Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

the function is not defined for x<0 because in \(\sqrt{x}\) x cannot be <0

so the question is : Is \(\frac{x}{\sqrt{x}}> 1\) or \(\sqrt{x}>1\), \(x>1\)?

(1) x^2 -5x + 6 > 0 x>3 or x<2. Not sufficient to say that x>1

(2) |x|^2 - 5|x| + 6 > 0 Because x cannot be negative this becomes x^2 -5x + 6 > 0, exactly the same as (1). Bad question IMO Of course is not sufficient

Because 1 and 2 are the same, together they add no new info. E What is the source?
_________________

It is beyond a doubt that all our knowledge that begins with experience.

Great question.. Solve the the stem...the equation boils down to Mod(Sqr root (x))>1 Using the statement 1 u can get x<2 or x>3 ......So substitute values and evaluate a yes no condition...u can get both the answers...

Using statement 2 ...u end up getting values for x that are +ve values less than 2 and + values greater than 3.... So here is a catch...u have X = 1 hence square root of 1 is 1 itself.....combining both the situation remains the same as in 2nd statement and hence the answer is E.

the function is not defined for x<0 because in \(\sqrt{x}\) x cannot be <0

so the question is : Is \(\frac{x}{\sqrt{x}}> 1\) or \(\sqrt{x}>1\), \(x>1\)?

(1) x^2 -5x + 6 > 0 x>3 or x<2. Not sufficient to say that x>1

(2) |x|^2 - 5|x| + 6 > 0 Because x cannot be negative this becomes x^2 -5x + 6 > 0, exactly the same as (1). Bad question IMO Of course is not sufficient

Because 1 and 2 are the same, together they add no new info. E What is the source?

sorry Zarrolou,

as you dint liked it.. this question was framed by me.

SKM
_________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

GIVE VALUE TO OFFICIAL QUESTIONS...

GMAT RCs VOCABULARY LIST: http://gmatclub.com/forum/vocabulary-list-for-gmat-reading-comprehension-155228.html learn AWA writing techniques while watching video : http://www.gmatprepnow.com/module/gmat-analytical-writing-assessment : http://www.youtube.com/watch?v=APt9ITygGss

First thing to note is that since root x is in the denominator, x must be positive.

When is \(|\frac{x}{\sqrt{x}}| > 1\)? When x is greater than \(\sqrt{x}\). When does that happen? When x is greater than 1. So we basically need to answer whether x is greater than 1 or not.

First things first, x cannot be negative or zero, as you cannot take the square root of a negative number, nor can x be = ) as that would leave ) in the denominator which isn't valid.

(1) x^2 -5x + 6 > 0 (x - 2)*(x - 3) > 0 x>3 OR x<2 If x>3 then (x-2)*(x-3) is (+)*(+) which is greater than zero. if x<2 then (x-2)*(x-3) is (-)*(-) which is positive thus greater than zero.

So x>3 (x/√x)>1 (3/√3)>1 TRUE

x<1 (1/√1)>1 FALSE (1/√1 =1) INSUFFICIENT

(2) |x|^2 - 5|x| + 6 > 0 As we determined in the stem, x cannot be negative nor can it be zero. Therefore, x must be positive. |x|^2 - 5|x| + 6 > 0 (x)^2 - 5(x) + 6 > 0 x^2-5x +6 > 0 (x-2)*(x-3) > 0 x>3 OR x<2 If x>3 then (x-2)*(x-3) is (+)*(+) which is greater than zero. if x<2 then (x-2)*(x-3) is (-)*(-) which is positive thus greater than zero.

We're left with the same information we determined in #1) INSUFFICIENT

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Military MBA Acceptance Rate Analysis Transitioning from the military to MBA is a fairly popular path to follow. A little over 4% of MBA applications come from military veterans...

Best Schools for Young MBA Applicants Deciding when to start applying to business school can be a challenge. Salary increases dramatically after an MBA, but schools tend to prefer...

Marty Cagan is founding partner of the Silicon Valley Product Group, a consulting firm that helps companies with their product strategy. Prior to that he held product roles at...