GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 22 Sep 2018, 00:35

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 49300
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

13 May 2017, 14:32
1
4
00:00

Difficulty:

25% (medium)

Question Stats:

75% (01:08) correct 25% (01:21) wrong based on 134 sessions

### HideShow timer Statistics

Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 8/33

D. 3/11

E. 1/3

_________________
Intern
Joined: 13 May 2017
Posts: 14
Location: Hungary
WE: Account Management (Entertainment and Sports)
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

13 May 2017, 15:02
1

Sent from my SM-G920F using GMAT Club Forum mobile app
Senior CR Moderator
Status: Long way to go!
Joined: 10 Oct 2016
Posts: 1387
Location: Viet Nam
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

13 May 2017, 20:21
1
Bunuel wrote:
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 2/11

D. 3/11

E. 1/3

To pick randomly 2 cans out of his refrigerator, there are $$12C2=66$$ different ways.
To pick randomly 2 cans out of his refrigerator and these 2 cans are cola and beer, there are $$4 \times 4 = 16$$ different ways.

The probability is $$\frac{16}{66}=\frac{8}{33}$$

Am I missing something?
_________________
SVP
Joined: 08 Jul 2010
Posts: 2334
Location: India
GMAT: INSIGHT
WE: Education (Education)
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

13 May 2017, 21:05
1
1
Bunuel wrote:
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 2/11

D. 3/11

E. 1/3

Probability = $$\frac{Favourable outcomes}{Total outcomes}$$ = 1- ($$\frac{Unfavourable outcomes}{Total outcomes}$$)

Ways to pull one can of Cola = 4C1 = 4
Ways to pull one can of Root Beer = 4C1 = 4

Favourable outcome = 4C1 * 4C1 = 4*4 = 16

Total Outcomes = total ways to pull 2 cans out of total 12 cans = 12C2 = 66

Probability = 16/66 = 8/33

Bunuel Please check the options as there seems to be some mistake
_________________

Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION

Current Student
Joined: 12 Aug 2015
Posts: 2648
Schools: Boston U '20 (M)
GRE 1: Q169 V154
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

14 May 2017, 14:13
1
I solved it via two methods ==>
Method (1)--->
which I generally use -->
Probability of the event => 4/12 *4/11 + 4/12 *4/11 => 8/33

Since it was not mentioned in the options ==> I moved to a slightly different method -->

Method 2--->

Total cases -->
(C1,C2)(C1,C3)(C1,C4)(C1,B1)...(C1,B4)(C1,G1)...(C1,G4)=> 11 cases for each item
Total cases => 11*12
Favourable cases => 4+4+4+4+4+4+4+4=> 32 cases

P(E) => 32/11*12 => 8/33 again..

What am I missing ?

_________________

MBA Financing:- INDIAN PUBLIC BANKS vs PRODIGY FINANCE!

Getting into HOLLYWOOD with an MBA!

The MOST AFFORDABLE MBA programs!

STONECOLD's BRUTAL Mock Tests for GMAT-Quant(700+)

AVERAGE GRE Scores At The Top Business Schools!

Math Expert
Joined: 02 Sep 2009
Posts: 49300
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

14 May 2017, 14:25
Bunuel wrote:
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 8/33

D. 3/11

E. 1/3

Edited the typo in options.
_________________
Manager
Joined: 04 Jan 2016
Posts: 166
Location: United States (NY)
GMAT 1: 620 Q44 V32
GMAT 2: 600 Q48 V25
GMAT 3: 660 Q42 V39
GPA: 3.48
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

14 May 2017, 15:06
We can work with slot method, probability of choosing cola times probability of choosing root times its combination (in this case two factorial)

$$\frac{4}{12} *\frac{4}{11} * 2 = \frac{8}{33}$$

Intern
Joined: 21 Mar 2017
Posts: 1
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

14 May 2017, 15:26
First choice is 8/12 or 2/3 because either can be chosen first. Second choice is the latter that wasn't chosen, so 4/11.

Answer: 2/3 * 4/11 = 8/33
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 3515
Location: United States (CA)
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

18 May 2017, 20:10
1
Bunuel wrote:
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 8/33

D. 3/11

E. 1/3

Let’s first determine the number of ways Jerome can pull 1 can of root beer and 1 can of cola from the fridge. The number of ways to pull the cola is 4C1 = 4 and the number of ways to pull the root beer is 4C1 = 4.

The total number of ways to pull 2 cans from the fridge, with no restrictions, is 12C2 = (12 x 11)/2! = 66 ways.

Thus, the probability is (4 x 4)/66 = 16/66 = 8/33.

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

CEO
Joined: 12 Sep 2015
Posts: 2872
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

04 Jan 2018, 09:26
Top Contributor
Bunuel wrote:
Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, and 4 cans of ginger ale. If Jerome were to randomly pull two cans out of his refrigerator, what is the probability that he would pull out one can of cola and one can of root beer?

A. 1/11

B. 1/9

C. 8/33

D. 3/11

E. 1/3

P(one can of cola and one can of root beer) = P(1st can is cola AND 2nd can is root beer OR 1st can is root beer AND 2nd can is cola)
= P(1st can is cola AND 2nd can is root beer) + P(1st can is root beer AND 2nd can is cola)
= P(1st can is cola) x 2nd can is root beer) + P(1st can is root beer) x P(2nd can is cola)
= 4/12 x 4/11 + 4/12 x 4/11
= 4/33 + 4/33
= 8/33
= C

RELATED VIDEO FROM OUR COURSE

_________________

Brent Hanneson – GMATPrepNow.com

EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 12425
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an  [#permalink]

### Show Tags

12 Jan 2018, 13:26
Hi All,

We have 4 cans each of: cola, root beer and ginger ale - which gives us a total of 12 cans. We're asked for the probability of pulling 2 cans and getting 1 cola and one root beer. The math behind this question can be approached in a couple of different ways.

1st can = cola OR root beer = 8/12

Once we pull that first can, there will then be 11 cans remaining and we'll need to pull the OTHER type (re: if we pulled cola 1st, then we would need to pull root beer 2nd - and vice versa).

2nd CAT = the other type = 4/11

Thus, the probability = (8/12)(4/11) = 32/132 = 8/33

GMAT assassins aren't born, they're made,
Rich
_________________

760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

# Rich Cohen

Co-Founder & GMAT Assassin

Special Offer: Save \$75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee
www.empowergmat.com/

***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************

Re: Jerome's refrigerator contains 4 cans of cola, 4 cans of root beer, an &nbs [#permalink] 12 Jan 2018, 13:26
Display posts from previous: Sort by

# Events & Promotions

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.