Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
17 Feb 2012, 19:53
5
00:00
A
B
C
D
E
Difficulty:
65% (hard)
Question Stats:
57% (01:58) correct 43% (02:12) wrong based on 422 sessions
HideShow timer Statistics
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
1) The average time it would take both to finish independently is 30 hours. 2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case.
This is actually from MGMAT flash cards. Looked interesting and hence I posted after modifying it a bit (I added a new statement).
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
17 Feb 2012, 21:55
3
2
Chembeti wrote:
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
1) The average time it would take both to finish independently is 30 hours. 2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case.
This is actually from MGMAT flash cards. Looked interesting and hence I posted after modifying it a bit (I added a new statement).
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
Given: 1/J + 1/F = 1/12
(1) The average time it would take both to finish independently is 30 hours --> J+F=60. Now, since we don't know which one drinks faster then even if we substitute F with 60-J (1/J + 1/(60-J) = 1/12) we must get two different answers for J and F: J<F and J>F. Not sufficient.
(2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case --> F=J-10 --> 1/J + 1/(J-10) = 1/12 --> J=4 (not a valid solution as F in this case is negative) and J=30 (F=20). Sufficient.
Now, technically the answer should be B, as Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
But even though the formal answer to the question is B, this is not a realistic GMAT question, as: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other. In our question, from (2) we have that the average time is (30+20)/2=25 and (1) states that it's 30, so the statements clearly contradict each other.
In order it to be a realistic GMAT question (1) should read: The average time it would take John to finish the case drinking alone and Fawn to finish the case drinking alone is 25 hours. In this case for (1) we'll have: 1/J + 1/(50-J) = 1/12 --> J=30 (so F=20 --> J>F) or J=20 (so F=30 --> J<F). Statements don't contradict and (1) is still insufficient.
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
17 Feb 2012, 21:20
Statement 1 can't be correct because you don't know who out of the 2 is the faster drinker... John could drink faster than his friend or vice versa. Also you definition of average is wrong... Average mean A+B/2. A and B does not have to be the same. It could take John 50 mins to finish and Fawn 10 mins The average would still be 30
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
17 Feb 2012, 21:35
kys123 wrote:
Statement 1 can't be correct because you don't know who out of the 2 is the faster drinker... John could drink faster than his friend or vice versa. Also you definition of average is wrong... Average mean A+B/2. A and B does not have to be the same. It could take John 50 mins to finish and Fawn 10 mins The average would still be 30
Faster drinker !!!! where does that come from???
St 1 Clearly states that "The average time it would take both to finish independently is 30 hours".
This clearly Implies : Rj = 1/30 , Rf= 1/30. In this case when they work together total time to finish this will be t=15.
But in the question they finish the work in 12 hrs. How come. The 1st statement is contradicting the question itself.
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
Updated on: 18 Feb 2012, 02:57
GMATPASSION wrote:
kys123 wrote:
Statement 1 can't be correct because you don't know who out of the 2 is the faster drinker... John could drink faster than his friend or vice versa. Also you definition of average is wrong... Average mean A+B/2. A and B does not have to be the same. It could take John 50 mins to finish and Fawn 10 mins The average would still be 30
Faster drinker !!!! where does that come from???
St 1 Clearly states that "The average time it would take both to finish independently is 30 hours".
This clearly Implies : Rj = 1/30 , Rf= 1/30. In this case when they work together total time to finish this will be t=15.
But in the question they finish the work in 12 hrs. How come. The 1st statement is contradicting the question itself.
Are there any Gaps or am I misinterpreting.
Yes Mate. There is a big gap. How do you identify who is faster and who is slower. Given the information you cannot decide. The question is asking for an individual's time. Its the average time. Imagine the average time is \(30\) hrs for both of them. This could happen in so many ways. The two values could be \(20\) & \(40\) or the two values could be \(10\) & \(50\). More importantly, we wouldn't know who accounted for which. The average of both these scenarios would be \(30\), NO? An infinite number of possibilities exist with that "Average" information alone. Only Statement B tells us the "weight" of each contributor and tells us who was quicker. That alone should be enough information for you to pick B (along-with the fact that B limits to one variable alone), in most cases, unless it is another one of those GMAT trick questions However, this one clearly isn't and Statement B is hence enough. Since we know the relative weights of each contributor, B wins and is SUFFICIENT alone. I suggest you look up "Weighted Averages" on Wikipedia or some good Mathematics site. By the way Bunuel has composed an amazing Maths Book on the Gmat Club Forum and the more I read it, the more I realize how precise his understanding of the GMAT Quantitative section is. I seriously suggest you read it up. It will help clear a lot of tricky logic gaps. Hope I was able to explain it to you. And thanks Bunuel for pointing the error in my post.
_________________
"Nowadays, people know the price of everything, and the value of nothing."Oscar Wilde
Originally posted by omerrauf on 18 Feb 2012, 00:50.
Last edited by omerrauf on 18 Feb 2012, 02:57, edited 5 times in total.
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
18 Feb 2012, 00:59
1
omerrauf wrote:
GMATPASSION wrote:
kys123 wrote:
Statement 1 can't be correct because you don't know who out of the 2 is the faster drinker... John could drink faster than his friend or vice versa. Also you definition of average is wrong... Average mean A+B/2. A and B does not have to be the same. It could take John 50 mins to finish and Fawn 10 mins The average would still be 30
Faster drinker !!!! where does that come from???
St 1 Clearly states that "The average time it would take both to finish independently is 30 hours".
This clearly Implies : Rj = 1/30 , Rf= 1/30. In this case when they work together total time to finish this will be t=15.
But in the question they finish the work in 12 hrs. How come. The 1st statement is contradicting the question itself.
Are there any Gaps or am I misinterpreting.
Yes Mate. There is a big gap. Its the average time. Imagine the average time is 30 hrs for both of them. This could happen in so many ways. The two values could be \(20\) & \(40\) or the two values could be \(10\) & \(50\). The average of both these scenarios would be \(30\), NO? An infinite number of possibilities exist with that "Average" information alone. Only Statement B tells us the "weight" of each contributor and that alone should be enough information for you to pick B, in most cases, unless it is another one of those GMAT trick questions However, this one clearly isn't and Statement B is hence enough. Since we know the relative weights of each contributor, B wins and is SUFFICIENT alone. Hope I was able to explain it to you.
Check the solution above: for (1) there exist only TWO combination of J and F, not more.
_________________
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
18 Feb 2012, 04:12
Bunuel wrote:
But even though the formal answer to the question is B, this is not a realistic GMAT question, as: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other. In our question, from (2) we have that the average time is (30+20)/2=25 and (1) states that it's 30, so the statements clearly contradict each other.
In order it to be a realistic GMAT question (1) should read: The average time it would take John to finish the case drinking alone and Fawn to finish the case drinking alone is 25 hours. In this case for (1) we'll have: 1/J + 1/(50-J) = 1/12 --> J=30 (so F=20 --> J>F) or J=20 (so F=30 --> J<F). Statements don't contradict and (1) is still insufficient.
Hope it's clear.
Actually MGMAT flashcards did not provide the first statement. I made it up so that the whole question looks like a GMAT question. But I did not think of the point you mentioned. Great man _________________
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
27 Dec 2014, 12:16
Bunuel wrote:
Chembeti wrote:
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
1) The average time it would take both to finish independently is 30 hours. 2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case.
This is actually from MGMAT flash cards. Looked interesting and hence I posted after modifying it a bit (I added a new statement).
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
Given: 1/J + 1/F = 1/12
(1) The average time it would take both to finish independently is 30 hours --> J+F=60. Now, since we don't know which one drinks faster then even if we substitute F with 60-J (1/J + 1/(60-J) = 1/12) we must get two different answers for J and F: J<F and J>F. Not sufficient.
(2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case --> F=J-10 --> 1/J + 1/(J-10) = 1/12 --> J=4 (not a valid solution as F in this case is negative) and J=30 (F=20). Sufficient.
Now, technically the answer should be B, as Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
But even though the formal answer to the question is B, this is not a realistic GMAT question, as: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other. In our question, from (2) we have that the average time is (30+20)/2=25 and (1) states that it's 30, so the statements clearly contradict each other.
In order it to be a realistic GMAT question (1) should read: The average time it would take John to finish the case drinking alone and Fawn to finish the case drinking alone is 25 hours. In this case for (1) we'll have: 1/J + 1/(50-J) = 1/12 --> J=30 (so F=20 --> J>F) or J=20 (so F=30 --> J<F). Statements don't contradict and (1) is still insufficient.
Hope it's clear.
Hi Bunnel , (1) The average time it would take both to finish independently is 30 hours --> J+F=60. Now, if we substitute F with 60-J (1/J + 1/(60-J) = 1/12) we will get a quadratic in J with one +ive and one -ive Solution for J . Clearly J cannot be negative . so this statement should be sufficient . no ? Please advise , if i am missing something .
thanks
_________________
Thanks, Lucky
_______________________________________________________ Kindly press the to appreciate my post !!
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
28 Dec 2014, 06:16
Lucky2783 wrote:
Bunuel wrote:
Chembeti wrote:
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
1) The average time it would take both to finish independently is 30 hours. 2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case.
This is actually from MGMAT flash cards. Looked interesting and hence I posted after modifying it a bit (I added a new statement).
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
Given: 1/J + 1/F = 1/12
(1) The average time it would take both to finish independently is 30 hours --> J+F=60. Now, since we don't know which one drinks faster then even if we substitute F with 60-J (1/J + 1/(60-J) = 1/12) we must get two different answers for J and F: J<F and J>F. Not sufficient.
(2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case --> F=J-10 --> 1/J + 1/(J-10) = 1/12 --> J=4 (not a valid solution as F in this case is negative) and J=30 (F=20). Sufficient.
Now, technically the answer should be B, as Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
But even though the formal answer to the question is B, this is not a realistic GMAT question, as: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other. In our question, from (2) we have that the average time is (30+20)/2=25 and (1) states that it's 30, so the statements clearly contradict each other.
In order it to be a realistic GMAT question (1) should read: The average time it would take John to finish the case drinking alone and Fawn to finish the case drinking alone is 25 hours. In this case for (1) we'll have: 1/J + 1/(50-J) = 1/12 --> J=30 (so F=20 --> J>F) or J=20 (so F=30 --> J<F). Statements don't contradict and (1) is still insufficient.
Hope it's clear.
Hi Bunnel , (1) The average time it would take both to finish independently is 30 hours --> J+F=60. Now, if we substitute F with 60-J (1/J + 1/(60-J) = 1/12) we will get a quadratic in J with one +ive and one -ive Solution for J . Clearly J cannot be negative . so this statement should be sufficient . no ? Please advise , if i am missing something .
thanks
Did you try to actually solve? You'd get two solutions for J, both positive: ~17 and ~43.
_________________
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
10 Nov 2016, 00:45
Chembeti wrote:
John and Fawn, each drinking at a constant pace, can finish a case of soda together in 12 hours. How fast can John, drinking alone, finish the case?
1) The average time it would take both to finish independently is 30 hours. 2) It would take John 10 more hours to finish the case drinking alone than it would for Fawn to finish the case.
This is actually from MGMAT flash cards. Looked interesting and hence I posted after modifying it a bit (I added a new statement).
Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html
Re: John and Fawn, each drinking at a constant pace, can finish
[#permalink]
Show Tags
20 Mar 2018, 05:05
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
close
57% (01:58) correct 
However, this one clearly isn't and Statement B is hence enough. Since we know the relative weights of each contributor, B wins and is SUFFICIENT alone. I suggest you look up "Weighted Averages" on Wikipedia or some good Mathematics site. By the way Bunuel has composed an amazing Maths Book on the Gmat Club Forum and the more I read it, the more I realize how precise his understanding of the GMAT Quantitative section is. I seriously suggest you read it up. It will help clear a lot of tricky logic gaps. Hope I was able to explain it to you. And thanks Bunuel for pointing the error in my post.
to appreciate my post !! 
