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Is x < y?
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15 Jan 2014, 01:54
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93% (00:27) correct 7% (00:39) wrong based on 549 sessions
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Re: Is x < y?
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15 Jan 2014, 01:54



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Re: Is x < y?
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15 Jan 2014, 08:46
As per my understanding best way will be to eliminate choices. Since both (1) and (2) does not talk about the relation between x and y so we can eliminate option a,b,d. We are left with option c and option e .
Now we take following two cases satisfying both given condition z<x and z<y  x=2, y=3, z=1 > x<y
x= 10, y=5, z =1 > x>y
we can see that we can not guarantee the statement x>y by using both condition so answer is (E)Statements (1) and (2) TOGETHER are NOT sufficient to answer the question



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Re: Is x < y?
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15 Jan 2014, 09:26
i) No information about 'x' ii) No information about 'y' Combining (i) and (ii), we know that z is less than, both x and why, but we do not know which one of the two (x or y) is greater than the other. Hence (E)



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Re: Is x < y?
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16 Jan 2014, 02:15
Is x < y?
(1) z < y (2) z < x
Statement 1
Given that z < y, the relationship between z and x can not be determined, hence it is not possible to evaluate the inequality x < y .........Not Sufficient.
Statement 2
Given that z < x, the relationship between z and y can not be determined, hence it is not possible to evaluate the inequality x < y .........Not Sufficient.
Combining statements (1) and (2), we have z less than both y and x and this statement is not sufficient to evaluate x < y. As an example, the sets (x=3, y=4, z=2) and (x=4, y=3, z=2) satisfy the given inequalities, whereas x and y relation is not unique.
Answer: (E)



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Re: Is x < y?
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18 Jan 2014, 04:14



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Re: Is x < y?
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11 Sep 2015, 01:14
we do not have specific details about Z,X, Y
hence E



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Re: Is x < y?
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27 Aug 2017, 04:17
For this question, I found using the number line a bit easier to think through this logically Stem: Does X lie to the left of y on the number line? S1: Z lies to the left of Y on the number line. Dont know the position of X. Insuff S2: Z lies to the left of X on the number line. Dont know the position of Y. insuff S1+S2: Z lies to the left of X and Y on the number line. We still dont know relative position of X and Y. X could be to the left of Y or Vice Versa. Insuff Final Answer: E Number line attached, just for better understanding
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Screen Shot 20170827 at 5.41.47 PM.png [ 28.3 KiB  Viewed 1412 times ]
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Is x < y?
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04 Apr 2018, 20:55
Bunuel niks18 amanvermagmatQuote: Is x < y?
(1) z < y (2) z < x Combining both statements, can we subtract (2) from (1)? 0 < yx Adding x to both sides: x<y.
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Re: Is x < y?
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04 Apr 2018, 20:59



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Re: Is x < y?
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04 Apr 2018, 21:42
adkikani wrote: Bunuel niks18 amanvermagmatQuote: Is x < y?
(1) z < y (2) z < x Combining both statements, can we subtract (2) from (1)? 0 < yx Adding x to both sides: x<y. Hello As Bunuel has already explained, we can add here and we will get: z+z < y+x OR 2z < y+x If you want to subtract the inequalities then the signs should be opposite, so lets rewrite the second inequality to get the two as: z < y x > z NOW we can subtract second from first, and the sign will be that of the first inequality, so we will get: z  x < y  z OR 2z < y+x This is the same result when we added the two. So the answer would be E.




Re: Is x < y? &nbs
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