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24 Sep 2017, 23:53
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
57% (01:31) correct
43%
(01:25)
wrong
based on 70
sessions
History
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25 Sep 2017, 00:51
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Is xy = x^2 ?
so find if x = y. and x can be -ve or +ve
so let x= -5 , if y =-5 => xy =x^2
or if x = 5 and y =5 => xy = x^2
(1) x + y < 0
5+5<0 false
(-5)+(-5) <0 true
Insufficient
(2) xy < 0
this implies x and y have opposte sign .. if x= +ve than y = -ve => xy <0 or else if x = -ve than y = +ve so xy <0
=> This implies x can never be equal to y with sign .
Even if magnitude of x and y are same = 2 => x=2 and y need to be -2 => xy = -4 < 0
=> xy can never be equal to x^2
Sufficient
Answer: B
so find if x = y. and x can be -ve or +ve
so let x= -5 , if y =-5 => xy =x^2
or if x = 5 and y =5 => xy = x^2
(1) x + y < 0
5+5<0 false
(-5)+(-5) <0 true
Insufficient
(2) xy < 0
this implies x and y have opposte sign .. if x= +ve than y = -ve => xy <0 or else if x = -ve than y = +ve so xy <0
=> This implies x can never be equal to y with sign .
Even if magnitude of x and y are same = 2 => x=2 and y need to be -2 => xy = -4 < 0
=> xy can never be equal to x^2
Sufficient
Answer: B
25 Sep 2017, 01:07
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Bunuel
Is xy = x^2 ?
(1) x + y < 0
(2) xy < 0
(1) x + y < 0
(2) xy < 0
I think the answer is E.
1) states that x<y- doesn't say if they are equal or not
2)xy<0 - it can be x=-6 and y =1 or vice a versa.
c) not sufficient from 1) and 2)
