Is |x|/|y| < |x||y|? (1) x^3 > y^3 (2) y^5 > y^4

Because we have one more variable in the question:|x|/|y|[/fraction] < |x|*|y|. From (2) we know that y > 1 but know nothing about x. If x ≠ 0, then \(\frac{|x|}{|y|} > |x|×|y|\) (answer YES) but if x = 0, then \(\frac{|x|}{|y|} = |x|×|y|\) (answer NO).

Check my post above: You could reduce by |x| directly (provided x is not 0). If x = 0, then we cannot reduce and thus only y^5 > y^4 will not be sufficient.

Since division by 0 is not allowed, the prompt should indicate that \(y≠0\):



Since an absolute value cannot be negative. we can simplify the question stem by multiplying both sides by |y|:
\(\frac{|x|}{|y|}|y| < |x||y||y|\)
\(|x| < |x|y^2\)?

If \(x=0\), the answer to the question stem is NO.
If \(x≠0\), we can divide both sides by \(|x|\):
\(\frac{|x|}{|x|} < \frac{|x|y^2}{|x|}\)
\(1 < y^2\)?
Here, the answer will be YES if \(y>1\) or \(y<-1\).

Question stem, rephrased:
Is it true that \(x≠0\) and that \(y>1\) or \(y<-1\)?

Statement 1:
Case 1: x=3 and y=2
Since \(x≠0\) and \(y>1\), the answer to the question stem is YES.
Case 2: x=2 and y=1
Since \(y=1\), the answer to the question stem is NO.
INSUFFICIENT.

Statement 2:
Since the inequality implies that \(y≠0\), we can safely divide both sides by \(y^4\), which must be positive:
\(\frac{y^5}{y^4}>\frac{y^4}{y^4}\)
\(y > 1\)
No information about \(x\).
INSUFFICIENT.

Statements combined:
\(y>1\) implies that \(y^3>1\).
Thus:
\(x^3 > y^3 > 1\)
\(x^3 > 1\)
\(x > 1\)
Since \(x≠0\) and \(y>1\), the answer to the question stem is YES.
SUFFICIENT.





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If i wanted to solve this question with the help of numbers how can I solve it? Can anyone help me?

Can people make sure that their answers are correct when posting questions? Makes it a lot harder to study when you are trying to work out whether the answer is actually the answer or not

Hi Bunuel and IanStewart,
Can I rearrange the question stem in the following way?
\(\frac{|x|}{|y|} < |x|×|y|\)?
==> \(\frac{x^2}{y^2}<x^2 × y^2?\)
==> \(x^2<x^2 × y^4\)? [dividing by \(x^2\) in both side as \(x^2\) is positive]
==> \(y^4>1?\)

Yes. You could reduce by |x| directly (provided x is not 0). \(\frac{1}{|y|} < |y|\) --> |y|^2 > 1 --> y < -1 or y > 1.

BTW, the correct answer is C, not B. (2) give y > 1. If x ≠ 0, then \(\frac{|x|}{|y|} > |x|×|y|\) (answer YES) but if x = 0, then \(\frac{|x|}{|y|} = |x|×|y|\) (answer NO).

What is the source of the question?

Source: Wizako
In this question, if we can determine that \(y^2>1\) then the data is sufficient.
Conversely, if we can determine that \(y^2≤1\) then the data is also sufficient.
Isn't it?
Statement 2 says:
(2) \(y^5>y^4\)
Here, y^4 is positive, so we can divide both part by \(y^4\). We get from statement 2:
==> \(y>1\)
==> \(y^2>1\) [multiplying by both side]
So, why not B sufficient?

But i've deduced the question stem as \(y^4>1\) where there is no existence of x.
Thanks__

Thank you so much. Better if you edit the OA.

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