Forget the conventional way to solve DS questions.
We will solve this DS question using the variable approach.DS question with 1 variable: Let the original condition in a DS question contain 1 variable. In other words, there are two fewer equations than variables. Now, we know that each condition (1) and (2) would usually give us an equation, however, since we need 1 equation to match the numbers of variables and equations in the original condition, the unequal number of equations and variables should logically give us an answer D.
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Let’s apply the 3 steps suggested previously. [Watch lessons on our website to master these 3 steps]
Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.We have to find whether x= 5 .Second and the third step of Variable Approach: From the original condition, we have 1 variable (x). To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.Let’s take a look at each condition.Condition(1) tells us that x ≥ 5.=> 'x' can be '5' or more
=> For x = 5 - is x = 5 -
YES=> For x = 6 - is x = 5 -
NOSince the answer is not unique YES or NO, condition(1) is not sufficient by CMT 1.Condition(2) tells us that x ≤ 5.=> 'x' can be '5' or less
=> For x = 5 - is x = 5 -
YES=> For x = 1 - is x = 5 -
NOSince the answer is not unique YES or NO, condition(1) is not sufficient by CMT 1.Let’s take a look at both conditions together.=> x ≥ 5 and x ≤ 5 , only x = 5 possible - is x = 5 -
YESSince the answer is unique YES, both conditions together are sufficient by CMT 1.So, C is the correct answer.Answer: C _________________