Question: x |y| > y^2.

The RHS of the question is +ve and similarly |y| is also +ve. Then, x |Y| can be greater only when x is +ve and x >y.

SO, the question can be rephrased to, is x +ve and is x >y.

1. x > y => y and x can both be negative. So insufficient.

2. y >0 => no info about x. So insufficient.

1 + 2 => x > y and y >0. Hence (C).

Hope this is clear.

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