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Line m and n pass through point (1,2). Is the slope of m

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Line m and n pass through point (1,2). Is the slope of m [#permalink]

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Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

(1) The x-intercept of m is greater than 1 and that of n is less than 1
(2) The y-intercept of m = 4 and that of n = (-2)
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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 Feb 2010, 00:42
line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1
m has negative slope as x intercept is greater than 1. take a point (2,0) and draw a line
n has positive slope. take a point (0,0) and draw a line
Sufficient

2.) the y-intercept of m = 4 and that of n = (-2)
m has negative slope
n has positive slope
sufficient

D

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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 Feb 2010, 01:00
(1.) IF two lines p and q have slopes (-3) and (-5) respectively then slope of which line is greater??


(2.) IF two lines a and b have slopes of (6) and (-4) respectively then the slope of which is greater??


Kindly elaborate on the rules regarding this :)


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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 Feb 2010, 01:57
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since you have problem with 1st statement.. I m considering that only as 2nd is sufficient.

Now take \(\frac{x}{a}+ \frac{y}{b}\) = 1 where a and b are intercepts on x and y axis and slope is -b/a
since this line passes through 1,2

we get 1/a + 2/b = 1

=> b/a = b-2 => slope = \(\frac{-b}{a}\) = 2-b that means we need b value to get the ans...

now....b/a = b-2 => a = \(\frac{b}{b-2}\)

for m a>1 and for n a< 1

b/b-2 >1 and b/b-2 <1
=> this will come when \(\frac{b}{b-2}\) - 1 > 0 and \(\frac{b}{b-2}\)- 1 < 0
=> 2/b-2 > 0 or 2/b-2 < 0

Thus for m b>2 and for n b< 2
since slope was 2-b thus sufficient.
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Re: Co-Ordinate Geometry!! [#permalink]

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apoorvasrivastva wrote:
line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1
2.) the y-intercept of m = 4 and that of n = (-2)



D...

Best is to draw graphically.
S1: gives u a range for x intercept. But since you have (1,2) fixed, you would see.. Line m has a -ve slope (in the given range) and Line n has a positive slope. Hence SUFF.

S2: Makes it much more clear by giving u two other points. Hence SUFF.
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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 May 2010, 06:51
Which each statment you can know that one slope is positive (n) and the other one is negative (m).
So one positive number is greater than a negative one = SUF
I hope it helps

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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 May 2010, 16:49
line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1
2.) the y-intercept of m = 4 and that of n = (-2)


Aren't we missing something ?

To compare the slope of two lines m and n in the context of the probelm, we must not consider the sign of the slope.
Question says which slope is greater. By definition a slope indicates how stiff the line is, other way to say, how difficult it is to walk on the line.
A slope is measured by (change in Y) / (change is X). A greater change in Y and lesser change in X give stiffer slope.
Therefore, even a negative slope can be stiffer than a positive slope. It just happens that a negative slope is in other direction.

To answer the question, I think we need actual value of the slope of two lines, which can be derived from statement 2.

Answer is B.

What is the rule GMAT follow to compare the slope of two lines ?
Does the GMAT compare actual value of the slope or absolute value of the slope ?
In my understanding, it is absolute value . However , we must follow whatever GMAT follows.

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Re: Co-Ordinate Geometry!! [#permalink]

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New post 21 May 2010, 17:11
You can take a look at http://en.wikipedia.org/wiki/Slope for definition of slope.

slope = tan (angle) = dy/dx - so slope could be negative and small positive slope is higher than any negative slope.
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clarification request to Bunuel.... [#permalink]

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New post 28 Apr 2012, 15:56
Dear Bunuel,
Can you please explain to me that if the question asks to compare the slope, are we suppose to consider the absolute value of slope of the real value? I have seen in the previous examples, you considering the absolute value and in this example, they have compared the real value . It seems inconsistent.
Thanks

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Re: clarification request to Bunuel.... [#permalink]

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Parthomazumdar wrote:
Dear Bunuel,
Can you please explain to me that if the question asks to compare the slope, are we suppose to consider the absolute value of slope of the real value? I have seen in the previous examples, you considering the absolute value and in this example, they have compared the real value . It seems inconsistent.
Thanks


The question asks: "Is the slope of m greater than the slope of n?" So, we should NOT compare the absolute value of the slopes.

Notice that a higher absolute value of a slope indicates a steeper incline. So:

If the slopes of lines k and l are positive and line k is steeper then it will have the greater slope.
If the slopes of lines k and l are negative and line k is steeper then its slope is more negative then the slope of line l (the absolute value of k's slope is greater), which means that the slope of l is greater than the slope of k.

Check the following questions to practice:
if-the-slopes-of-the-line-l1-and-l2-are-of-the-same-sign-is-126759.html
lines-n-and-p-lie-in-the-xy-plane-is-the-slope-of-line-n-127999.html
in-the-xy-plane-is-the-slope-of-line-l-greater-than-the-126941.html
if-the-slopes-of-the-line-l1-and-l2-are-of-the-same-sign-is-126759.html
slopes-of-m-and-n-124025.html
lines-n-and-p-lie-in-the-xy-plane-is-the-slope-of-the-line-30553.html
lines-n-and-p-lie-in-the-xy-plane-is-the-slope-of-line-n-97007.html

Hope it helps.
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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Equation for Line m
y = mx + b

Equation for Line n

y = nx + b

Question: is m > n?


(1)
X-intercept of Line m > 1
X-intercept of Line n < 1

Solve for X-intercept of Line m
y = mx + b
(0) = mx + b
mx = - b
x = \(\frac{-b}{m}\)

x > 1
\(\frac{-b}{m}\) > 1
\(\frac{-b}{1}\) > m

Solve for X-intercept of Line y
y = nx + b
(0) = nx + b
nx = -b
x = \(\frac{-b}{n}\)

x < 1
\(\frac{-b}{n}\) < 1
\(\frac{-b}{1}\) < n

m < \(\frac{-b}{1}\) < n
Therefore, (1) is sufficient


(2)
Y-intercept of Line m = 4
Y-intercept of Line n = -2

Solve for m
y = mx + b
(2) = (1)m + 4
m = -2

Solve for n
y = nx + b
(2) = (1)n -2
n = 4

n > m
Therefore, (2) is sufficient

Answer: D

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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 21 Jun 2012, 07:55
With condition 1, when we try to solve algebraic way:

x intercept of line m : -b1/m1>1
and for line b : -b2/m2<1

Given that we do not the sign of slopes m1 and m2, we cant cross multiply, then how do we proceed after this condition?

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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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pavanpuneet wrote:
With condition 1, when we try to solve algebraic way:

x intercept of line m : -b1/m1>1
and for line b : -b2/m2<1

Given that we do not the sign of slopes m1 and m2, we cant cross multiply, then how do we proceed after this condition?


ALGEBRAIC APPROACH.

Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

Given: lines \(y_m=mx+b\) and \(y_n=nx+c\) pass through point (1,2). Hence: \(2=m+b\) and \(2=n+c\).
Question asks: is \(m>n\)?

(1) The x-intercept of m is greater than 1 and that of n is less than 1. The x-intercept is the value of \(x\) when \(y=0\), so from this statement we have that:

\(-\frac{b}{m}>1\). Now, since from the stem \(b=2-m\), then \(-\frac{2-m}{m}>1\) --> \(\frac{m-2}{m}>1\) --> \(\frac{m}{m}-\frac{2}{m}>1\) --> \(1-\frac{2}{m}>1\) --> \(\frac{2}{m}<0\) --> \(m<0\);

\(-\frac{c}{n}<1\). Now, since from the stem \(c=2-n\), then \(-\frac{2-n}{n}<1\) --> \(\frac{n-2}{n}<1\) --> \(\frac{n}{n}-\frac{2}{n}<1\) --> \(1-\frac{2}{n}<1\) --> \(\frac{2}{m}>0\) --> \(n>0\);

So, we have that \(m<0<n\). Sufficient.

(2) The y-intercept of m = 4 and that of n = (-2). The y-intercept is the value of \(y\) for \(x=0\), so from this statement we have that:

\(b=4\). Now, since from the stem \(b=2-m\), then \(4=2-m\) --> \(m=-2\);
\(c=-2\). Now, since from the stem \(c=2-n\), then \(-2=2-n\) --> \(n=4\);

So, we have that \(m=-2<4=n\). Sufficient.

Answer: D.

Hope it's clear.
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 23 Jan 2014, 14:56
Bunuel wrote:
pavanpuneet wrote:
With condition 1, when we try to solve algebraic way:

x intercept of line m : -b1/m1>1
and for line b : -b2/m2<1

Given that we do not the sign of slopes m1 and m2, we cant cross multiply, then how do we proceed after this condition?


ALGEBRAIC APPROACH.

Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

Given: lines \(y_m=mx+b\) and \(y_n=nx+c\) pass through point (1,2). Hence: \(2=m+b\) and \(2=n+c\).
Question asks: is \(m>n\)?

(1) The x-intercept of m is greater than 1 and that of n is less than 1. The x-intercept is the value of \(x\) when \(y=0\), so from this statement we have that:

\(-\frac{b}{m}>1\). Now, since from the stem \(b=2-m\), then \(-\frac{2-m}{m}>1\) --> \(\frac{m-2}{m}>1\) --> \(\frac{m}{m}-\frac{2}{m}>1\) --> \(1-\frac{2}{m}>1\) --> \(\frac{2}{m}<0\) --> \(m<0\);

\(-\frac{c}{n}<1\). Now, since from the stem \(c=2-n\), then \(-\frac{2-n}{n}<1\) --> \(\frac{n-2}{n}<1\) --> \(\frac{n}{n}-\frac{2}{n}<1\) --> \(1-\frac{2}{n}<1\) --> \(\frac{2}{m}>0\) --> \(n>0\);

So, we have that \(m<0<n\). Sufficient.

(2) The y-intercept of m = 4 and that of n = (-2). The y-intercept is the value of \(y\) for \(x=0\), so from this statement we have that:

\(b=4\). Now, since from the stem \(b=2-m\), then \(4=2-m\) --> \(m=-2\);
\(c=-2\). Now, since from the stem \(c=2-n\), then \(-2=2-n\) --> \(n=4\);

So, we have that \(m=-2<4=n\). Sufficient.

Answer: D.

Hope it's clear.


Hi Bunel I shall try to give a easier approach.
If a line's X intercept is ''a'' what information we get from that . Line pasess through point (a,0)
similarly if a line's Y intercept is "b" what information we get from that . Line pasess through point (0,b)
and if a line pasess through points (x1,y1)and (x2,y2) we compute the slope of the line by (y2-y1)/x2-x1).
so let us apply this to the present question
Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?
1.The x-intercept of m is greater than 1 and that of n is less than 1
so x intercept of m is greater than 1 so it should pass through points (>1,0) so let us assume its (2,0)
x intercept of n is less than 1 so it should pass through points (<1,0) so let us assume its (-1,0) you can actually take any point less than 1 even (0.9,0) also.
so now computing slope with slope formula you can find slope of n > slope of m hence sufficient.
2.The y-intercept of m = 4 and that of n = (-2)
i.e. m pasess through point (0,4) and n pasess through point (0,-2)
and you can straight away compute the slope and determine which is greater
IMP: It is important to understand what is meant by intercept
hope this helps
This would avoid the larger equations.
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 08 Dec 2015, 18:44
I solved it easily by picturing the lines in the graph.
1 - if x intercept of m is greater then 1, we can automatically deduct that line m has a negative slope. we are also told that x intercept of line n is less than 1, which only gives 1 possibility - slope of line n is positive. thus, this is sufficient to answer the question.

2. we are told that y-intercept of line m is 4, which is above the point of intersection. the only case when this is possible is when slope of m is negative. we are also told the y-intercept of line n, which is -2. since the point of intersection is above, it clearly means that the slope is positive. sufficient to answer the question.

another method is finding the slope of one line, then finding the slope of another line. Both statements, individually, are sufficient to do so, since for each line we have 2 points, which is enough to find the slope.

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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 17 Dec 2015, 11:31
Slope is defined as rise by run. From the question we know a point on the line. From the intercepts we can detect which has a higher rise and run. Each Statement alone is sufficient

Hence, D.
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 27 Jul 2016, 05:20
honsmos wrote:
Equation for Line m
y = mx + b

Equation for Line n

y = nx + b

Question: is m > n?


(1)
X-intercept of Line m > 1
X-intercept of Line n < 1

Solve for X-intercept of Line m
y = mx + b
(0) = mx + b
mx = - b
x = \(\frac{-b}{m}\)

x > 1
\(\frac{-b}{m}\) > 1
\(\frac{-b}{1}\) > m

Solve for X-intercept of Line y
y = nx + b
(0) = nx + b
nx = -b
x = \(\frac{-b}{n}\)

x < 1
\(\frac{-b}{n}\) < 1
\(\frac{-b}{1}\) < n

m < \(\frac{-b}{1}\) < n
Therefore, (1) is sufficient


(2)
Y-intercept of Line m = 4
Y-intercept of Line n = -2

Solve for m
y = mx + b
(2) = (1)m + 4
m = -2

Solve for n
y = nx + b
(2) = (1)n -2
n = 4

n > m
Therefore, (2) is sufficient

Answer: D



why is the y intercept for both lines m and n takes as "b" ? Should it not be "b1" and "b2" ?
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 27 Jul 2016, 05:22
Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

(1) The x-intercept of m is greater than 1 and that of n is less than 1
(2) The y-intercept of m = 4 and that of n = (-2)


1(m1 - m2) = c2 - c1

B) is suff

A) x1 = -c1/m1

-c1/m1 > 1

2 = 1m1 + c1
c1 = 2 - m1

(m1 - 2)/m1 > 1

1 - 2/m1 > 1
1/m1 < 0 ————> 1 therefore m1 is -ve

similarly since :

-c2/m2 < 1

1/m2 > 0 therefore m2 is +ve (A) is sufficient too

ans is (D)
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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 27 Jul 2016, 08:15
apoorvasrivastva wrote:
Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

(1) The x-intercept of m is greater than 1 and that of n is less than 1
(2) The y-intercept of m = 4 and that of n = (-2)


We already know one point per line, we need a second point, then a gradient can be determined.

1) We are given an inequality for the first point of the line in which neither of the lines will share a point. Sufficient

2) We are given one additional point per line. Sufficient.

[Reveal] Spoiler:
(D) each statement alone is sufficient

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Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]

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New post 06 Oct 2016, 02:39
apoorvasrivastva wrote:
Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

(1) The x-intercept of m is greater than 1 and that of n is less than 1
(2) The y-intercept of m = 4 and that of n = (-2)


FROM STEM

2=m+b , 2=n+c and thus m = 2-b and n= 2-c thus question asks whether 2-b> 2-c or whether c>b ( i.e. y intercepts ) , my interpretation to this is that the slopes are dependent on the y-intercepts and i went for B

Bunuel, if you plz where am i going wrong?

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Re: Line m and n pass through point (1,2). Is the slope of m   [#permalink] 06 Oct 2016, 02:39

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