Distance travelled by John in 40 Minutes \(= \frac{15}{60} * 40 = 10\) Miles (At this point, his car gets punctured)

Distance travelled by Jacob in 40 Minutes\(= \frac{12}{60}* 40 = 8\)Miles (He is still moving)

John is idle for 1hr, means he's still at 10 Miles from initial start

Jacob is still moving for 1hr, means he has travelled another 12 Miles; total distance travelled from initial start = 12+8 = 20 Miles

Relative distance between Jacob & John = 10 Miles

Refer diagram below:

Attachment:

meet.png [ 3.37 KiB | Viewed 11164 times ]
Time taken by John to reach the meeting point would be same as time taken by Jacod

Setting up the equation

\(\frac{10+x}{15} = \frac{x}{12}\)

x = 40

Total catch up time taken \(= \frac{10+40}{15} = \frac{31}{3} Hrs\)

Answer = B

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