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Bunuel
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Bunuel
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girishiyer
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girishiyer
Hi,

I got C.

Since we know :[A-B] <C<A+B

We can easily say its not an equilateral triangle

pls brunei can you specify

How?

Case 1: all sides are of lengths 1.
Case 2: sides are: 0.9, 1, 1.1.
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thanks bunuel for clarifying
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Bunuel
Is triangle \(ABC\) equilateral?


(1) \(AB = 1\)

(2) \(BC + AC = 2\)

For first few seconds, I was thinking where is the image. lol

Coming to the question, we can see that either the answer is C or E and that basically means one thing : Prove with one case that it is incorrect and you're good to go.

Combined :

AB=1 Assume BC and AC can only be nice sweet integers 1 and 1 the answer is Yes. It is an Eq Triangle.
But if AB=1 BC=0.5 AC=1.5. well it is not possible because AB+BC is not greater than AC and that means it is not a triangle in the first place.
But we can go further than that.
AB=1 BC=0.8 AC=1.2. It is a triangle but not equilateral.

We have enough information to declare E as the winner :)
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Bunuel
Is triangle \(ABC\) equilateral?
Quote:
(1) \(AB = 1\)
A. AB = 1 - Other sides BC, AC can be / cannot be equal to AB --> Not Sufficient
Quote:
(2) \(BC + AC = 2\)
B. BC+AC=2 - Other side AB can be / cannot be equal to each BC and AC --> Not Sufficient

C. We have AB = 1, BC+AC=2
Quote:
Case 1 - If, BC=AC=1 --> Yes - it is equilateral triangle
Quote:
Case 2 - If, BC=0.6 and AC=1.4
Lets check if this values meets the criteria of properties of Triangles -
1. Any side of triangle will always be less than the sum of other two sides
BC+AC>AB, AB+BC>AC, AC+AB>BC
2. Any side of triangle will always be greater than difference of the other two sides
AC-BC<AB, AC-AB<BC, AB-BC<AC

--> No - It is not an equilateral triangle

E is clearly the right answer. :)
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