| < 1$$ --> insuff: -1<x<+1

Combining (1) & (2) => -1<x<0, so sufficient

Hi

thanks for explanation.
will you please explain this equation
x(x-1)>0 => x <0
why x<0 why not x>0?
Intern  B
Joined: 15 Nov 2017
Posts: 16
Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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GMATinsight wrote:
Bunuel wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$

(2) $$|x| < 1$$

Project DS Butler Data Sufficiency (DS3)

Are You Up For the Challenge: 700 Level Questions

Question: Is x < 0?

Statement (1) $$x^2 - x > 0$$

i.e. x(x-1) > 0

i.e. either x > 1 (No) or x < 0 (Yes)

NOT SUFFICIENT

Statement (2) $$|x| < 1$$

i.e. -1 < x < 1

NOT SUFFICIENT

Combining the two statetemetns

-1 < x < 0 (YES)

SUFFICIENT

I know when my aim is to appear for GMAT I should have some basic knowledge. Yet will you plz explain how does first statement imply x<0.

Thanks
CrackVerbal Quant Expert P
Joined: 12 Apr 2019
Posts: 590
Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  [#permalink]

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tannumunu wrote:
hiranmay wrote:
Is $$x<0?$$ ?

(1) $$x^2 - x > 0$$ -->insuff: x(x-1)>0 => x <0 & x>1

(2) $$|x| < 1$$ --> insuff: -1<x<+1

Combining (1) & (2) => -1<x<0, so sufficient

Hi

thanks for explanation.
will you please explain this equation
x(x-1)>0 => x <0
why x<0 why not x>0?

Hello tannumunu,

$$x^2$$ – x>0 is a quadratic inequality. When you have a quadratic inequality, factorise the expression to obtain the roots of the expression. These represent the critical points on the number line. Since the expression is quadratic, it will clearly have two roots.

When you mark two points on a number line, you will see that these points will divide the ENTIRE number line into three segments. Consider the right most segment as positive, the segment in the middle as negative and the left most segment as positive. Reason enough to call this the wavy curve method since the graph sweeps down from right to left and then rises up.

If your inequality has a ‘>’ sign, the segments with the positive sign represent the solutions to your inequality. On the other hand, if your inequality has a ‘<’ sign, the segment with the negative sign represents the solutions to your inequality.

Let’s simplify $$x^2$$-x>0 to obtain x(x-1)>0. What are the roots here? They are 0 and 1, right? Let’s mark them on the number line which will look like this:

Attachment: 03rd Apr 2020 - Reply 3.jpg [ 31.01 KiB | Viewed 357 times ]

Since we have a ‘>’ sign in our inequality, the range of x which will satisfy our inequality is x>1 OR x<0. Important keyword here – OR. x can be greater than 1 OR lesser than 0.
As we do not know which range it is, we cannot conclusively say if x>0 or not.

x(x-1)>0. What does this mean? This means that the product of x and (x-1) has to be positive. This can happen only when both are positive or both are negative.

If x<0, (x-1)<0. If (x-1)<0, x<1. But, if x<0, then x<1 automatically, isn’t it? But, is x<0 the only range? No.

If x>0, (x-1)>0. If (x-1)>0, x>1. But, if x>1, then x>0 automatically, isn’t it?

https://bit.ly/2X35jno
_________________ Re: Is x < 0? (1) x^2 - x > 0 (2) |x| < 1   [#permalink] 02 Apr 2020, 23:26

# Is x < 0? (1) x^2 - x > 0 (2) |x| < 1  