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# It takes 6 days for 3 women and 2 men working together to

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Joined: 02 Sep 2009
Posts: 53066
Re: Time n Work Problem  [#permalink]

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07 Feb 2014, 03:57
mrwells2 wrote:
Bunuel wrote:
nonameee wrote:
Guys, even if you know the solution right away, it takes several minutes (definitely more than 3) to just write it down to find the answer. Is it a real GMAT question? Can something like that be expected on the real test?

Below is another solution which is a little bit faster.

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman?
A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Let one woman complete the job in $$w$$ days and one man in $$m$$ days. So the rate of 1 woman is $$\frac{1}{w}$$ job/day and the rate of 1 man is $$\frac{1}{m}$$ job/day.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: $$\frac{3}{w}+\frac{2}{m}=\frac{1}{6}$$.

3 men would do the same work 5 days sooner than 9 women --> $$\frac{m}{3}+5=\frac{w}{9}$$.

Solving: $$m=15$$ and $$w=90$$. $$\frac{w}{m}=6$$.

I stumbled on this answer and think it's worth clarifying:

In the second equation: 3 men would do the same work 5 days sooner than 9 women --> $$\frac{m}{3}+5=\frac{w}{9}$$.

m and w are representing TOTAL work done by men and women.

Whereas in the first equation: Let one woman complete the job in $$w$$ days and one man in $$m$$ days. So the rate of 1 woman is $$\frac{1}{w}$$ job/day and the rate of 1 man is $$\frac{1}{m}$$ job/day.

m and w are representing the RATE of work done by men and women.

I hope this is correct (Bunuel can you confirm?) and has helped some grasp the concept.

No, that's not correct.

m and w in both equations represent the same thing: time.

w is the number of days (time) one woman needs complete the job.
m is the number of days (time) one man needs complete the job.

The following posts might help:
it-takes-6-days-for-3-women-and-2-men-working-together-to-82718.html#p751436
it-takes-6-days-for-3-women-and-2-men-working-together-to-82718-20.html#p1272526
it-takes-6-days-for-3-women-and-2-men-working-together-to-82718-40.html#p1295389
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It takes 6 days  [#permalink]

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16 Jul 2018, 02:46
An alternate approach for a problem in a locked thread:

Quote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman ?

a. 3
b. 4
c. 5
d. 6
e. 7

We can PLUG IN THE ANSWERS, which represent how many times a man's output exceeds that of a woman.
When the correct answer is plugged in, 3 men will take 5 fewer days to complete the job than 9 women.

B: 4
Let the rate for each woman = 1 unit per day and the rate for each man = 4 units per day.
Since it takes 6 days for 3 women and 2 men to complete the job, the job = (rate for 3 women and 2 men)(6 days) = (3*1 + 2*4)(6) = 66 units.
Time for 9 women to complete the job $$= \frac{work}{rate-for-9-women} = \frac{66}{(9*1)} = \frac{22}{3}$$ ≈ 7 days.
Time for 3 men to complete the job $$= \frac{work}{rate-for-3-men} = \frac{66}{(3*4)} = \frac{66}{12} = \frac{11}{2}$$ ≈ 5 days.
Doesn't work:
Here, 3 men take only about 2 fewer days than 9 women.
Eliminate B.
For 3 men to take 5 fewer days, the rate for each man must INCREASE.
Eliminate A.

D: 6
Let the rate for each woman = 1 unit per day and the rate for each man = 6 units per day.
Since it takes 6 days for 3 women and 2 men to complete the job, the job = (rate for 3 women and 2 men)(6 days) = (3*1 + 2*6)(6) = 90 units.
Time for 9 women to complete the job $$= \frac{work}{rate-for-9-women} = \frac{90}{(9*1)} = \frac{90}{9} = 10$$ days.
Time for 3 men to complete the job $$= \frac{work}{rate-for-3-men} = \frac{90}{(3*6)} = \frac{90}{18} = 5$$ days.
Success!
Here, 3 men take 5 fewer days than 9 women.

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Re: It takes 6 days for 3 women and 2 men working together to  [#permalink]

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17 Jul 2018, 03:15
2
virtualanimosity wrote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

We can PLUG IN THE ANSWERS, which represent how many times a man's output exceeds that of a woman.
When the correct answer is plugged in, 3 men will take 5 fewer days to complete the job than 9 women.

B: 4
Let the rate for each woman = 1 unit per day and the rate for each man = 4 units per day.
Since it takes 6 days for 3 women and 2 men to complete the job, the job = (rate for 3 women and 2 men)(6 days) = (3*1 + 2*4)(6) = 66 units.
Time for 9 women to complete the job = $$\frac{work}{rate-for-9-women} = \frac{66}{(9*1)} = \frac{22}{3} ≈ 7$$ days.
Time for 3 men to complete the job = $$\frac{work}{rate-for-3-men} = \frac{66}{(3*4)} = \frac{66}{12} = \frac{11}{2} ≈ 5$$ days.
Doesn't work:
Here, 3 men take only about 2 fewer days than 9 women.
Eliminate B.
For 3 men to take 5 fewer days, the rate for each man must INCREASE.
Eliminate A.

D: 6
Let the rate for each woman = 1 unit per day and the rate for each man = 6 units per day.
Since it takes 6 days for 3 women and 2 men to complete the job, the job = (rate for 3 women and 2 men)(6 days) = (3*1 + 2*6)(6) = 90 units.
Time for 9 women to complete the job = $$\frac{work}{rate-for-9-women} = \frac{90}{(9*1)} = \frac{90}{9} = 10$$ days.
Time for 3 men to complete the job = $$\frac{work}{rate-for-3-men} = \frac{90}{(3*6)} = \frac{90}{18} = 5$$ days.
Success!
Here, 3 men take 5 fewer days than 9 women.

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Re: It takes 6 days for 3 women and 2 men working together to  [#permalink]

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19 Jul 2018, 11:42
virtualanimosity wrote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

We can let the number of days for 1 man to finish the work = m and that for 1 woman = w. Thus, the rate of 1 man = 1/m and the rate of 1 woman = 1/w.

Since it takes 6 days for 3 women and 2 men working together to complete the work, we have:

6(3/w + 2/m) = 1

Since 3 men would do the same work 5 days sooner than 9 women, we have:

1/(3/m) + 5 = 1/(9/w)

m/3 + 5 = w/9

Multiplying the above by 9, we have:

3m + 45 = w

Substituting this into 6(3/w + 2/m) = 1, we have:

6(3/(3m + 45) + 2/m) = 1

6(1/(m + 15) + 2/m) = 1

Multiplying the above by m(m + 15), we have:

6m + 12(m + 15) = m(m + 15)

6m + 12m + 180 = m^2 + 15m

m^2 - 3m - 180 = 0

(m - 15)(m + 12) = 0

m = 15 or m = -12

Since m can’t be negative, m = 15. So w = 3(15) + 45 = 90. We see that it takes a man 15 days to complete the work but 90 days for a woman to complete the same work. So a man’s output is 6 times the output of a woman.

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Re: It takes 6 days for 3 women and 2 men working together to  [#permalink]

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07 Nov 2018, 22:55
1
1
virtualanimosity wrote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Please find attached the solution
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Re: It takes 6 days for 3 women and 2 men working together to  [#permalink]

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26 Nov 2018, 09:10
virtualanimosity wrote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

3w+2m= 1/6 (in one day )

NEXT: 3 men would do the same work 5 days sooner than 9 women , SO let X be the job done by woman and let x-5 be the work done by men

HENCE: $$\frac{1}{x}- \frac{1}{(x-5)} = \frac{x-5-x}{x(x-5)}$$ i.e $$\frac{-5}{x(x-5)}$$ (i know i got negative in numerator but still continued solving further )

$$\frac{-5}{x(x-5)}$$ = $$\frac{1}{6}$$ cross multiply

$$x(x-5)=-30$$

$$x$$ = $$\frac{-30}{x(x-5)}$$ now if i divide -30 by -5 i get 6. this was my solution to correct answer

Bunuel, pushpitkc generis do you think my solution is correct ?
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Re: It takes 6 days for 3 women and 2 men working together to  [#permalink]

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11 Jan 2019, 00:05
virtualanimosity wrote:
It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times

Hello all,

I couldn't solve this question within time. But i did attempt it the following manner and got the answer right. Can someone tell me if this approach is correct/incorrect?

Let the work be W.

Now, based on the data provided
- one man can do 1/3 of W
- one woman can do 1/9 of W

Here i am now assuming a number for W - let's say the work needed to be done is eating 27 pies. i.e. W=27

So one man can eat 9 pies and one woman can eat 3 pies.

Because the question asks How many times does the output of a man exceed that of a woman?, I have understood this as Output of a man (9 pies) is x more than output of a woman (3 pies).
so 9 = 3+x therefore, X=6.

Let me know if this makes sense or I was just lucky to get the answer right (won't work all the time)
Re: It takes 6 days for 3 women and 2 men working together to   [#permalink] 11 Jan 2019, 00:05

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