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IMO: D

step 1 - find total time taken by john to reach "B" = (distance1/average speed1)+(distance2/average speed2) =2.7Hr = 14Hr 44 min
step 2 - find the time taken by JIM to reach "B" = 12:20 - 14:44 = 2:24
Step 3 - average speed of JIM = total distance / total time = 120 /(2:24) = 50mph

note - convert 2:24 into hour unit
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Not an overly difficult question, but it is time consuming. It's all about setting up the equations.

John's average speed is 50 mph over the first 60 miles and 40mph over the last 60:
Avg1 = 60/t1
50 = 60/t1
t1 = 6/5 h

Avg2 = 60/t2
40 = 60/t2
t2 = 3/2 h

Therefore, the total number of hours spent traveling is 6/5 + 3/2 = 2 and 7/10 of an hour. This means he reached his destination at 2:44 pm.

Since Jim left 18 minutes later at 12:20 pm, that means he has 2 hours and 24 minutes to travel 120 miles

AvgJim = 120/2.4h = 50mph
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understanding and solving this question took me long time, especially, took time to find out the time required for Jim...what is the score level of this question (i think it deserve to be at 700 level. any thoughts?
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Bunuel
John leaves Town A. at 12:02 PM and drives to Town B. a distance of 120 miles. His average speed for the first 60 miles was 50 mph and for the final 60 miles it was 40 mph. Jim leaves Town A. at 12:20 PM and also drives to Town B. What must Jim's average speed be in order to arrive at Town B at the same time that John arrives?

A. 35 mph
B. 40 mph
C. 45 mph
D. 50 mph
E. 85 mph


Are You Up For the Challenge: 700 Level Questions
 
Since distance travelled at two speeds by John is the same, his avg speed will be given by:

Average speed of John = 2ab/(a + b) = 2*50*40/(50 + 40) = 400/9 mph

Time taken by John = 120/(400/9) = 2.7 hrs = 2 hrs 42 mins

Jim starts 18 mins late so needs to complete the same distance in 2 hrs 24 mins = 2.4 hrs

Avg speed of Jim = 120/2.4 = 50 mph

Check:
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2015/0 ... -the-gmat/­
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Hi VeritasKarishma and Bunuel

Greetings of the day.

I have tried to solve this problem but was unable to do so. Then I checked for the available solutions and I found the proper solution. But what I want to ask is, can we solve this problem with Relative speed concept as I was trying this via it and did not get the correct answer. As per my opinion, we can apply that concept in this problem, however, I am not sure where I am going wrong.

Hence, I would request you guys to confirm me whether we can apply Relative speed concept in this problem or not and if yes, then kindly provide solution also, so i can check where i am going wrong.

Many Thanks in advance.
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RahulHGGmat
Hi VeritasKarishma and Bunuel

Greetings of the day.

I have tried to solve this problem but was unable to do so. Then I checked for the available solutions and I found the proper solution. But what I want to ask is, can we solve this problem with Relative speed concept as I was trying this via it and did not get the correct answer. As per my opinion, we can apply that concept in this problem, however, I am not sure where I am going wrong.

Hence, I would request you guys to confirm me whether we can apply Relative speed concept in this problem or not and if yes, then kindly provide solution also, so i can check where i am going wrong.

Many Thanks in advance.

John drives at different speeds so using relative speed here will be unnecessarily complicated. It will add no value and we will still need to do everything we are doing right now.
It is a simple average speed question. They both drive independently without reference to the other. We can get the time when John reaches and we need to make Jim reach at the same time so we have distance to be covered and time to be taken. We can easily find his speed.
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