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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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03 Jan 2016, 12:42
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83% (00:47) correct 17% (01:05) wrong based on 107 sessions
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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06 Jan 2016, 03:02
let james and shiela have j and e pairs of shoes as per the question s=e/3 > e=3s s=2j total number of pairs =s+3s+(s/2)=9s/2



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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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07 Jan 2016, 02:08
Bunuel wrote: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?
A. 7/3*s B. 10/3*s C. 7/2*s D. 4s E. 9/2*s Shoes with John = s Shoes with Shiela = 3s Shoels with James = s/2 Total shoes = s + 3s + s/2 = 9s/2 Option E



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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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07 Sep 2016, 08:27
Bunuel wrote: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?
A. 7/3*s B. 10/3*s C. 7/2*s D. 4s E. 9/2*s oh, the wording is kind of confusing...s for john, then we have Sheila, which forces us to use different letter and confuse us a little bit... so...John has S sheila has 3 times as many as john, thus 3S James has half of what has John..so 0.5S total: 3+1+0.5S or 4.5S this is equal to 9/2 S E



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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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07 Sep 2016, 08:33
mvictor wrote: Bunuel wrote: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?
A. 7/3*s B. 10/3*s C. 7/2*s D. 4s E. 9/2*s oh, the wording is kind of confusing...s for john, then we have Sheila, which forces us to use different letter and confuse us a little bit... so...John has S sheila has 3 times as many as john, thus 3S James has half of what has John..so 0.5S total: 3+1+0.5S or 4.5S this is equal to 9/2 S E A tip: If you feel that you *need* to use more than one variable to solve a question, read the question till the end before starting with equations. Usually, you will get enough data to stick to a single variable.
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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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07 Sep 2016, 23:10
John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?
A. 7/3*s B. 10/3*s C. 7/2*s D. 4s E. 9/2*s
== s +3s + s/2 ==> 4s + 1/2 s = 9/2*s
Ans .E



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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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08 Sep 2016, 01:17
john = s shiela = 1/3(shiela) = s => 3s james = 2(james) =s => (1/2)s total = s+3s+(1/2)s = (9/2)s
E



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Re: John has s pairs of shoes, which is 1/3 as many as Shiela and twice as
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23 Dec 2017, 03:46
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