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Difficulty:
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Question Stats:
70% (01:35) correct
30%
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If the area of square A is three times the area of square B, what is the ratio of the diagonal of square A to that of square B?
A. \(\frac{1}{\sqrt{3}}\)
B. \(\frac{1}{\sqrt[3]{3}}\)
C. \(\sqrt[3]{3}\)
D. \(\sqrt{3}\)
E. 3
A. \(\frac{1}{\sqrt{3}}\)
B. \(\frac{1}{\sqrt[3]{3}}\)
C. \(\sqrt[3]{3}\)
D. \(\sqrt{3}\)
E. 3
25 Oct 2009, 23:32
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slingfox
If the area of square Q is three times the area of square P, what is the ratio of the diagonal of square Q to that of square?
A. 1/Sqrt(3)
B. 1/Third Root(3)
C. Third Root(3)
D. Sqrt(3)
E. 3
A. 1/Sqrt(3)
B. 1/Third Root(3)
C. Third Root(3)
D. Sqrt(3)
E. 3
Area of small square-P = s^2
Side of small square-P = s
Diagonal of a small square-P = s (sqrt2)
Area of large square-Q = 3s^2
Side of large square-Q = s {sqrt(3)}
Diagonal of a large square-Q = s (sqrt6)
Diagonal of a large square-Q / Diagonal of a small square-P = s (sqrt6) / s (sqrt2) = sqrt3
26 Oct 2009, 06:07
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Area Q = 3a^2
Area P = 3b^2.
3a^2 = 3b^2.
a = sqrt(3)*b.
diagonal of Q = sqrt(2) * a
diagonal of P = sqrt(2) * b.
Ratio of Q/P = a/b = sqrt(3) * b/b = sqrt(3).
I will go with option D
Area P = 3b^2.
3a^2 = 3b^2.
a = sqrt(3)*b.
diagonal of Q = sqrt(2) * a
diagonal of P = sqrt(2) * b.
Ratio of Q/P = a/b = sqrt(3) * b/b = sqrt(3).
I will go with option D
