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Is x^2>x^3

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G
Joined: 04 Sep 2016
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WE: Engineering (Other)
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Is x^2>x^3 [#permalink]

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New post 10 Nov 2017, 21:10
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A
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C
D
E

Difficulty:

  25% (medium)

Question Stats:

71% (00:49) correct 29% (00:12) wrong based on 38 sessions

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Is \(x^2 > x^3\) ?

(1) \(x^3\) > 0

(2) \(x\neq{1}\)
[Reveal] Spoiler: OA

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Joined: 17 Oct 2016
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Re: Is x^2>x^3 [#permalink]

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New post 10 Nov 2017, 21:24
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E

St1 says x>0. X can be any value. If x is an integer say 2, the answer to the question is No. but if x is a fraction say, 1/2 the answer is yes. Insufficient

St2 gives no info about x an integer or a fraction. Insufficient

Combining-clearly insufficient

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Re: Is x^2>x^3 [#permalink]

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New post 10 Nov 2017, 21:28
Bunuel VeritasPrepKarishma

Is there a better approach than plugging nos for this Q?

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Re: Is x^2>x^3 [#permalink]

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New post 11 Nov 2017, 01:01
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adkikani wrote:
Bunuel VeritasPrepKarishma

Is there a better approach than plugging nos for this Q?


Hi adkikani

the question can be simplified as \(x^2>x^3 => x^2-x^3>0\)

or \(x^2(1-x)>0\), Now \(x^2\) is always positive, hence the question is asking Is \(1-x>0\) or \(x<1\) ?

Statement 1: Implies that \(x\) is positive but it can be less than \(1\) eg. \(0.5\) or more than \(1\) eg \(2\). Hence Insufficient

Statement 2: again \(x\) can be less than \(1\) eg. \(-1\) or it can be more than \(1\) eg. \(2\). Hence Insufficient

Combining 1 & 2 we know that \(x\) is positive and not equal to \(1\). But \(x\) can be less than \(1\) eg \(0.5\) or more than \(1\) eg \(2\). Hence insufficient

Option E

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Re: Is x^2>x^3   [#permalink] 11 Nov 2017, 01:01
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