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Is x·|y| > y^2? (1) x > y (2) y > 0

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Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 08:46
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

80% (00:34) correct 20% (00:49) wrong based on 15 sessions

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Is x·|y| > y^2?

(1) x > y

(2) y > 0

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-y-y-2-1-x-y-2-y-127370.html

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 09:44
1) x>y

x= 3, y =2. x mod(y) > y^2.
x=3, y=-2. x mod(y)<y^2.

So Insuff

2)y>0, we don't know abt x so Insuff

1) & 2) together

x=3, y=2. x mod(y)>y^2. In general, if y is positive and x>y then x*y is always > then y*Y

C
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 09:48
I guess i am correcting myself. I did not consider fractions.

x = 1/4, y=1/2

xy = 1/8 and y^2 = 1/4. so xy<y^2.

So E.

I think my previous statement holds true for y>1
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 11:31
OA is C though I think it's wrong
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 11:40
nikhilpoddar wrote:
OA is C though I think it's wrong


whatever source you got this question from, practising DS from bad sources is like cursing yourself or digging your own grave!!!!
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 11:50
this question is from MGMAT practice test 2
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 13:18
The answer is C.

\(x\mid y\mid > y^2\)

1) \(y<0, -xy>y^2\)
2)\(y>0, xy>y^2\)

Stmt 1 => x>y alone tells notheing
Stmt 2 y>0 alone tells nothing

Combined

x>y>0

\(x^2>xy>y^2\)
since y>0, \(x \mid y\mid=yx>y^2\)

Sufficient
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 13:32
hagadre wrote:
I guess i am correcting myself. I did not consider fractions.

x = 1/4, y=1/2 have to be x> y

xy = 1/8 and y^2 = 1/4. so xy<y^2.

So E.

I think my previous statement holds true for y>1



opps have to agreee its C
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 28 Aug 2009, 22:24
x*|y|>y^2

that means x>|y|

(1) x > y
x=-1, y=-2, can't reach x>|y|, insuf

(2) y > 0
doesn't mean anything

combine together

x>y>0, x>|y|, therefore answer C
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 11 Jul 2011, 10:21
x*mod(y) > y^2.
=> x^2*y^2 > y^4
=> y^2(x^2 -y^2) >0 ---------------(1)

stmt 1: x >y, Not suff for (1)
stmt 2: y >0, not suff for (1)

combining, (1) holds good. C
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 11 Jul 2011, 18:07
1
Question: x |y| > y^2.

The RHS of the question is +ve and similarly |y| is also +ve. Then, x |Y| can be greater only when x is +ve and x >y.
SO, the question can be rephrased to, is x +ve and is x >y.

1. x > y => y and x can both be negative. So insufficient.

2. y >0 => no info about x. So insufficient.

1 + 2 => x > y and y >0. Hence (C).

Hope this is clear.
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Re: Is x·|y| > y^2? (1) x > y (2) y > 0 [#permalink]

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New post 06 Dec 2017, 00:25
Is x|y|>y^2?

(1) x>y --> if \(x>y>0\) then obviously \(x|y|>y^2\) but if \(0>x>y\) then \(x|y|0 --> [m]|y|=y\). No info about x. Not sufficient.

(1)+(2) Since \(x>y>0\) then \(xy>y^2\). Sufficient.

Answer: C.

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-y-y-2-1-x-y-2-y-127370.html

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Re: Is x·|y| > y^2? (1) x > y (2) y > 0   [#permalink] 06 Dec 2017, 00:25
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