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It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times


We can let m = the number of days a man can complete the work by himself and w = the number of days a woman can complete the work by herself. Thus, 1/m = the rate of a man, and 1/w = the rate of a woman.

We can create the equations

6(3 x 1/w + 2 x 1/m) = 1

and

1/(3 x 1/m) = 1/(9 x 1/w) - 5

Simplifying the first equation, we have:

3/w + 2/m = 1/6

Multiplying the equation by 6wm, we have:

18m + 12w = mw

Simplifying the second equation, we have:

m/3 = w/9 - 5

Multiplying the equation by 9, we have:

3m = w - 45

3m + 45 = w

Substituting this in 18m + 12w = mw, we have:

18m + 12(3m + 45) = m(3m + 45)

18m + 36m + 540 = 3m^2 + 45m

3m^2 - 9m - 540 = 0

m^2 - 3m - 180 = 0

(m - 15)(m + 12) = 0

m = 15 or m = -12

Since m can’t be negative, m = 15. Hence, w = 3(15) + 45 = 90. We see that a man’s rate is 6 times that of a woman’s rate since the number of days a man can complete the job is only 1/6 of the number of days a woman can complete the job.

Answer: D
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Given: It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women.
Asked: How many times does the output of a man exceed that of a woman?

Let a man complete the work in m days and a women complete the same work in w days.

It takes 6 days for 3 women and 2 men working together to complete a work.
3/w + 2/m = 1/6

3 men would do the same work 5 days sooner than 9 women.
m/3 + 5 = w/9

m = 15; w = 90 is the solution

IMO D
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Guys, even if you know the solution right away, it takes several minutes (definitely more than 3) to just write it down to find the answer. Is it a real GMAT question? Can something like that be expected on the real test?
Below is another solution which is a little bit faster.

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman?
A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Let one woman complete the job in \(w\) days and one man in \(m\) days. So the rate of 1 woman is \(\frac{1}{w}\) job/day and the rate of 1 man is \(\frac{1}{m}\) job/day.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\).

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.
­Hello @Bunuel

I was able to solve this question, but it was a longer method involving quadratic equations.

Could you tell me how you arrived at your second equation: "m/3 + 5 = w/9"??
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kanikaa9

Bunuel

nonameee
Guys, even if you know the solution right away, it takes several minutes (definitely more than 3) to just write it down to find the answer. Is it a real GMAT question? Can something like that be expected on the real test?
Below is another solution which is a little bit faster.

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman?
A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Let one woman complete the job in \(w\) days and one man in \(m\) days. So the rate of 1 woman is \(\frac{1}{w}\) job/day and the rate of 1 man is \(\frac{1}{m}\) job/day.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\).

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.
­Hello @Bunuel

I was able to solve this question, but it was a longer method involving quadratic equations.

Could you tell me how you arrived at your second equation: "m/3 + 5 = w/9"??
I tried to elaborate on the solution in the following four posts:

https://gmatclub.com/forum/it-takes-6-d ... ml#p751436
https://gmatclub.com/forum/it-takes-6-d ... l#p1272526
https://gmatclub.com/forum/it-takes-6-d ... l#p1295389
https://gmatclub.com/forum/it-takes-6-d ... l#p1319223
Please review those and let me know if anything is still unclear.­
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Slightly different approach

3/w + 2/m = 1/6 where w and m are time to complete the work by an individual man or woman

3 men would do the same work 5 days sooner than 9 women.
So I believe original work too will be in similar time difference.
3/m = 1/x
9/w = 1/x+5

Multiplying original equation by 3

9/w + 6/m = 1/2
Then
1/x+5 + 2/x = 1/2
X can be 5

3/m = 1/5
And
9/w = 1/10
So
3/m *1/2 = 9/w
W=6m

Rate should be opposite.
So 6 times greater than women.
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One way to attempt this could be to calculate how many men and women will be needed to complete the work in 1 day.

3 women and 2 men requires 6 days to complete, so we will need 18 women and 12 men to complete job in 1 day.

Similarly let 9 women requires x days to complete work, which means 9x women will be required to complete work in a day.

3 men requires (x-5) days to complete work, which needs 3*(x-5) men to complete work in a day.

Equate these 3 equations -

Let w be women and m be men,

18 w + 12 m = 9x w
m/w = (9x-18)/12 = (3x-6)/4 --- (1)

9x w = (3x - 15) m
m/w = 9x/(3x-15) = 3x/(x-5) --- (2)

From 1 and 2,

(3x-6)/4 = 3x/(x-5)
(x-2)(x-5) = 4x
x^2 - 11x + 10 = 0
x = 10 or x = 1 (1 is not possible as 9 women cannot complete work in 1 day) which means,

9x = 90 women can complete same work as 3*(x-5) = 15 men in 1 day ie. 6 times

IMO: D
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1 men do 1/x work per day (1)
=> 3 men do 3/x work per day
=> 3 men do 1 work in x/3 days

9 women takes 5 days longer to finish the same work
=> 9 women do 1 work in x/3 + 5 = (x+15)/3 days
=> 9 women do 3/(x+15) work per day
=> 1 women do 3/(x+15) divided by 9 = 1/(3(x+15)) work per day (2)

From (1), 2 men in 6 days would do 12/x work
From (2), 3 women in 6 days would do 18/(3(x+15)) = 6/(x+15) work
They finish all work in 6 days, so 12/x + 6/(x+15) = 1

Solve for x
12/x + 6/(x+15) = 1
=> 12(x+15)+6(x)=(x)(x+15)
=> 12x+180+6x=x^2+15x
=> x^2-3x-180=0
=> (x-15)(x+12)=0
=> x=15 or x=-12 (impossible)

Plug x=15 to (1), men do 1/15 work in 1 day
Plug x=15 to (2), women do 1/(3*(15+15)) = 1/90 work in 1 day
90 / 15 = 6 => men capacity is 6 times more

Hope it helps :)
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how did you solve it furthur to get 15

Bunuel


Below is another solution which is a little bit faster.

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Let one woman complete the job in \(w\) days and one man in \(m\) days. So the rate of 1 woman is \(\frac{1}{w}\) job/day and the rate of 1 man is \(\frac{1}{m}\) job/day.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\).

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.
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lettercreativensq
how did you solve it furthur to get 15



From m/3 + 5 = w/9, get w = 3m + 45.

Substitute into 3/w + 2/m = 1/6:
3/(3m + 45) + 2/m = 1/6
1/(m + 15) + 2/m = 1/6
m^2 - 3m - 180 = 0
(m - 15)(m + 12) = 0
m = 15.
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