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Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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03 Nov 2012, 22:23
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69% (01:16) correct 31% (01:08) wrong based on 312 sessions
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Julie opened a lemonade stand and sold lemonade in two different sizes, a 52cent (12oz) and a 58cent (16oz) size. How many 52cent (12oz) lemonade drinks did Julie sell? (1) Julie sold a total of 9 lemonades (2) The total value of the lemonade drinks Julie sold was $4.92
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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03 Nov 2012, 22:37
tim415 wrote: Julie opened a lemonade stand and sold lemonade in two different sizes, a 52cent (12oz) and a 58cent (16oz) size. How many 52cent (12oz) lemonade drinks did Julie sell?
(1) Julie sold a total of 9 lemonades (2) The total value of the lemonade drinks Julie sold was $4.92 Cost of 12 oz drink =52 cents, lets assumte total number sold are N Cost of 16 oz drink =58 cents, lets assumte total number sold are M Statement 1: N+M =9 So it could be that N=1, M=8 or that N=2, M=7 etc. Clearly not sufficient. Statement 2: N*0.52 + M*0.58 = 4.92 Or to simplify it: N*52 + M*58 = 492 N*26 + M*29 = 246 M*29 = 246N*26 This is true only for one value of M and N, when M=4 and N=5. (Assuming number of drinks to be only integers and hoping Julie's stand is not a unique stand that sells 0.732, 0.981 drinks ) Hence sufficient to answer. Ans B it is.
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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03 Nov 2012, 23:09
Vips0000 wrote: M*29 = 246N*26 This is true only for one value of M and N, when M=4 and N=5. (Assuming number of drinks to be only integers and hoping Julie's stand is not a unique stand that sells 0.732, 0.981 drinks ) Thanks! Hmm.. I think I'm missing something pretty obvious here, how do you conclude that there is only one value for M and N and that it has to be M=4, N=5? When I look at the equation I see 1 equation and 2 unknowns so my knee jerk reaction is "not solvable!!"



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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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03 Nov 2012, 23:15
tim415 wrote: Vips0000 wrote: M*29 = 246N*26 This is true only for one value of M and N, when M=4 and N=5. (Assuming number of drinks to be only integers and hoping Julie's stand is not a unique stand that sells 0.732, 0.981 drinks ) Thanks! Hmm.. I think I'm missing something pretty obvious here, how do you conclude that there is only one value for M and N and that it has to be M=4, N=5? When I look at the equation I see 1 equation and 2 unknowns so my knee jerk reaction is "not solvable!!" Well, when question or context gives you certain constraints to help you. (Or actually to trick you ) If we dont know that number of drinks got to be a nonnegative integer then surely we can not solve 1 equation with 2 variables. But in this case that is one underlying constraint. So we can simply check if there is anything that satisifies the equation. Remember this trick for any such context (Number of drinks/ animals/ trees/ votes/ persons etc) Hope it helps
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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06 Nov 2012, 05:16



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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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15 Jul 2013, 20:36
Vips0000 wrote: tim415 wrote: Vips0000 wrote: M*29 = 246N*26 This is true only for one value of M and N, when M=4 and N=5. (Assuming number of drinks to be only integers and hoping Julie's stand is not a unique stand that sells 0.732, 0.981 drinks ) Thanks! Hmm.. I think I'm missing something pretty obvious here, how do you conclude that there is only one value for M and N and that it has to be M=4, N=5? When I look at the equation I see 1 equation and 2 unknowns so my knee jerk reaction is "not solvable!!" Well, when question or context gives you certain constraints to help you. (Or actually to trick you ) If we dont know that number of drinks got to be a nonnegative integer then surely we can not solve 1 equation with 2 variables. But in this case that is one underlying constraint. So we can simply check if there is anything that satisifies the equation. Remember this trick for any such context (Number of drinks/ animals/ trees/ votes/ persons etc) Hope it helps Can you please explain the statement again ? I got the answer choice wrong. "If we dont know that number of drinks got to be a nonnegative integer then surely we can not solve 1 equation with 2 variables. But in this case that is one underlying constraint. So we can simply check if there is anything that satisifies the equation."
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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15 Jul 2013, 22:41
hb wrote: Vips0000 wrote: tim415 wrote: Thanks! Hmm.. I think I'm missing something pretty obvious here, how do you conclude that there is only one value for M and N and that it has to be M=4, N=5? When I look at the equation I see 1 equation and 2 unknowns so my knee jerk reaction is "not solvable!!" Well, when question or context gives you certain constraints to help you. (Or actually to trick you ) If we dont know that number of drinks got to be a nonnegative integer then surely we can not solve 1 equation with 2 variables. But in this case that is one underlying constraint. So we can simply check if there is anything that satisifies the equation. Remember this trick for any such context (Number of drinks/ animals/ trees/ votes/ persons etc) Hope it helps Can you please explain the statement again ? I got the answer choice wrong. "If we dont know that number of drinks got to be a nonnegative integer then surely we can not solve 1 equation with 2 variables. But in this case that is one underlying constraint. So we can simply check if there is anything that satisifies the equation." Check these posts: joannaboughtonly015stampsand029stampshowmany101743.htmlcommongmattrap31x25y128578.htmljoeboughtonlytwentycentstampsandthirtycentstamps106212.htmlacertainfruitstandsoldapplesfor070eachandbananas101966.htmleunicesoldseveralcakesifeachcakesoldforeither109602.htmlmarthaboughtseveralpencilsifeachpencilwaseithera100204.htmlarentalcaragencypurchasesfleetvehiclesintwosizesa105682.htmlHope it helps.
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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04 Nov 2014, 22:17
This is Value type of DS questions in which we should answer if there is only one value or more than one value. If only one possible value  sufficient If more than one value  insufficient
We do not need to count this value as we do in PS
In this case we should answer if it is only one possible value of 52cent lemonade drinks' number
S1. x+y=9, can be 1+8, 2+7, 3+6, 4+5..., so INSUFFICIENT S2. 52x+58y=492, we have two different prices per drink, so there is always unique number of X (nonnegative integer), so SUFFICIENT
B



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Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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10 Jul 2015, 09:30
Vips0000 wrote: tim415 wrote: Julie opened a lemonade stand and sold lemonade in two different sizes, a 52cent (12oz) and a 58cent (16oz) size. How many 52cent (12oz) lemonade drinks did Julie sell?
(1) Julie sold a total of 9 lemonades (2) The total value of the lemonade drinks Julie sold was $4.92 Cost of 12 oz drink =52 cents, lets assumte total number sold are N Cost of 16 oz drink =58 cents, lets assumte total number sold are M Statement 1: N+M =9 So it could be that N=1, M=8 or that N=2, M=7 etc. Clearly not sufficient. Statement 2: N*0.52 + M*0.58 = 4.92 Or to simplify it: N*52 + M*58 = 492 N*26 + M*29 = 246 M*29 = 246N*26 This is true only for one value of M and N, when M=4 and N=5. (Assuming number of drinks to be only integers and hoping Julie's stand is not a unique stand that sells 0.732, 0.981 drinks ) Hence sufficient to answer. Ans B it is. It took a lot of time for me to arrive at the values. I agree this is a DS question and solving till the last line is not required as in case of PS. but still the equation looks quite complex that I felt it may not have a solution at all. Is there is any way to solve the equation in less time.
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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10 Jul 2015, 14:35
Hi Mechmeera, In situations such as this (when you THINK that you need two variables and two unique equations to answer the given question), it helps to be on the lookout for "weird" numbers and/or low "totals." You also have to be ready to do some 'brute force' work to get the solution. In this prompt, we're told that the two sizes cost 52 cents and 58 cents. Fact 2 tells us that the TOTAL value of glasses sold was $4.92. Since each size of lemonade sells for OVER 50 cents, and the total is LESS than $5, there must be FEWER than 10 lemonades sold  this leads to a relatively small number of possibilities. While the work might seem a little tedious, you CAN list out the various 'multiples' of each size and look for an option that totals $4.92 For the 12ounce lemonade: .52 1.04 1.56 2.08 2.60 3.12 3.64 4.16 4.68 For the 16ounce lemonade: .58 1.16 1.74 2.32 2.90 3.48 4.06 4.64 How many ways are there to add a number from the first group to the number from the second group and get a TOTAL of $4.92 (hint: the units digit is a '2', so look for a pair of values that SUM to that units digit). You'll find that there's just one pairing. Thus, Fact 2 is SUFFICIENT. GMAT assassins aren't born, they're made, Rich
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Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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25 Feb 2018, 06:40
VeritasPrepKarishma how to conclude that there is only one value for M and N for the equation M*29 = 246N*26 Please help.



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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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25 Feb 2018, 15:24
techiesam wrote: VeritasPrepKarishma how to conclude that there is only one value for M and N for the equation M*29 = 246N*26 Please help. Hi techiesam, If you read my explanation (the post that immediately appears before your post), you'll see that with a little logic  and some 'brute force' arithmetic  you can prove that there's only one solution when you include the information in Fact 2. GMAT assassins aren't born, they're made, Rich
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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25 Feb 2018, 22:03
EMPOWERgmatRichC wrote: techiesam wrote: VeritasPrepKarishma how to conclude that there is only one value for M and N for the equation M*29 = 246N*26 Please help. Hi techiesam, If you read my explanation (the post that immediately appears before your post), you'll see that with a little logic  and some 'brute force' arithmetic  you can prove that there's only one solution when you include the information in Fact 2. GMAT assassins aren't born, they're made, Rich Thanks..But the brute force method is time consuming,specially when you are taking the test.Is there any other way!



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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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25 Feb 2018, 22:24
techiesam wrote: VeritasPrepKarishma how to conclude that there is only one value for M and N for the equation M*29 = 246N*26 Please help. Check out this post: https://www.veritasprep.com/blog/2011/0 ... ofthumb/It discusses in detail how to solve equations with integer solutions and also how you can find out the exact number of solutions an equation such as this will have.
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Re: Julie opened a lemonade stand and sold lemonade in two diff [#permalink]
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25 Feb 2018, 22:32
VeritasPrepKarishma wrote: techiesam wrote: VeritasPrepKarishma how to conclude that there is only one value for M and N for the equation M*29 = 246N*26 Please help. Check out this post: https://www.veritasprep.com/blog/2011/0 ... ofthumb/It discusses in detail how to solve equations with integer solutions and also how you can find out the exact number of solutions an equation such as this will have. Thank you very much Ma'am.This is what I've been looking for.




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