adkikani wrote:
Bunuel niks18 amanvermagmatQuote:
Is x < y?
(1) z < y
(2) z < x
Combining both statements, can we subtract (2) from (1)?
0 < y-x
Adding x to both sides:
x<y.
Hello
As Bunuel has already explained, we can add here and we will get:
z+z < y+x OR 2z < y+x
If you want to subtract the inequalities then the signs should be opposite, so lets re-write the second inequality to get the two as:
z < y
x > z
NOW we can subtract second from first, and the sign will be that of the first inequality, so we will get:
z - x < y - z OR 2z < y+x
This is the same result when we added the two. So the answer would be E.