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Bunuel
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Bunuel
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Tsuruga
Hi Bunuel,

I am having trouble understanding this problem visually. Based on the solution, I can see we calculated the distance that the "wheel" travel. However, we want to calculate the distance that the car travel. Are they the same? I draw out how the wheel rotate on paper and having trouble to think of these two distances are the same. Could you help me clear this out?

I thinks similar problems might help:
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a-point-on-the-edge-of-a-fan-blade-that-is-rotating-in-a-plane-is-65505.html
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I think this is a high-quality question and I agree with explanation.
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KarishmaB i solved it like this

Circumference of wheel 2piR = 2*10 =20

75000/20 = 3750 inches

1 inch = 0.025
3750 =x meters

x = 94 meters convert to km very small speed :)

Any idea where i went wrong
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KarishmaB i solved it like this

Circumference of wheel 2piR = 2*10 =20

75000/20 = 3750 inches

1 inch = 0.025
3750 =x meters

x = 94 meters convert to km very small speed :)

Any idea where i went wrong

What does circumference of the wheel give you? It gives you the straight line distance the wheel covers in one complete revolution.
So how do we find the distance covered by the wheels and hence the whole car in 75000 revolutions? We multiply it by the distance covered in one revolution

\(Distance = 20\pi * 75000 inches\)

In km, distance covered \(= 20*(\frac{22}{7}) * 75000 * \frac{0.0254}{1000 } = 120 km\)

Speed = 120/2 = 60 mph

Answer (C)

Depending on what value you take of pi, the approximation will vary a bit. Though this looks like a question from an exam in which the calculator is allowed.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I agree with explanation.
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I like the solution - it’s helpful.
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