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Re M0936
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16 Sep 2014, 00:41



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Re: M0936
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02 Jul 2015, 08:10
Bunuel wrote: Official Solution:
If the area of square \(A\) is three times the area of square \(B\), what is the ratio of the diagonal of square \(B\) to that of square \(A\)?
A. \(\frac{1}{3^{(\frac{1}{2})}}\) B. \(\frac{1}{3^{(\frac{1}{3})}}\) C. \(3^{(\frac{1}{3})}\) D. \(3^{(\frac{1}{2})}\) E. 3
The ratio of the diagonals is the same as the ratio of the sides. If the side of \(B\) is \(b\), then the side of \(A\) must be \(\sqrt{3}b\). The required ratio is: \(\frac{b}{\sqrt{3}b} = \frac{1}{\sqrt{3}} = \frac{1}{3^{\frac{1}{2}}}.\)
Answer: A Hi, I answer correctly, but it would help me if you explain in a little more detail the conclusion in order to answer quickly: The ratio of the diagonals is the same as the ratio of the sides. If the side of B is b, then the side of A must be 3√b Thanks a lot. Regards, Luis Navarro Looking for 700



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Re: M0936
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02 Jul 2015, 08:37
luisnavarro wrote: Bunuel wrote: Official Solution:
If the area of square \(A\) is three times the area of square \(B\), what is the ratio of the diagonal of square \(B\) to that of square \(A\)?
A. \(\frac{1}{3^{(\frac{1}{2})}}\) B. \(\frac{1}{3^{(\frac{1}{3})}}\) C. \(3^{(\frac{1}{3})}\) D. \(3^{(\frac{1}{2})}\) E. 3
The ratio of the diagonals is the same as the ratio of the sides. If the side of \(B\) is \(b\), then the side of \(A\) must be \(\sqrt{3}b\). The required ratio is: \(\frac{b}{\sqrt{3}b} = \frac{1}{\sqrt{3}} = \frac{1}{3^{\frac{1}{2}}}.\)
Answer: A Hi, I answer correctly, but it would help me if you explain in a little more detail the conclusion in order to answer quickly: The ratio of the diagonals is the same as the ratio of the sides. If the side of B is b, then the side of A must be 3√b Thanks a lot. Regards, Luis Navarro Looking for 700 Check here: iftheareaofsquareaisthreetimestheareaofsquareb85808.htmlHope it helps.
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Re: M0936
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02 Jul 2015, 09:00
Bunuel wrote: luisnavarro wrote: Bunuel wrote: Official Solution:
If the area of square \(A\) is three times the area of square \(B\), what is the ratio of the diagonal of square \(B\) to that of square \(A\)?
A. \(\frac{1}{3^{(\frac{1}{2})}}\) B. \(\frac{1}{3^{(\frac{1}{3})}}\) C. \(3^{(\frac{1}{3})}\) D. \(3^{(\frac{1}{2})}\) E. 3
The ratio of the diagonals is the same as the ratio of the sides. If the side of \(B\) is \(b\), then the side of \(A\) must be \(\sqrt{3}b\). The required ratio is: \(\frac{b}{\sqrt{3}b} = \frac{1}{\sqrt{3}} = \frac{1}{3^{\frac{1}{2}}}.\)
Answer: A Hi, I answer correctly, but it would help me if you explain in a little more detail the conclusion in order to answer quickly: The ratio of the diagonals is the same as the ratio of the sides. If the side of B is b, then the side of A must be 3√b Thanks a lot. Regards, Luis Navarro Looking for 700 Check here: iftheareaofsquareaisthreetimestheareaofsquareb85808.htmlHope it helps. Thanks a lot¡¡



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Re: M0936
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28 Nov 2015, 11:09
Hi Bunuel
I think the correct choice is D.



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Re: M0936
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28 Nov 2015, 11:18



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Re: M0936
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28 Nov 2015, 20:49
Bunuel wrote: sigma wrote: Hi Bunuel
I think the correct choice is D. Care to elaborate? Oh, I had put in the link mentioned by you at the top but it didn't go through. The correct choice is root 3, even as per the link that you have given on the top you can see in your earlier post you have mentioned it as root 3.



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Re: M0936
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29 Nov 2015, 06:50



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Re: M0936
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10 Jan 2016, 10:38
Hi! I'm trying to solve using the diagonal, but my answer is not matching.... Area of A: 12 Area of B: 4 Diagonal of A: \(\sqrt{24}\) Diagonal of B: \(\sqrt{8}\) Ratio: \(\sqrt{24}\) / \(\sqrt{8}\) > \(\sqrt{2}\) / \(\sqrt{6}\) Could someone help? Bunuel wrote: luisnavarro wrote: Bunuel wrote: Official Solution:
If the area of square \(A\) is three times the area of square \(B\), what is the ratio of the diagonal of square \(B\) to that of square \(A\)?
A. \(\frac{1}{3^{(\frac{1}{2})}}\) B. \(\frac{1}{3^{(\frac{1}{3})}}\) C. \(3^{(\frac{1}{3})}\) D. \(3^{(\frac{1}{2})}\) E. 3
The ratio of the diagonals is the same as the ratio of the sides. If the side of \(B\) is \(b\), then the side of \(A\) must be \(\sqrt{3}b\). The required ratio is: \(\frac{b}{\sqrt{3}b} = \frac{1}{\sqrt{3}} = \frac{1}{3^{\frac{1}{2}}}.\)
Answer: A Hi, I answer correctly, but it would help me if you explain in a little more detail the conclusion in order to answer quickly: The ratio of the diagonals is the same as the ratio of the sides. If the side of B is b, then the side of A must be 3√b Thanks a lot. Regards, Luis Navarro Looking for 700 Check here: iftheareaofsquareaisthreetimestheareaofsquareb85808.htmlHope it helps.



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Joined: 21 Oct 2015
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Though it is often advised not to rely too much on math formula on GMAT but this problem is best suited if you remember below :
Area of Square = (Diagonal^2)/2 > Square of diagonal divided by 2.
Let's apply the same formula here  (A^2)/2 = (3)(B^2)/2 >Where A is the diagonal of SquareA and B is the diagonal of SquareB. Simplifying the formula, B/A = 1/Sqrt(3). Ans A.
It is little easy in this case as we have a direct formula which links Area of a square to its diagonal. Hope it makes sense.



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Re M0936
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17 Aug 2018, 10:18
I think this is a highquality question and I agree with explanation.










