Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Mar 2408:30 AM PDT
-09:30 AM PDT
Join 99th percentile Manhattan Prep Instructor, Ryan Starr, for the third session in our three-part series on how to maximize your study effectiveness. The new GMAT tests comprehension, analysis, and logic, and more.
Mar 1910:00 AM EDT
-11:59 PM EDT
Get a massive $250 off the TTP OnDemand GMAT course by using the coupon code FLASH25 at checkout. If you prefer learning through engaging video lessons, TTP OnDemand GMAT is exactly what you need.
Mar 2305:30 AM PDT
-07:30 AM PDT
Achieving a high GMAT score while balancing a hectic work life is challenging, but with the right strategy, it's absolutely possible. Discover the ultimate GMAT study strategy designed exclusively for working professionals...- Mar 25
11:00 AM PDT
-12:00 PM PDT
Dreaming about studying abroad but worried about finances? In this video, we provide overview of HDFC Credila's education loan offerings and insights into securing an education loan effortlessly. 
Mar 2610:00 AM EDT
-11:59 PM EDT
The Target Test Prep GMAT Flash Sale is LIVE! Get 25% off our game-changing course and save up to $400 today! Use code FLASH25 at checkout. This limited-time deal won’t last long, so grab your discount now!- Mar 26
10:00 AM PDT
-11:00 AM PDT
Confused about how to get the most from your GMAT mock tests? In this video, learn the perfect strategy to analyze GMAT mocks effectively and boost your score. We break down the common mistakes GMAT aspirants make when using mock tests - Mar 27
09:30 AM PDT
-10:30 AM PDT
Preparing for the GMAT? Avoid these 5 major mistakes that can lower your score and hurt your MBA dreams. In this expert panel discussion, 4 top GMAT coaches - GMAT Ninja, Jeff Miller from TTP, Rida Shafiq from eGMAT, and Chris Gentry from Manhattan Prep - Mar 27
10:00 AM PDT
-11:00 AM PDT
What happens after getting an MBA? Is it worth the investment? To find out, I interviewed 10 GMAT Club professionals who have completed their MBAs and built careers in consulting, finance, tech, and entrepreneurship. Their answers might surprise you! 
Mar 3011:00 AM IST
-01:00 PM IST
Attend this session to evaluate your current skill level, learn process skills, and solve through tough Arithmetic questions.
16 Sep 2014, 00:17
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
50% (02:26) correct
50%
(02:36)
wrong
based on 938
sessions
History
Date
Time
Result
Not Attempted Yet
Andy, George, and Sally are a team of consultants working on Project Alpha. They have an eight-hour deadline to complete the project. The team members work at constant rates throughout the eight-hour period. If the team of three has to start work immediately and no one else can work on this project, will Project Alpha be completed by the deadline?
(1) Sally can finish the project alone in \(4k+7\) hours, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
(2) Working alone, George will take \(2k+1\) hours, and Andy will take \(3+2k\) hours to complete the project, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
(1) Sally can finish the project alone in \(4k+7\) hours, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
(2) Working alone, George will take \(2k+1\) hours, and Andy will take \(3+2k\) hours to complete the project, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
16 Sep 2014, 00:17
Kudos
Bookmarks
Official Solution:
Andy, George, and Sally are a team of consultants working on Project Alpha. They have an eight-hour deadline to complete the project. The team members work at constant rates throughout the eight-hour period. If the team of three has to start work immediately and no one else can work on this project, will Project Alpha be completed by the deadline?
(1) Sally can finish the project alone in \(4k+7\) hours, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
We know Sally can finish the project in \(4k+7\) hours, but we know nothing about George's or Andy's time. If \(k = 5\), Sally can finish the work by herself in 27 hours. In this worst-case scenario, Sally alone cannot complete the project within the deadline, which means we need more information about George and Andy to determine if the team as a whole can complete the project within the deadline. Suppose Andy and George also need a considerable amount of time to finish the job by themselves, say 100 hours each. In that case, the team won't be able to complete the project by the deadline, as their combined rate of \(\frac{1}{27} + \frac{1}{100} +\frac{1}{100}\) job/hour would be less than the required rate of \(\frac{1}{8}\) job/hour. On the other hand, if Andy and George need a small amount of time to finish the job by themselves, say 1 hour each, then the team will be able to complete the project by the deadline. This is because their combined rate of \(\frac{1}{27} + \frac{1}{1} +\frac{1}{1}\) job/hour would be greater than the required rate of \(\frac{1}{8}\) job/hour. Not sufficient.
(2) Working alone, George will take \(2k+1\) hours, and Andy will take \(3+2k\) hours to complete the project, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
Let's check whether George and Andy can finish the project by themselves for the greatest possible value of \(k\). We do this because if they can finish the project by themselves for the greatest possible value of \(k\), it would mean that they don't even need Sally's input to complete the project. For the maximum value of \(k = 5\), George needs \(2k+1=11\) hours and Andy needs \(3+2k=13\) hours to finish the project alone. Their combined rate is \(\frac{1}{11} + \frac{1}{13}\) job/hour. Since this is more than the required rate of \(\frac{1}{8}\) job/hour (\(\frac{1}{11} + \frac{1}{13} > (\frac{1}{16} + \frac{1}{16}=\frac{1}{8})\) ), George and Andy can complete the job by themselves irrespective of Sally's rate. Sufficient.
Answer: B
Andy, George, and Sally are a team of consultants working on Project Alpha. They have an eight-hour deadline to complete the project. The team members work at constant rates throughout the eight-hour period. If the team of three has to start work immediately and no one else can work on this project, will Project Alpha be completed by the deadline?
(1) Sally can finish the project alone in \(4k+7\) hours, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
We know Sally can finish the project in \(4k+7\) hours, but we know nothing about George's or Andy's time. If \(k = 5\), Sally can finish the work by herself in 27 hours. In this worst-case scenario, Sally alone cannot complete the project within the deadline, which means we need more information about George and Andy to determine if the team as a whole can complete the project within the deadline. Suppose Andy and George also need a considerable amount of time to finish the job by themselves, say 100 hours each. In that case, the team won't be able to complete the project by the deadline, as their combined rate of \(\frac{1}{27} + \frac{1}{100} +\frac{1}{100}\) job/hour would be less than the required rate of \(\frac{1}{8}\) job/hour. On the other hand, if Andy and George need a small amount of time to finish the job by themselves, say 1 hour each, then the team will be able to complete the project by the deadline. This is because their combined rate of \(\frac{1}{27} + \frac{1}{1} +\frac{1}{1}\) job/hour would be greater than the required rate of \(\frac{1}{8}\) job/hour. Not sufficient.
(2) Working alone, George will take \(2k+1\) hours, and Andy will take \(3+2k\) hours to complete the project, where \(k\) is a positive integer ranging from 1 to 5, inclusive.
Let's check whether George and Andy can finish the project by themselves for the greatest possible value of \(k\). We do this because if they can finish the project by themselves for the greatest possible value of \(k\), it would mean that they don't even need Sally's input to complete the project. For the maximum value of \(k = 5\), George needs \(2k+1=11\) hours and Andy needs \(3+2k=13\) hours to finish the project alone. Their combined rate is \(\frac{1}{11} + \frac{1}{13}\) job/hour. Since this is more than the required rate of \(\frac{1}{8}\) job/hour (\(\frac{1}{11} + \frac{1}{13} > (\frac{1}{16} + \frac{1}{16}=\frac{1}{8})\) ), George and Andy can complete the job by themselves irrespective of Sally's rate. Sufficient.
Answer: B
General Discussion
FightToSurvive
Joined: 18 Sep 2014
Last visit: 15 Dec 2016
Posts: 198
Given Kudos: 5
Schools: ISB '18 (A) Fisher '19 (II) Smeal Penn State "19 (A$) Kelley '19 (S) Olin '19 (S) Simon '19 (A$) Broad '19 (S)
Products:
23 Mar 2015, 05:46
Kudos
Bookmarks
Deeuk,
Firstly consider the below cases:
1. say, k =5 (Maximum)
Then also, on further simplification, 1/11 + 1/13 > 1/8
2. say, k =1 (Minimum)
Then also, on further simplification, 1/3 + 1/5 > 1/8
Both cases, its sufficient to decipher that both person sufficient to do alpha within the schedule of 8 hours. Hence B is the answer to the said question.
Yes, coming to your question, yes if we could find different solution to both cases, then we would have to consider the first option, then in that case, C would have been the answer.
Hope its clear.
Firstly consider the below cases:
1. say, k =5 (Maximum)
Then also, on further simplification, 1/11 + 1/13 > 1/8
2. say, k =1 (Minimum)
Then also, on further simplification, 1/3 + 1/5 > 1/8
Both cases, its sufficient to decipher that both person sufficient to do alpha within the schedule of 8 hours. Hence B is the answer to the said question.
Yes, coming to your question, yes if we could find different solution to both cases, then we would have to consider the first option, then in that case, C would have been the answer.
Hope its clear.
