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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 05 Jun 2015, 06:10
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 05 Jun 2015, 07:38
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Bunuel
At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.
Show more

CONCEPT: Distance travelled by Wheel in 1 revolution = Circumference of Wheel = 2 *(Pi)* Radius
and Total Distance covered by Wheel = No. of Revolutions made to cover that Distance * (2*(Pi)*r)

Statement 1: At the moment Sue and Nancy crossed paths, Sue had travelled 60 feet with the wheelbarrow.

Speeds of Sue / Speeds of Nancy = 2/3

Speeds of Sue / Speeds of Nancy = Distance of Sue / Distance of Nancy

i.e. Distance travelled by Nancy in same time = (3/2)*60 = 90 feet

i.e. Total Distance between X and Y = 60 + 90 = 150 Feet

But This doesn't provide us the information about how many revolutions does the wheel takes to cover total or any part of distance

Hence NOT SUFFICIENT


Statement 2: The total number of wheel revolutions during Sue's trip from X to Y was 75

But This doesn't provide us the information about Total distance travelled by the wheel in 75 Revolutions

Hence NOT SUFFICIENT

Combining the two statements

Total Distance = 150 feet (Calculated from statement 1)
Total Revolutions made by wheel to cover total distance = 75

i.e. 150 = 75 * (2*pi*r)

i.e. Radius of wheel, r = 1/(pi)

SUFFICIENT

Answer: Option
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C
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 08 Jun 2015, 04:03
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Bunuel
At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.
Show more

MANHATTAN GMAT OFFICIAL SOLUTION:

For the wheelbarrow, we can set up a distance formula:
Distance Traveled = (Wheel Circumference) (Number of Wheel Revolution)
Distance Traveled = (2πr) (Number of Wheel Revolutions)

\(\frac{Distance \ Traveled}{(2\pi)(Number \ of \ Wheel \ Revolutions)}=r\)

We can rephrase the question from “What is r?” to “What is the distance traveled and the number of wheel revolutions?”

(1) INSUFFICIENT: This provides the distance traveled, but no information about the number of wheel revolutions.

(2) INSUFFICIENT: This gives the number of wheel revolutions, but no information about the total distance from X to Y.

(1) AND (2) SUFFICIENT: If Sue traveled 60 feet at a rate of 2 feet per second, she traveled for 60/2 = 30 seconds before meeting Nancy. During those 30 seconds, Nancy had traveled at a rate of 3 feet per second, for a distance of (3)(30) = 90 feet. The total distance between X and Y is 60 + 90 = 150 feet.

We also know the total number of wheel revolutions that occurred between X and Y, so we have the answer to the rephrased question.

The correct answer is C.
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 05 Jun 2015, 23:12
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Q: At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

we need the total # of revolutions and total distance covered by wheelbarrow.
Sue | 2 feet per sec |
Nancy | 3 feet per sec |

Stmt (1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
    Sue time to cover 60 feet = distance/speed = 60 feet/2 = 30 sec
    Nancy took same time to cover = 30 sec * 3 = 90 feet
    total Dist = 90 + 60 = 150 feet.
    but no info about # of revolutions by wheelbarrow. ----- not sufficient

Stmt (2) The total number of wheel revolutions during Sue's trip from X to Y was 75.
    info about # of revolutions by wheelbarrow.
    but no info about total distance. ----- not sufficient

Together Stmt (1) and Stmt (2)
    total Dist = 150 feet.
    # of revolutions by wheelbarrow = 75
    \(2 \pi r = 150/75.\) ----- sufficient

Answer: Option
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 08 Jun 2015, 04:31
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.

MANHATTAN GMAT OFFICIAL SOLUTION:

For the wheelbarrow, we can set up a distance formula:
Distance Traveled = (Wheel Circumference) (Number of Wheel Revolution)
Distance Traveled = (2πr) (Number of Wheel Revolutions)

\(\frac{Distance \ Traveled}{(2\pi{r})(Number \ of \ Wheel \ Revolutions)}=r\)

We can rephrase the question from “What is r?” to “What is the distance traveled and the number of wheel revolutions?”

(1) INSUFFICIENT: This provides the distance traveled, but no information about the number of wheel revolutions.

(2) INSUFFICIENT: This gives the number of wheel revolutions, but no information about the total distance from X to Y.

(1) AND (2) SUFFICIENT: If Sue traveled 60 feet at a rate of 2 feet per second, she traveled for 60/2 = 30 seconds before meeting Nancy. During those 30 seconds, Nancy had traveled at a rate of 3 feet per second, for a distance of (3)(30) = 90 feet. The total distance between X and Y is 60 + 90 = 150 feet.

We also know the total number of wheel revolutions that occurred between X and Y, so we have the answer to the rephrased question.

The correct answer is C.
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 21 Jul 2016, 18:26
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Bunuel
At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.
Show more

Circumference * Rev = Total distance covered.

Distance covered by Sue = 60 feet, Time taken = 60/2 = 30 secs.
Distance covered by Nancy in same time = 30 * 3 = 90 feet.

Total D = 60 + 90 = 150 feet.

2 * pi * r * 75 = 150

using I and II, we can get the value of the wheelbarrow radius, hence C
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 19 Apr 2021, 01:16
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Bunuel
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.

MANHATTAN GMAT OFFICIAL SOLUTION:

For the wheelbarrow, we can set up a distance formula:
Distance Traveled = (Wheel Circumference) (Number of Wheel Revolution)
Distance Traveled = (2πr) (Number of Wheel Revolutions)

\(\frac{Distance \ Traveled}{(2\pi{r})(Number \ of \ Wheel \ Revolutions)}=r\)

We can rephrase the question from “What is r?” to “What is the distance traveled and the number of wheel revolutions?”

(1) INSUFFICIENT: This provides the distance traveled, but no information about the number of wheel revolutions.

(2) INSUFFICIENT: This gives the number of wheel revolutions, but no information about the total distance from X to Y.

(1) AND (2) SUFFICIENT: If Sue traveled 60 feet at a rate of 2 feet per second, she traveled for 60/2 = 30 seconds before meeting Nancy. During those 30 seconds, Nancy had traveled at a rate of 3 feet per second, for a distance of (3)(30) = 90 feet. The total distance between X and Y is 60 + 90 = 150 feet.

We also know the total number of wheel revolutions that occurred between X and Y, so we have the answer to the rephrased question.

The correct answer is C.
Show more

Hello Bunuel, thank you for the explanation! Though, I have one question about the formula: should not it be without r? \(\frac{Distance \ Traveled}{(2\pi)(Number \ of \ Wheel \ Revolutions)}=r\)
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 19 Apr 2021, 03:27
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Bunuel
At the same time Sue began rolling a wheelbarrow from X to Y, Nancy started walking along the same road from Y to X. If Sue's traveling rate was 2 feet per second and Nancy's was 3 feet per second, and if the wheelbarrow wheel rolled without slipping, what is the radius of the wheel on Sue's wheelbarrow?

(1) At the moment Sue and Nancy crossed paths, Sue had traveled 60 feet with the wheelbarrow.
(2) The total number of wheel revolutions during Sue's trip from X to Y was 75.

MANHATTAN GMAT OFFICIAL SOLUTION:

For the wheelbarrow, we can set up a distance formula:
Distance Traveled = (Wheel Circumference) (Number of Wheel Revolution)
Distance Traveled = (2πr) (Number of Wheel Revolutions)

\(\frac{Distance \ Traveled}{(2\pi{r})(Number \ of \ Wheel \ Revolutions)}=r\)

We can rephrase the question from “What is r?” to “What is the distance traveled and the number of wheel revolutions?”

(1) INSUFFICIENT: This provides the distance traveled, but no information about the number of wheel revolutions.

(2) INSUFFICIENT: This gives the number of wheel revolutions, but no information about the total distance from X to Y.

(1) AND (2) SUFFICIENT: If Sue traveled 60 feet at a rate of 2 feet per second, she traveled for 60/2 = 30 seconds before meeting Nancy. During those 30 seconds, Nancy had traveled at a rate of 3 feet per second, for a distance of (3)(30) = 90 feet. The total distance between X and Y is 60 + 90 = 150 feet.

We also know the total number of wheel revolutions that occurred between X and Y, so we have the answer to the rephrased question.

The correct answer is C.

Hello Bunuel, thank you for the explanation! Though, I have one question about the formula: should not it be without r? \(\frac{Distance \ Traveled}{(2\pi)(Number \ of \ Wheel \ Revolutions)}=r\)
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You are right! Edited the typo. Thank you!
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 19 Apr 2021, 03:49
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To identify radius , we need total distance between X and Y and total number of revolutions that wheel made during the trip.
Option A) helps to identify distance between two points and Option B) provides total number of the wheel made during the distance. Hence both options are important. So Option C

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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 26 Jun 2022, 07:26
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Interesting question!

When a wheel rotates, the distance it covers in one rotation is 2*pi*r, which means total distance travelled in n rotations = n*2*pi*r

For DS questions, I'm experimenting with a WHO framework:

What is needed
How to get it
Options that will satisfy needs

What we need here is radius r. How to get it? If we go back to the equation, we need the total distance and number of rotations. Options A and C together satisfy this need.
Note that speeds in the question stem are pure distractions
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At the same time Sue began rolling a wheelbarrow from X to Y, Nancy 30 May 2024, 08:57
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