DesecratoR wrote:
Is x < y?
(1) z < y
(2) z < x
Well, I don't agree with answer given, and I 'm little bit frustrated because I think this is an easy question. Need your opinion and help if I 'm wrong. Thank you!
My reasoning:
Stmt 1:
z<y, ok. Doesn't provide information about relation between x and y. If z>x then x<z<y. But if z<x, we don't know anything about relation between x and y. So, not sufficient.
Stmt 2:
z<x, ok. z could be also less than y, hence no information about relation between x and y. Not sufficient.
Taken together, still not sufficient.
Answer: E
You are right for (1)+(2) we just have that x and y are more than some number z, we clearly cannot say whether x<y. So, the answer is E.
Notice that if (2) were x<z then the answer would be C, as for (1)+(2) we would have x<z<y --> x<y.
Hope it helps.
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