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Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3

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Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3  [#permalink]

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New post Updated on: 03 Oct 2018, 00:10
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

85% (01:11) correct 15% (01:20) wrong based on 46 sessions

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Is √(x + y) an integer?

(1) x^3 = 64
(2) x^2 = y – 3

Originally posted by HariS1992 on 03 Oct 2018, 00:00.
Last edited by Bunuel on 03 Oct 2018, 00:10, edited 1 time in total.
Renamed the topic.
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Re: Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3  [#permalink]

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New post 03 Oct 2018, 00:07
HariS1992 wrote:
Is √(x + y) an integer?

(1) x^3 = 64
(2) x^2 = y – 3



1. x^3 = 64
We can get the value of x = 4, but without the value of y - we can't
say whether √(x + y) is an integer. (Insufficient)

2. x^2 = y – 3
If x = 1 and y = 4, then √(x + y) is not an integer
If x = 2 and y = 7, then √(x + y) is an integer (Insufficient)

On combining the information in both the statements, we can clearly
get a unique value of x and y and √(x + y) is not an integer (Sufficient - Option C)

Btw, are you sure this is from the OG - 2017(because if it is - it must have definitely been discussed)
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Re: Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3  [#permalink]

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New post 03 Oct 2018, 02:59
I think OA should be B

because sqrt(x^2 + x + 3) will never be a perfect square for any integer value of x
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Re: Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3  [#permalink]

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New post 03 Oct 2018, 06:49
1
vipulkhandelwal999 wrote:
I think OA should be B

because sqrt(x^2 + x + 3) will never be a perfect square for any integer value of x



Take x as -3
U will get your answer
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Re: Is (x + y)^(1/2) an integer? (1) x^3 = 64 (2) x^2 = y – 3 &nbs [#permalink] 03 Oct 2018, 06:49
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