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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as

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Bunuel
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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   03 Jan 2016, 12:42
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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s
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E
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   06 Jan 2016, 03:02
let james and shiela have j and e pairs of shoes
as per the question
s=e/3 --> e=3s
s=2j
total number of pairs =s+3s+(s/2)=9s/2
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   07 Jan 2016, 02:08
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Bunuel wrote:
John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s



Shoes with John = s
Shoes with Shiela = 3s
Shoels with James = s/2

Total shoes = s + 3s + s/2 = 9s/2
Option E
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   07 Sep 2016, 08:27
Bunuel wrote:
John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s



oh, the wording is kind of confusing...s for john, then we have Sheila, which forces us to use different letter and confuse us a little bit... :-)
so...John has S
sheila has 3 times as many as john, thus 3S
James has half of what has John..so 0.5S
total: 3+1+0.5S or 4.5S
this is equal to 9/2 S

E
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   07 Sep 2016, 08:33
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mvictor wrote:
Bunuel wrote:
John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s



oh, the wording is kind of confusing...s for john, then we have Sheila, which forces us to use different letter and confuse us a little bit... :-)
so...John has S
sheila has 3 times as many as john, thus 3S
James has half of what has John..so 0.5S
total: 3+1+0.5S or 4.5S
this is equal to 9/2 S

E


A tip: If you feel that you *need* to use more than one variable to solve a question, read the question till the end before starting with equations. Usually, you will get enough data to stick to a single variable.
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   07 Sep 2016, 23:10
John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s

== s +3s + s/2 ==> 4s + 1/2 s = 9/2*s

Ans .E
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   08 Sep 2016, 01:17
john = s
shiela = 1/3(shiela) = s => 3s
james = 2(james) =s => (1/2)s
total = s+3s+(1/2)s = (9/2)s

E
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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   08 Dec 2018, 10:42
s = john , X = Shiela, & Y = James
s = (1/3) X -> x = s * 3, to get rid of the (1/3)
s = 2Y -> y = s/2 of (1/2)S

question is what is x + y + X -> s + 3s + s /2

4s + (1/2)s

(8/8)s + (1/2)s = (9/2)s
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink] New post   02 Nov 2022, 09:54
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as [#permalink]
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