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Kgmishra
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M03-32 20 Aug 2025, 11:55
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I like the solution - it’s helpful. We could also do a simple alligation 110 and 90 building a ratio of 3:1. only one option fits
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alrightalright
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M03-32 31 Aug 2025, 21:35
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I like the solution - it’s helpful.
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M03-32 12 Oct 2025, 08:55
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There is another method to solve this, and that is alligation


CarA CarB
+10% -10%
5%
----------------------------
15% : 5%
3 : 1

5% = 1000, Therefore cost price will be 20,000

15000 and 5000 are the only two options solving upon which we can get the right answer as 1000 profit


Bunuel
A car dealership sold two cars: Car A at a 10% profit and Car B at a 10% loss, resulting into an overall profit of 5% from the two sales. If the dealership's profit from these two cars was $1,000, what was the initial cost of cars A and B?

A. $5,000 and $1,000
B. $9,000 and $5,000
C. $11,000 and $9,000
D. $15,000 and $5,000
E. $20,000 and $10,000
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M03-32 30 Oct 2025, 21:15
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I like the solution - it’s helpful.
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M03-32 16 Nov 2025, 01:54
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I like the solution - it’s helpful.
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M03-32 08 Dec 2025, 12:23
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you don't also need the figure 1000
Let A's CP = 100a
and B's = 100b

10a - 10b= 5(a + b)
=> 5a = 15b
=> a/b = 15/5
You know which option to select
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M03-32 17 Jan 2026, 11:21
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I like the solution - it’s helpful.
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2kraj
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M03-32 20 Jan 2026, 10:21
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I like the solution - it’s helpful.
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M03-32 08 Feb 2026, 08:40
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Deconstructing the Question
Car A is sold at a 10% profit and Car B at a 10% loss.
The overall profit from both cars is 5%, equal to $1000.
We are asked to find the original costs of Cars A and B.

Step-by-step
Let the cost of Car A be x and the cost of Car B be y.

Profit from Car A:
\(0.1x\)

Loss from Car B:
\(-0.1y\)

Total profit:
\(0.1x - 0.1y = 1000\)
\(x - y = 10000\)

Overall profit is 5% of total cost:
\(0.05(x + y) = 1000\)
\(x + y = 20000\)

Solve the system:
\(x = 15000\)
\(y = 5000\)

Answer: $15,000 and $5,000 (D)
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