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L spends total $6.00 for one kind of D and one kind of C. How many D d

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L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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New post 18 Nov 2011, 13:06
3
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

45% (02:36) correct 55% (01:51) wrong based on 121 sessions

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L spends total $6.00 for one kind of D and one kind of C. How many D did he buy?

(1) The price of 2D was $0.10 less than the price of 3C
(2) The average price of 1 D and 1 C was $0.35

Discussed here: at-the-bakery-lew-spent-a-total-of-6-for-one-kind-of-130748.html

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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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New post 19 Nov 2011, 04:18
2
1
D = price of one donut
C = price of one cupcake
x = number of donuts bought
y = number of cupcakes bought

xD + yC = $6.00

1) 2D = 3C - 0.10
We do not know x or y, NS

2) (D + C) / 2 = 0.35
Same problem, NS

1+2) We can solve for D and C, but we can't solve for the quantity of each that has been bought.

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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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New post 19 Nov 2011, 10:59
1
This problem doesn't make any sense because it says "$6.00 for one kind of D and one kind of C". Later on, it says that the average price of D and C is .35.
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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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New post 19 Nov 2011, 17:06
1
kostyan5 wrote:
This problem doesn't make any sense because it says "$6.00 for one kind of D and one kind of C". Later on, it says that the average price of D and C is .35.


Agree that the wording is deceiving, but have another read.

It says 'one kind' of donut. E.g. you buy five chocolate donuts, you have bought one kind of donut, even though you have bought five.

This is actually a GMATPrep problem.

The proper wording is "At the bakery, Lew spent a total of $6.00 for one kind of cupcake and one kind of doughnut. How many doughnuts did he buy?"

We never can answer a question from the stem along, hence if we read this to mean 'one' donut was bought (which directly answers the question), then we know we have made a mistake.
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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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New post 20 Nov 2011, 00:33
enigma123 wrote:
L spends total $6.00 for one kind of D and one kind of C. How many D did he buy?
(1) the price of 2D was $0.10 less than the price of 3C
(2) the average price of 1 D and 1 C was $0.35

Can someone please help? OA is not provided.


Price of one kind of D = D
Price of one kind of C = C

Number of D =x
Number of C=y

From stem we already know that

Dx + Cy = 6

We need to find x = ?

S1: 2D+0.10=3C no idea about x
S2: D+C= 2*0.35 no idea about x

Even if you combine S1 and S2, there won't be nay idea about x.

Thus answer should be "E"
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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d  [#permalink]

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Re: L spends total $6.00 for one kind of D and one kind of C. How many D d &nbs [#permalink] 15 Apr 2018, 00:17
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